如图是一块长方形ABCD的场地，长AB=a米，宽AD=b米，从A、B两处入口的小路宽都为1米，两小路汇合处路宽为2 （2004?济宁）如图是一块矩形ABCD的场地，长AB=10...
\u5982\u56fe\u662f\u4e00\u5757\u957f\u65b9\u5f62ABCD\u7684\u573a\u5730\uff0cAB=a\u7c73AD=b\u7c73AB\u4e24\u51fa\u5165\u53e3\u7684\u8def\u5bbd\u4e3a1m\u4e24\u5c0f\u8def\u6c47\u5408\u5904\u5bbd\u4e3a...\u628a\u5c0f\u8def\u79fb\u5230\u4e00\u8fb9\u53d1\u73b0\u5269\u4f59\u90e8\u5206\u4e3a\u77e9\u5f62
S=(a-2)(b-1)=ab-(a+2b)+2=48
\u7531\u56fe\u53ef\u77e5\uff1a\u77e9\u5f62ABCD\u4e2d\u53bb\u6389\u5c0f\u8def\u540e\uff0c\u8349\u576a\u6b63\u597d\u53ef\u4ee5\u62fc\u6210\u4e00\u4e2a\u65b0\u7684\u77e9\u5f62\uff0c\u4e14\u5b83\u7684\u957f\u4e3a\uff1a102-2=100\uff0c\u5bbd\u4e3a51-1=50\uff0e\u6240\u4ee5\u8349\u576a\u7684\u9762\u79ef\u5e94\u8be5\u662f\u957f\u00d7\u5bbd=100\u00d750=5000\uff0e\u6545\u9009C\uff0e
由图可知：矩形ABCD中去掉小路后，草坪正好可以拼成一个新的矩形，且它的长为：（a-2）米，宽为（b-1）米．所以草坪的面积应该是长×宽=（a-2）（b-1）=ab-a-2b+2（米2）．
故答案为（ab-a-2b+2）．
绛旓細涓婇潰涓や釜鍖哄潡鍒嗗埆寰涓棿绉诲姩1m锛屽啀鍚戜笅绉诲姩1m 鏋勬垚涓涓柊鐨勬棤绌洪殭鐨闀挎柟褰锛屽叏閮ㄤ负鑽夊潽 鏂伴暱鏂瑰舰闀夸负AB-2=100-2=98 m 瀹戒负AD-1=50-1=49 m 鈭磋崏鍧潰绉负98*49=(100-2)*(50-1)=2(50-1)^2 =4802 (m^2)
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绛旓細鈭3/3)X-(鈭3/3)X=(鈭3/3)X 鏄捐屾槗瑙侊細DEBF鏄钩琛屽洓杈瑰舰锛堝彲浠ラ氳繃璇佹槑鈻矨DE鈮屸柍CBF寰桞F=DE锛孌E鈭F)鈭碨鍥涜竟褰EBF=2S鈻矱DF=2脳1/2EF脳DE=EF脳DE S鐭╁舰ABCD=2S鈻矨DC=2脳1/2AC脳DE=AC脳DE 鈭碨鍥涜竟褰EBF鈭禨鐭╁舰ABCD=EF鈭禔C=(鈭3/3)X鈭垛垰3X=1鈭3 ...
绛旓細鍋囪AB=DC鏍瑰彿2,AD=BC=1,鏍规嵁娌熻偂瀹氱悊AC=鏍瑰彿3 AC:AB:AD=鏍瑰彿3:鏍瑰彿2:1 BF鈯C,鎵浠C:BF=鏍瑰彿3:鏍瑰彿2,BC:FC=鏍瑰彿3:1 AB:BF=鏍瑰彿2*BC:BF=鏍瑰彿3:1 AC:FC=鏍瑰彿3*BC:FC=鏍瑰彿3*鏍瑰彿3:1=3:1 鍚岀悊鍙瘉AC:AE=3:1 閭ｄ箞AE:EF:FC=1:1:1 闀挎柟褰BCD闈㈢Н=AB*BC 鑿卞舰BEDF闈㈢Н=...
绛旓細50 6 3 m锛庘埓S 鈻矨DE = 1 2 脳AE脳DE = 1250 2 3 m 2 锛庘埓S 鈻矨ED +S 鈻矪CF +S 鈻矨EB +S 鈻矰CF = 5000 2 3 m 2 锛庘埓S 鍥涜竟褰EBF =S 鐭╁舰ABCD - 5000 2 3 =2500 2 - 5000 2 3 = ...
