因式分解
\u56e0\u5f0f\u5206\u89e3\uff081\uff09x\u7684\u4e09\u6b21\u65b9+3x\u7684\u5e73\u65b9-4x-12
=x²(x+3)-4(x+3)
=(x²-4)(x+3)
=(x+2)(x-2)(x+3)
\uff082\uff09\u82e5\u591a\u9879\u5f0f5x\u7684\u5e73\u65b9+7x+a\u6709\u56e0\u5f0f(x+1).\u5219\u6b64\u591a\u9879\u5f0f\u53ef\u4ee5\u5206\u89e3\u4e3a(x+1)(5x+12)
\uff083\uff09a\u7684\u5e73\u65b9b\u7684\u5e73\u65b9-a\u7684\u5e73\u65b9-b\u7684\u5e73\u65b9+1
=a²(b²-1)-(b²-1)
=(a²-1)(b²-1)
=(a+1)(a-1)(b+1)(b-1)
\uff084\uff09(1-x\u7684\u5e73\u65b9\uff09\uff081-y\u7684\u5e73\u65b9\uff09-4xy=
=1-x²-y²+x²y²-4xy
=1-2xy+x²y²-x²-y²-2xy
=(1-xy)²-(x+y)²
=(1-xy+x+y)(1-xy-x-y)
\uff085\uff09\uff08a-1)(a-2b-1)+b\u7684\u5e73\u65b9=
=(a-1)²-2b(a-1)+b²
=(a-1-b)²
\uff086\uff09x\u7684\u5e73\u65b9-y\u7684\u5e73\u65b9-6x+9
=x²-6x+9-y²
=(x-3)²-y²
=(x-3+y)(x-3-y)
\uff087\uff094x\u7684\u5e73\u65b9+1/4-2x-9y\u7684\u5e73\u65b9=
=1/4(16x²+1-8x)-9y²
=1/4(4x-1)²-9y²
=(2x-1/2)²-(3y)²
=(2x-1/2+3y)(2x-1/2-3y)
=(x^2+y^2)^2+(x^2+y^2)^2
=2(x^2+y^2)^2
=2(x+y)^4
才学的因式分解，不知道对不对诶。。
需谅解！
希望是最佳回答````~~~~
x^4+y^4+(x+y)^4
=(x^2+y^2)^2-2x^2y^2+(x+y)^4
=[(x+y)^2-2xy]^2-2x^2y^2+(x+y)^4
=[(x+y)^2]^2-4xy(x+y)^2+4x^2y^2-2x^2y^2+(x+y)^4
=2(x+y)^4-4xy(x+y)^2+2x^2y^2
=2[(x+y)^4-2xy(x+y)^2+(xy)^2]
=2[(x+y)^2-xy]^2
=2(x^2+xy+y^2)^2.
原式
=（x`2+y`2）`2-2x`2y`2+（（x+y）`2）`2
令x`2+y`2=a，xy=b
原式
=a`2-2b`2+（a+2b）`2
=2a`2+2b`2+4ab
=2（a+b）`2
=2（x`2+y`2+xy）`2
x4 * y4 + (x+y)4 是这样的式子吗？
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