一些关于实数的数学问题，请高手指教! 求解关于实数的数学问题。
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\u7136\u540e\u628a\u5b83\u5206\u5f00
5\u221a11=4\u221a11+\u221a11=3\u221a11+2\u221a=2\u221a11+3\u221a11=\u221a11+4\u221a11
\u90a3\u4e48\u8fd9\u51e0\u79cd\u60c5\u51b5\u5c31\u90fd\u6709\u53ef\u80fd
2\uff1ab\u662f\u221a3+5\u7684\u5c0f\u6570\u90e8\u5206\uff0c\u4e5f\u5c31\u662f\u221a3\u7684\u5c0f\u6570\u90e8\u5206\uff0c\u8868\u793a\u4e3a\u221a3-1\uff0c\u6574\u6570\u90e8\u5206\u5c31\u662f6\uff0c\u90a3\u4e48a-b=6-\uff08\u221a3-1\uff09=7-\u221a3
3\uff1a.|1-\u6839\u53f72|+|\u6839\u53f72-\u6839\u53f73|+|\u6839\u53f73-\u6839\u53f74|+|\u6839\u53f74+\u6839\u53f75|+\u2026\u2026+|\u6839\u53f72009-\u6839\u53f72010|
\u53bb\u6389\u7edd\u5bf9\u503c
\u53d1\u73b0\u4e00\u4e2a\u89c4\u5f8b
\u4e2d\u95f4\u9879\u90fd\u80fd\u62b5\u6d88\uff0c\u90a3\u4e48\u7ed3\u679c\u5c31\u662f
\u221a2010-1
\u6b63\u786e\u7684\u8bf4\u6cd5\u67092\u4e2a\uff1a
1\uff0c5\u5bf9
\u53cd\u4f8b\u5982\u4e0b
2\uff1a0*\u221a2=0\uff08\u6709\u7406\u6570\uff09 \u6240\u4ee5\u9519\u8bef
3\uff1a\u221a3+\uff08-\u221a3\uff09=0\uff08\u6709\u7406\u6570\uff09 \u6240\u4ee5\u9519\u8bef
4\uff1a\u221a4*\u221a4=4\uff08\u6709\u7406\u6570\uff09 \u6240\u4ee5\u9519\u8bef
6\uff1a\u221a5/\u221a5=1\uff08\u6709\u7406\u6570\uff09 \u6240\u4ee5\u9519\u8bef
\u5e0c\u671b\u91c7\u7eb3\uff01
\u5bf9\u4e86\uff0c\u521a\u521a\u770b\u5230\u697c\u4e0a\u56de\u7b54\uff0c\u4e2a\u4eba\u8ba4\u4e3a\u7b2c\u4e94\u9898\u5e94\u8be5\u662f\u6b63\u786e\u7684\uff0c2-\u221a2\u5e94\u8be5\u4e0d\u5c5e\u4e8e\u5b9e\u6570\u8303\u56f4\uff0c\u56e0\u6b64\u4e0d\u5c5e\u4e8e\u65e0\u7406\u6570\u3002
\u77e5\u8bc6\u9ed1\u6d1e\u56e2\u961f\u4e3a\u60a8\u89e3\u7b54\uff01
5√11=4√11+√11=3√11+2√=2√11+3√11=√11+4√11那么这几种情况就都有可能2：b是√3+5的小数部分，也就是√3的小数部分，表示为√3-1，整数部分就是6，那么a-b=6-（√3-1）=7-√33：.|1-根号2|+|根号2-根号3|+|根号3-根号4|+|根号4+根号5|+……+|根号2009-根号2010|
去掉绝对值
发现一个规律
中间项都能抵消，那么结果就是
√2010-1
绛旓細24. 璁鹃搧涓濈殑闀垮害涓篴鍒 (a/4)^2=25 a=20 锌r^2=25 r^2=25/3 r=5/鈭3 鍦嗙殑鍛ㄩ暱鏄 10*鈭3=17.3 鍓╀綑20-17.3=2.7cm 25 AC= 24. 璁鹃搧涓濈殑闀垮害涓篴鍒 (a/4)^2=25 a=20 锌r^2=25 r^2=25/3 r=5/鈭3 鍦嗙殑鍛ㄩ暱鏄 10*鈭3=17.3 鍓╀綑20...
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绛旓細1.鈭祒銆亂鏄鏁癮鐨勪袱涓钩鏂规牴 鈭磝+y=0 鍙堚埖2x-y=2 鈭磞=2x-2 鈭磝+2x-2=0 鈭3x=2 鈭磝=3锛2 鈭碼=锛3/2锛²=9锛4 2.鈭(鏍瑰彿5)鐨勮В涓猴細2.236067...鎵浠ュ皬鏁伴儴鍒嗕负锛(鏍瑰彿5)-2=a 鍙堚埖5-(鏍瑰彿5)鐨勮В涓猴細2.7639320...鎵浠ュ皬鏁伴儴鍒嗕负5-锛堟牴鍙5锛-2 =3-锛堟牴鍙5...
绛旓細1:棣栧厛鍖栫畝鈭275=5鈭11鐒跺悗鎶婂畠鍒嗗紑 5鈭11=4鈭11+鈭11=3鈭11+2鈭=2鈭11+3鈭11=鈭11+4鈭11閭ｄ箞杩欏嚑绉嶆儏鍐靛氨閮芥湁鍙兘2锛歜鏄垰3+5鐨勫皬鏁伴儴鍒嗭紝涔熷氨鏄垰3鐨勫皬鏁伴儴鍒嗭紝琛ㄧず涓衡垰3-1锛屾暣鏁伴儴鍒嗗氨鏄6锛岄偅涔坅-b=6-锛堚垰3-1锛=7-鈭33锛.|1-鏍瑰彿2|+|鏍瑰彿2-鏍瑰彿3|+|鏍瑰彿3-鏍瑰彿4|+|...
绛旓細=5[y-(3-鈭5)/2][y-(3+鈭5)/2](鍦瀹炴暟鑼冨洿鍐呭垎瑙)8.x(m-x)(m-y)-m(x-m)(y-m)=(m-x)(m-y)(x-m)=-(m-x)²(m-y)9.-27m²n+9mn²-18mn=9mn(-3m+n-2)10.(3x+1)²=9x²+1+6x,鎵浠ュ崟椤瑰紡鍙互鏄6x 11.a=b=c 12.(x+1/x)&...
绛旓細閭ｄ箞鍓峮缁勫叡鍚1+3+5+...+(2n-1)=n²涓暟锛岃2013鍦ㄧm+1缁勫唴锛岄偅涔堝墠m缁勫叡鍚玬²涓暟锛屽叾涓m缁勬渶鍚庣殑涓涓暟涓哄ぇ鏁板垪鐨勭m²涓紝涓2m²-1,閭ｄ箞2m²-1<2013,2m²<2014 m²<1012 鈭 32²,=1024锛 31²=961 婊¤冻鏉′欢鏈澶х殑m=3...
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绛旓細瑙ｏ細鎴戜滑璁綼<=b<=c 鍐嶈f(a,b,c)=1/(a+b)+1/(a+c)+1/(b+c)鍒檉(0,a+b,1/(a+b)=1/(a+b)+(a+b)+1/(a+b+1/(a+b))鍒檉(a,b,c)-f(0,a+b,1/(a+b)) =1/(a+c)+1/(b+c)-(a+b)-1/(a+b+1/(a+b))(1) 鍥犱负ab+bc+ca=1 鎵浠=(1-ab)/(...
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