C语言如何将一个字符串按照规定长度分解为几个字符串 c语言如何使一行字符串，按空格分开形成多个字符串，然后再记录...
\u5982\u4f55\u5c06\u4e00\u4e2a\u5b57\u7b26\u4e32\u5206\u5272\u6210\u51e0\u4e2a\u5b57\u7b26\u957f\u5ea6\u76f8\u540c\u7684\u5b57\u7b26\u4e32\u7528substring().
\u6bd4\u5982String str="abcdefgh";
String s1 = str.substring(0,4);
String s2 = str.substring(4,8);
System.out.println(s1);
System.out.println(s2);
\u8f93\u51fa\u7ed3\u679c\uff1aabcd
efgh
#include #include #define MAX 32int find_longest(char *buff){ int total_len = 0, str_len = 0, longest_len = -1; char longest[128] = {0}; char *p = buff; while(1) { if (' ' == *p || '\0' == *p) { if (str_len > longest_len) { strncpy(longest, p-str_len, str_len); longest_len = str_len; } total_len += str_len; str_len = 0; if ('\0' == *p) { break; } } else { str_len++; } p++; } strcpy(buff, longest); return total_len;}int main(int argc, char *argv[]){ int i = 0, cnt = 0, total_len = 0; char buff[MAX][128] = {{0}}; for (i = 0; i < MAX; i++) { if (NULL == fgets(buff[i], 128, stdin)) { printf("\u9519\u8bef\n"); return -1; } else { buff[i][strlen(buff[i])-1] = '\0'; if (0 == strcmp("stop", buff[i])) { cnt = i; break; } } } for (i = 0; i < cnt; i++) { total_len = find_longest(buff[i]); printf("%d %s\n", total_len, buff[i]); } return 0;}
按题意，字符串之间没有空格，那么用指针循环每次跳一个分组长度来取每个分组，同时判断是0开头还是1开头，决定数组正取还是反取。
#include<stdio.h>
#include<string.h>
#include<malloc.h>
#define size 9//每组字符串长度
int main()
{
char str[100]="041FF820010028FF24083FF8200",**adds=NULL,*p=str,*p1=NULL;
int i,j,len=strlen(str),n,m;
n=len/size;
printf("字符串：%s
",str);
adds=(char **)malloc(sizeof(char *)*n);
if(!adds)
return 1;
for(i=0;i<n;i++)
{
adds[i]=(char *)malloc(sizeof(char)*size);
if(!adds[i])
return 1;
memset(adds[i],0,sizeof(char)*size);
if(*p=='0')//首字母0，反向取
{
p1=p+(size-1);
m=size-1;
j=0;
while(m--)
{
adds[i][j++]=*p1;
p1--;
}
}
if(*p=='1')//首字母1，正向取
{
p1=p+1;
m=size-1;
j=0;
while(m--)
{
adds[i][j++]=*p1;
p1++;
}
}
p+=size;
}
printf("每组地址为：
");
for(i=0;i<n;i++)
printf("%s
",adds[i]);
return 0;
}
C语言实现一个字符串的输入、解析、转置并输出（注：最后一组不足9个字符的情况不做解析），参考代码如下：
#include<stdio.h>
#include<string.h>
#define N 9
void reverse(char *str,int n)
{
char t;
int i;
for(i=0; i<n/2; ++i)
t=str[i],str[i]=str[n-i-1],str[n-i-1]=t;
}
int main()
{
char str[300];
char buf[N+1];
char substr[N];
char ch,*p=str;
int i;
gets(str);
while(1) {
for(i=0; i<N; ++i) {
if(p[i]=='\0') break;
buf[i]=p[i];
}
if(i!=N) break;
p+=N;
buf[N]='\0';
sscanf(buf,"%c%s",&ch,substr);
if(ch=='0')
reverse(substr,N-1);
printf("%s ",substr);
}
return 0;
}
绛旓細鎸夐鎰忥紝瀛楃涓蹭箣闂存病鏈夌┖鏍硷紝閭ｄ箞鐢ㄦ寚閽堝惊鐜瘡娆¤烦涓涓垎缁勯暱搴︽潵鍙栨瘡涓垎缁勶紝鍚屾椂鍒ゆ柇鏄0寮澶磋繕鏄1寮澶达紝鍐冲畾鏁扮粍姝ｅ彇杩樻槸鍙嶅彇銆俰nclude<stdio.h>#include<string.h>#include<malloc.h>#define size 9//姣忕粍瀛楃涓查暱搴nt main(){ char str[100]="041FF820010028FF24083FF8200",**adds=NULL,...
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绛旓細鍙互鍒╃敤瀛楃鎸囬拡缁撳悎while寰幆鐨勬柟寮忔潵缂栧啓瀛楃涓插鍒跺嚱鏁銆傚叿浣撳疄鐜版柟娉曞彲浠ュ弬鑰冨涓嬬▼搴忥細include<stdio.h>void str_copy(char *str1, char *str2) // 瀛楃涓插鍒跺嚱鏁皗 while(*str1++ = *str2++); // 灏嗗瓧绗︿覆str2涓殑姣忎釜瀛楃閫愪釜澶嶅埗鍒皊tr1涓紝鐩村埌閬囧埌瀛楃涓茬粨鏉熷瓧绗'\0'}void ma...
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