x十y一1的绝对值十括号y+3反括号的平方等于0,则x减y的值为多少? 若x加3的绝对值加括号y减2括号的平方等于0,则x减2y等于...
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\u6240\u4ee5|x-y-1|+2(2x-y-3)²=0
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\u82e5\u6709\u4e00\u4e2a\u5927\u4e8e0\uff0c\u5219\u53e6\u4e00\u4e2a\u5c0f\u4e8e0\uff0c\u4e0d\u6210\u7acb\u3002
\u6240\u4ee5\u4e24\u4e2a\u90fd\u7b49\u4e8e0
\u6240\u4ee5x-y-1=0
2x-y-3=0
\u76f8\u51cf
x-2=0
x=2
y=x-1=1
X+Y-1=0
Y+3=0
y=-3
x=4
X-Y=7
7
绛旓細鍘熼搴斾负锛殀x+y+1|+(x-2y)^2=0 渚缁濆鍊鍜屽钩鏂规暟鎬ц川锛屽簲鏈墄+y+1=0 x-2y=0 瑙=-2/3 y=-1/3 鍒檟+2y=-2/3-2*1/3=-4/3 绛旈瀹屾瘯锛岃鎵硅瘎鎸囨銆
绛旓細缁濆鍊鍜屽钩鏂瑰煎潎澶т簬绛変簬0锛岃岀浉鍔犵粨鏋滀负0锛屽垯x-1=0,3x+y-1=0锛屽嵆x=1锛寉=-2,闂缁撴灉涓9
绛旓細瑙g敱ix涓1i鍗亅y鍗3.5|=0 鐭x-1=0涓攜+3.5=0 瑙e緱x=1锛寉=-3.5 鍗硏+y-1=-3.5
绛旓細瑙o細渚濋鎰忓緱锛歺-1=0 y-2=0 鈭磝=1 y=2 鏁呭師寮=2*(x^2+xy)-x^2 =2*3-1^2 =5 濡傛湁鐤戦棶锛屽彲杩介棶锛
绛旓細浜掍负鐩稿弽鏁板垯鐩稿姞涓0 鎵浠x-y-1|+2(2x-y-3)²=0 缁濆鍊鍜屽钩鏂瑰ぇ浜庣瓑浜0锛岀浉鍔犵瓑浜0 鑻ユ湁涓涓ぇ浜0锛屽垯鍙︿竴涓皬浜0锛屼笉鎴愮珛銆傛墍浠ヤ袱涓兘绛変簬0 鎵浠-y-1=0 2x-y-3=0 鐩稿噺 x-2=0 x=2 y=x-1=1
绛旓細鍥犱负x+y-3鎷彿鐨勫钩鏂逛笌x-y-1[缁濆鍊绗﹀彿]浜掍负鐩稿弽鏁 鎵浠 锛坸+y-3锛夊钩鏂+|x-y-1|=0 鍗 x+y-3=0,x-y-1=0 x+y=3 x-y=1 鎵浠 x=2,y=1.
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绛旓細瑙o細鐢卞凡鐭ユ湁 |x+y|+(y-3)²锛0锛屽張鍥犱负 |x+y|鈮0锛(y-3)²鈮0锛屾墍浠ュ繀鏈 x+y锛0 涓 y-3锛0锛岃В寰 x锛-3锛寉锛3锛屾墍浠 3y-4x+(-1)^2019锛9+12-1锛20 .