已知;抛物线y=x^2-2x+1的顶点坐标为A,抛物线y=-x^2+1的顶点坐标为B?
A(1,0),B(0,1)△AOB是等腰直角三角形,∠0是直角
p(-1,0),或为(-1,4),10,已知;抛物线y=x^2-2x+1的顶点坐标为A,抛物线y=-x^2+1的顶点坐标为B
(1)求A,B的坐标
(2)判断三角形AOB的形状
(3)抛物线y=x^2+2x+1的对称轴上有一点P,使得S△ABP=2S△AOB,求P点坐标
绛旓細4/3=鈭(0,a)[0-(x²-2x)]dx=-a³/3+a² 鐨勬柟绋 a³-3a²+4=0 瑙h繖涓柟绋嬶細伪=1 b=-3 c=0 d=4 A=b^2锛3ac=9 B=bc锛9伪d=-36 C=c^2锛3bd=36 螖=B^2锛4AC=0 鏍规嵁鐩涢噾鍏紡 a1=锛峛/伪锛婯=-7锛涳紙K=B/A锛夛紙涓嶅拰棰...
绛旓細1. 鐩稿垏 鑱旂珛鏂圭▼ y=x^2-2x y=x+b x^2-3x-b=0 鏈夊敮涓瑙 鎵浠9+4b=0 b=-9/4 2. C2 y=x^2+2x 褰撶洿绾垮拰C2鐩稿垏鏃 x^2+x-b=0 1+4b=0 b=-1/4 鎵浠 鏈変袱涓氦鐐圭殑b鐨勮寖鍥 -9/4<b<-1/4
绛旓細浠e叆鍒颁笂闈㈠紡瀛,鏈 (m-1)^2=(1/4)*(4-4m)鍖栨垚涓鍏冧簩娆℃柟绋,鏈 锛坢-1)^2 + (m-1)=0 m*(m-1)=0 m=0鎴栬卪=1 鍙堝洜涓烘湁涓や釜浜ょ偣,鎵浠x^2-2x+m=0鐨勬牴鐨勫垽鍒紡瑕佸ぇ浜0 b^2-4ac=4-4m>0 m,10,
绛旓細y=x^2-2x=锛坸-1)^2-1 ,锛坸-1)^2=y+1 鐢眡^2=y鍙崇Щ涓涓崟浣,鍐嶄笅绉讳竴涓崟浣嶅緱鍒,鎵浠ョ劍鐐瑰潗鏍囨湁锛0,1/4)浣滅浉鍚屽钩绉诲緱鍒,鏄紙1,-3/4)
绛旓細绛旓細y=x^2-2x=(x-1)^2-1 鎶涚墿绾寮鍙e悜涓婏紝瀵圭О杞磝=1 椤剁偣锛1锛-1锛夊煎煙涓篬-1,3]鎵浠ワ細-1<=(x-1)^2-1<=3 鎵浠ワ細2<=(x-1)^2<=4 鎵浠ワ細-2<=x-1<=-鈭2鎴栬呪垰2<=x-1<=2 鎵浠ワ細-1<=x<=1-鈭2鎴栬1+鈭2<=x<=3 鍥惧儚瑙佷笅鍥剧矖缁嗘锛
绛旓細y'=2x-2 浠=2,寰梱'=2脳2-2=2,鍒囩嚎鏂滅巼涓2,娉曠嚎涓庡垏绾垮瀭鐩,鏂滅巼浜掍负璐熷掓暟,娉曠嚎鏂滅巼=-1/2 鍒囩嚎鏂圭▼锛歽-2=2(x-2),鏁寸悊,寰y=2x-2 娉曠嚎鏂圭▼锛歽-2=(-1/2)(x-2),鏁寸悊,寰梱=-x/2 +3
绛旓細瑙o紙1锛夊洜涓鎶涚墿绾縴=x^2-2x+c鐨勯《鐐瑰潗鏍囧湪绗4璞¢檺 鎵浠(4ac-b^2)/4a=(4*1*c-2^2)/(4*1)=c-1<0 寰楋細c<1 (2)鍥犱负鎶涚墿绾跨粡杩囩偣锛0锛-1锛夋墍浠ワ細-1=0^2+2*0+c 鍖栬В寰楋細c=-1 浠ゆ姏鐗╃嚎鍦ㄧ鍥涜薄闄愯鎴偣鐨勭殑鍧愭爣涓猴紙x0,y0锛夛紝鐢卞浘绀哄彲鐭 4ac-b^2<y0< c锛寈0>-b/2a ...
绛旓細绛旓細鎶涚墿绾縴=x²-2x-3=(x-1)²-4 瀵圭О杞磝=1锛岄《鐐逛负锛1锛-4锛夎骞崇Щ鍚庣殑鎶涚墿绾夸负y=(x+a)²-4 缁忚繃鍘熺偣锛0,0锛夛紝浠e叆寰楋細a²-4=0 鎵浠ワ細a=-2鎴栬卆=2 鍥犱负鏄悜鍙冲钩绉伙紝鎵浠ワ細a=-2 鎵浠ワ細鍚戝彸骞崇Щ浜2-1=1涓崟浣 鎵浠ワ細骞崇Щ鍚庣殑鎶涚墿绾夸负y=(x-2)²...
绛旓細鈭垫槸骞崇Щ鎶涚墿绾 鈭碼鐩稿悓 璁炬柊鎶涚墿绾夸负y=x²+bx+c 鈭碿=2 杩嘇鐐 1+b+c=0 杩嘊鐐 鈭碽=-3 c=2 鈭磞=x²-3x+2
绛旓細锛1锛夌敤鏍圭殑鍒ゅ埆寮忔潵瑙 b²-4ac=锛-2锛²-4脳1脳锛-8锛=36锛0 鈭磋鎶涚墿绾涓巟杞翠竴瀹氭湁涓や釜浜ょ偣 锛2锛夌畻鍑哄綋y=o鏃秞鐨勫 瑙e緱x1=4 x2=-2 鍒檃b闀垮害涓4-锛-2锛=6 鍐嶇畻鍑哄畠鐨勯《鐐瑰潗鏍囷紙1锛-9锛夋墍浠ラ《鐐筆鍒皒杞寸殑璺濈涓9 涓夎褰㈢殑闈㈢Н涓6脳9梅2=27 ...