一吨火箭燃料N2H4能产生多少能量
N2H4\u662f\u4e00\u79cd\u9ad8\u6548\u6e05\u6d01\u7684\u706b\u7bad\u71c3\u6599\u30020.25\u6beb\u5347N2H4\u5b8c\u5168\u71c3\u70e7\u751f\u6210\u6c2e\u6c14\u548c\u6c14\u6001\u6c34\u65f6,\u653e\u51fa133.5KJ\u7684\u70ed\u91cf,\u8bf7\u5199\u51fa\u5b831mol \u6c14\u4f53\u4e3a22.4ML \u9996\u5148\u6c42\u51fa1mol\u6c14\u4f53\u53cd\u5e94\u6240\u91ca\u653e\u7684\u80fd\u91cf = 133.5x22.4/0.25 \uff08\u5047\u8bbe\u6c42\u89e3\u7ed3\u679c\u4e3aenergy\uff09N2H4+O2=N2+2H2O \u25b3H= \u2014energy
0.25mol N2H4\uff08g\uff09\u5b8c\u5168\u71c3\u70e7\u751f\u6210\u6c2e\u6c14\u548c\u6db2\u6001\u6c34\u65f6\uff0c\u653e\u51fa150.0kJ\u70ed\u91cf\uff0c\u52191mol N2H4\uff08g\uff09\u5b8c\u5168\u71c3\u70e7\u751f\u6210\u6c2e\u6c14\u548c\u6db2\u6001\u6c34\u65f6\uff0c\u653e\u51fa150.0kJ\u00d74=600kJ\u7684\u70ed\u91cf\uff0c\u70ed\u5316\u5b66\u65b9\u7a0b\u5f0f\u4e3a\uff1aN2H4\uff08g\uff09+O2\uff08g\uff09=N2\uff08g\uff09+2H2O\uff08l\uff09\u25b3H=-600kJ?mol-1\uff1b\u6545\u7b54\u6848\u4e3a\uff1aN2H4\uff08g\uff09+O2\uff08g\uff09=N2\uff08g\uff09+2H2O\uff08l\uff09\u25b3H=-600kJ?mol-1\uff1b
1、N2H4常用作航天燃料，也称联氨或无水肼，可做火箭推进剂或燃料电池。2、它的低位发热量（热值）为19412.500KJ/kg（千焦/公斤），完全燃烧释放的能量：
N2H4+O2=N2+2H2O；释放热量△H=624KJ/mol（约合19412.500KJ/kg）
3、1吨联氨做火箭燃料完全燃烧释放的能量：
19412500KJ（千焦）=4622023千卡
绛旓細N2H4+O2=N2+2H2O锛涢噴鏀剧儹閲忊柍H=624KJ/mol锛堢害鍚19412.500KJ/kg锛3銆1鍚ㄨ仈姘ㄥ仛鐏鐕冩枡瀹屽叏鐕冪儳閲婃斁鐨勮兘閲忥細19412500KJ锛堝崈鐒︼級=4622023鍗冨崱
绛旓細鏇存柊2: 绛旀鏄2.3.5 绛旀鏄細 2銆3 鍜 5 1. 閿欒 2N2H4 + N2O4 鈫 3N2 + 4H2O 64 鍏 N2H4 鐨鑾虫暟 = 64 / (14x2 + 1x4) = 2mol 46 鍏 N2O4 鐨勮帿鑰虫暟 = 46 / (14x2 + 16x4) = 0.5mol 鑻 N2O4 瀹屽叏鍙嶅簲锛岄渶 N2H4鐨鑾虫暟 = 0.5 x 2 = 1 mol 鍥犳锛孨2H4...
绛旓細0.25mol N2H4锛坓锛夊畬鍏ㄧ噧鐑鐢熸垚姘皵鍜屾恫鎬佹按鏃讹紝鏀惧嚭150.0kJ鐑噺锛屽垯1mol N2H4锛坓锛夊畬鍏ㄧ噧鐑х敓鎴愭爱姘斿拰娑叉佹按鏃讹紝鏀惧嚭150.0kJ脳4=600kJ鐨勭儹閲忥紝鐑寲瀛︽柟绋嬪紡涓猴細N2H4锛坓锛+O2锛坓锛=N2锛坓锛+2H2O锛坙锛夆柍H=-600kJ?mol-1锛涙晠绛旀涓猴細N2H4锛坓锛+O2锛坓锛=N2锛坓锛+2H2O锛坙锛夆柍H=-600kJ...
绛旓細鈻砪 H = 2鈻 f (H2O,l) + 1/3 鈻砯 (N2) - 鈻砯( N2H4) - 1/2 鈻砯 (N2O4)= 2鈻 f (H2O,l) + 0 - 鈻砯( N2H4) - 1/2 鈻砯 (N2O4)鏌ュ嚭N2H4锛孨2O4锛 鍜孒2O 鐢熸垚鐑暟鎹嵆鍙眰寰椼
绛旓細锛1锛32gN2H4鐨鐗╄川鐨勯噺=32g32g/mol=1mol锛1molN2H4鍦板湪姘ф皵涓畬鍏ㄧ噧鐑鐢熸垚姘皵锛屾斁鍑虹儹閲624kJ锛屽叾鍖栧鍙嶅簲鏂圭▼寮忎负锛歂2H4锛坓锛+O2锛坓锛=N2锛坓锛+2H2O锛坙锛夆柍H=-624KJ/mol锛屾晠绛旀涓猴細N2H4锛坓锛+O2锛坓锛=N2锛坓锛+2H2O锛坙锛夆柍H=-624KJ/mol锛涳紙2锛夎偧--绌烘皵纰辨鐕冩枡鐢垫睜涓紝璐熸瀬涓婄噧鏂...
绛旓細10000KJ/Kg浠ヤ笂銆傛牴鎹960鍖栧伐缃戞煡璇㈠緱鐭ワ紝鐏鐕冩枡鐢ㄧ儹鍊艰姹傚湪10000KJ/Kg浠ヤ笂銆傝埅澶╀紒涓氱獊鐮翠娇鐢ㄧ敳閱囦綔涓虹伀绠彂鍔ㄦ満鐕冩枡锛岀儹鍊间负55MJ/Kg锛屾瘮鐓ゆ补鐨勭儹鍊奸珮銆傝仈姘ㄦ槸甯哥敤浣滆埅澶╃噧鏂欙紝浣庝綅鐑间负19412.500KJ/Kg锛屽畬鍏ㄧ噧鐑ч噴鏀剧殑鑳介噺涓N2H4+O2=N2+2H2O銆
绛旓細2N2H4 + 2NO2 == 3N2 + 4H2O
绛旓細宸茬煡3.2g娑叉佽偧涓庤冻閲忔哀姘斿弽搴旓紝鐢熸垚姘皵鍜屾按钂告皵锛屾斁鍑62.2KJ鐨勭儹閲忥紝鍒1mol娑叉佽偧瀹屽叏鍙嶅簲鐢熸垚姘皵鍜屾按钂告皵鏀惧嚭鐨勭儹閲忎负锛62.2kJ脳323.2=622kJ锛岃鍙嶅簲鐨勭儹鍖栧鏂圭▼寮忎负锛N2H4锛1锛+O2锛坓锛=N2锛坓锛+2H2O锛坓锛夆柍H=-622kJ/mol锛屾晠绛旀涓猴細N2H4锛1锛+O2锛坓锛=N2锛坓锛+2H2O锛坓锛夆柍H...
绛旓細锛2锛夆憼N2H4锛坙锛+2H2O2锛坙锛夆晲N2锛坓锛+4H2O锛坓锛夆柍H=-641.75kJ/mol锛涒憽H2O锛坙锛=H2O锛坓锛夆柍H=+44kJ/mol锛涗緷鎹洊鏂畾寰嬧憼-鈶∶4寰楀埌N2H4锛坙锛+2H2O2锛坙锛夆晲N2锛坓锛+4H2O锛坙锛夆柍H=-817.75kJ/mol锛岃16g娑叉佽偧鐗╄川鐨勯噺涓0.5mol锛屼笌娑叉佸弻姘ф按鍙嶅簲鐢熸垚娑叉佹按鏃舵斁鍑虹殑鐑噺=0....
绛旓細锛1锛1.6g鍗0.05mol鐨 N2H4锛坙锛夊湪涓婅堪鍙嶅簲涓斁鍑64.22kJ鐨勭儹閲忥紝鍒1mol鏀惧嚭鐨勭儹閲忎负1mol0.05mol脳64.22kJ=1284.4kJ锛屾墍浠ョ儹鍖栧鏂圭▼寮忎负锛歂2H4锛坙锛+2H2O2锛坙锛=N2锛坓锛+4H2O 锛坓锛夆柍H=-1284.4kJ/mol锛屾晠绛旀涓猴細N2H4锛坙锛+2H2O2锛坙锛=N2锛坓锛+4H2O 锛坓锛夆柍H=-1284.4kJ...
