python怎么找出字符串中的数字 python中怎么查找字符串中的数字？遇到瓶颈求帮助
Python\u600e\u4e48\u7528\u6b63\u5219\u8868\u8fbe\u5f0f\u627e\u5230\u8fd9\u4e2a\u5b57\u7b26\u4e32\u91cc\u9762\u7684\u6570\u5b57\u6ce8\u610f\u7a7a\u5339\u914d\u4e5f\u662f\u5339\u914d\u3002*\u8868\u793a0\u6216\u591a\u5339\u914d\uff0c\u4e00\u5f00\u5934\u5c31\u6709\u7a7a\u5339\u914d\u6240\u4ee5search\u9a6c\u4e0a\u5b8c\u6210\uff0c\u5047\u4f7f\u6ca1\u627e\u5230\u7684\u8bddsearch\u4f1a\u8fd4\u56deNone\u7136\u540egroup()\u64cd\u4f5c\u662f\u4f1a\u62a5\u9519\u3002\u4f60\u53ef\u4ee5\u8bd5\u8bd5fianall()\u4f1a\u4ece\u5934\u627e\u5230\u5c3e\uff0c\u5728\u627e\u5230666\u4e4b\u524d\u6bcf\u4e2a\u4f4d\u7f6e\u90fd\u662f\u7a7a\u5339\u914d...\u5e94\u6539\u7528\d+\u88681\u6216\u591a
import re
temp = 'DwellTime: 666'
m = re.search(r'\d*', temp)
print repr(m.group()), m.start(), m.end()
m = re.search(r'\d+', temp)
print repr(m.group()), m.start(), m.end()
print re.findall(r'\d*', temp)
\u8f93\u51fa\uff1a
'' 0 0
'666' 11 14
['', '', '', '', '', '', '', '', '', '', '', '666', '']
\u5faa\u73af\u91cc\u505a\u7d2f\u52a0\u64cd\u4f5c\u554a
if line.startswith('X-DSPAM-Confidence:'): #\u6839\u636e:\u53f7\u6765\u5206\u5272line\uff0c\u53d6\u51fa\u8be5\u503c\uff0c\u7d2f\u52a0 total += float(line.split('\uff1a')[1]) count=count+1print countprint total/count
也可以把字符串中的每一位弄成ascii的对应数字范围，0~9对应的是一个范围，判断是否在范围就行。
要么就遍历，看看是不是int类型的
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