java中验证字符串是不是数字的四种方法

java\u4e2d\u5224\u65ad\u5b57\u7b26\u4e32\u662f\u5426\u6570\u5b57\u7684\u4e24\u79cd\u65b9\u6cd5

\u5224\u65ad\u5b57\u7b26\u4e32\u662f\u4e0d\u662f\u6570\u5b57\uff0c\u5927\u5bb6\u53ef\u80fd\u4f1a\u7528\u4e00\u4e9bjava\u81ea\u5e26\u7684\u65b9\u6cd5\uff0c\u4e5f\u6709\u53ef\u80fd\u7528\u5176\u4ed6\u602a\u5f02\u7684\u62db\u5f0f\uff0c\u6bd4\u5982\u5224\u65ad\u662f\u4e0d\u662f\u6574\u578b\u6570\u5b57\uff0c\u5c06\u5b57\u7b26\u4e32\u5f3a\u5236\u8f6c\u6362\u6210\u6574\u578b\uff0c\u4e0d\u662f\u6570\u5b57\u7684\u5c31\u4f1a\u629b\u51fa\u9519\u8bef\uff0c\u90a3\u4e48\u5c31\u4e0d\u662f\u6574\u578b\u7684\u4e86\u3002\u4f46\u672c\u6587\u4ecb\u7ecd\u7684\u6bd4\u8f83\u597d\u7684\u4e24\u79cd\u65b9\u6cd5\uff1a
1\u3002java\u7c7b\u5e93\u81ea\u5e26\u7684\u65b9\u6cd5\uff1a
public boolean isNum(String msg){
if(java.lang.Character.isDigit(msg.charAt(0))){
return true;}return false;}�0�2�0�2\u66f4\u65b0\uff1a\u53d1\u73b0\u4ee5\u4e0a\u65b9\u6cd5\u5199\u5f97\u4e0d\u591f\u5230\u4f4d\uff0c\u73b0\u5728\u5c31\u6539\u4e3a\u4e0b\u9762\u7684\u7b80\u5355\u8bf4\u660e\u4e86\uff0c\u81f3\u4e8e\u5177\u4f53\u7684\u65b9\u6cd5\u5b9e\u73b0\u5b57\u7b26\u4e32\u5224\u65ad\u662f\u5426\u6570\u5b57\u5c31\u4e0d\u5199\u4e86\u3002
java.lang.Character.isDigit(char ch) boolean
isDigit \u53ea\u80fd\u4f5c\u7528\u4e8echar\uff0c\u6240\u4ee5\u5224\u65ad\u5b57\u7b26\u4e32\u662f\u5426\u4e3a\u6570\u5b57\uff0c\u8981\u4e00\u4e2a\u4e00\u4e2a\u62ff\u51fachar\u8fdb\u884c\u5224\u65ad\u3002
2\u3002\u7528\u6b63\u5219\u8868\u8fbe\u5f0f
\u9996\u5148\u8981import java.util.regex.Pattern \u548c java.util.regex.Matcher
\u8fd9\u4e24\u4e2a\u5305\uff0c\u63a5\u4e0b\u6765\u662f\u4ee3\u7801
public boolean isNumeric(String str){Pattern pattern = Pattern.compile(\u201d[0-9]*\u201d);
Matcher isNum = pattern.matcher(str);
if( !isNum.matches() ){return false;}return true;}�0�2
3\u3002\u7528\u6b63\u5219\u8868\u8fbe\u5f0f

1.\u4f7f\u7528Character.isDigit(char)\u5224\u65ad
char num[] = str.toCharArray();//\u628a\u5b57\u7b26\u4e32\u8f6c\u6362\u4e3a\u5b57\u7b26\u6570\u7ec4
StringBuffer title = new StringBuffer();//\u4f7f\u7528StringBuffer\u7c7b\uff0c\u628a\u975e\u6570\u5b57\u653e\u5230title\u4e2d
StringBuffer hire = new StringBuffer();//\u628a\u6570\u5b57\u653e\u5230hire\u4e2d
for (int i = 0; i < num.length; i++) {
// \u5224\u65ad\u8f93\u5165\u7684\u6570\u5b57\u662f\u5426\u4e3a\u6570\u5b57\u8fd8\u662f\u5b57\u7b26
if (Character.isDigit(num[i])) {\u628a\u5b57\u7b26\u4e32\u8f6c\u6362\u4e3a\u5b57\u7b26\uff0c\u518d\u8c03\u7528Character.isDigit(char)\u65b9\u6cd5\u5224\u65ad\u662f\u5426\u662f\u6570\u5b57\uff0c\u662f\u8fd4\u56deTrue\uff0c\u5426\u5219False
hire.append(num[i]);// \u5982\u679c\u8f93\u5165\u7684\u662f\u6570\u5b57\uff0c\u628a\u5b83\u8d4b\u7ed9hire} else {title.append(num[i]);// \u5982\u679c\u8f93\u5165\u7684\u662f\u5b57\u7b26\uff0c\u628a\u5b83\u8d4b\u7ed9title}}}
2.\u4f7f\u7528\u7c7b\u578b\u8f6c\u6362\u5224\u65adtry {String str="123abc";
int num=Integer.valueOf(str);//\u628a\u5b57\u7b26\u4e32\u5f3a\u5236\u8f6c\u6362\u4e3a\u6570\u5b57
return true;//\u5982\u679c\u662f\u6570\u5b57\uff0c\u8fd4\u56deTrue
} catch (Exception e) {
return false;//\u5982\u679c\u629b\u51fa\u5f02\u5e38\uff0c\u8fd4\u56deFalse}
3.\u4f7f\u7528\u6b63\u5219\u8868\u8fbe\u5f0f\u5224\u65ad
String str = "";
boolean isNum = str.matches("[0-9]+");
//+\u8868\u793a1\u4e2a\u6216\u591a\u4e2a\uff08\u5982"3"\u6216"225"\uff09\uff0c*\u8868\u793a0\u4e2a\u6216\u591a\u4e2a\uff08[0-9]*\uff09\uff08\u5982""\u6216"1"\u6216"22"\uff09\uff0c?\u8868\u793a0\u4e2a\u62161\u4e2a([0-9]?)(\u5982""\u6216"7")
ps\uff1a\u8fd9\u4e2a\u65b9\u6cd5\u53ea\u80fd\u7528\u4e8e\u5224\u65ad\u662f\u5426\u662f\u6b63\u6574\u6570

判断字符串是不是数字,大家可能会用一些java自带的方法,也有可能用其他怪异的招式,比如判断是不是整型数字,将字符串强制转换成整型,不是数字的就会抛出错误,那么就不是整型的了。但本文介绍的比较好的两种方法:
1。java类库自带的方法:
public boolean isNum(String msg){
if(java.lang.Character.isDigit(msg.charAt(0))){
return true;}return false;}0202更新:发现以上方法写得不够到位,现在就改为下面的简单说明了,至于具体的方法实现字符串判断是否数字就不写了。
java.lang.Character.isDigit(char ch) boolean
isDigit 只能作用于char,所以判断字符串是否为数字,要一个一个拿出char进行判断。
2。用正则表达式
首先要import java.util.regex.Pattern 和 java.util.regex.Matcher
这两个包,接下来是代码
public boolean isNumeric(String str){Pattern pattern = Pattern.compile(”[0-9]*”);
Matcher isNum = pattern.matcher(str);
if( !isNum.matches() ){return false;}return true;}02
3。用正则表达式

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