y=sin根号1＋x平方求导 y=sin根号下1+x平方，求函数的导数，希望过程详细谢谢！...
y=sin\u6839\u53f71+x\u5e73\u65b9 y=cos\u5e73\u65b9(x\u5e73\u65b9+1)\u6c42\u5bfc\u6570
\u795d\u5b66\u4e60\u8fdb\u6b65~~
\u590d\u5408\u51fd\u6570\u7684\u6c42\u5bfc\u3002
y'=cos(\u6839\u53f7(1+x^2)) *\uff08\u6839\u53f7(1+x^2))'
=cos(\u6839\u53f7(1+x^2)) *1/2 *2x*\u6839\u53f7(1+x^2)^(-1/2)
=xcos(\u6839\u53f7(1+x^2))/\u6839\u53f7(1+x^2)
绛旓細鍒╃敤鍜屾硶鍒 y=鏍瑰彿(1+x骞虫柟)+ln(sin x)+e鐨刟娆℃柟 y'=[鏍瑰彿(1+x骞虫柟)]'+[ln(sin x)]'+(e鐨刟娆℃柟)'绗竴绗簩涓兘鏄摼寮 =(1/2)(1+x^2)^(-1/2)*2x+(1/sinx)*cosx+0 =x/鏍瑰彿(1+x^2)+cotx
绛旓細鍥犱负y锛鈭1+sinx 鎵浠ワ細y'=(1+sinx)'/2鈭1+sinx =cosx/(2鈭1+sinx)
绛旓細3cos(3x+2)+鏍瑰彿锛1+x^2锛+x^2*锛1+x^2)^(-1/2)璇︾粏杩囩▼瑙佹垜鎷嶇殑鐓х墖锛岀偣寮鍥剧墖鍗冲彲
绛旓細婊℃剰璇烽噰绾筹紝璋㈣阿
绛旓細绛旀鏄繖涓,鑻ユ兂鐭ラ亾璇︾粏杩囩▼鍙互杩介棶.
绛旓細濡傛灉鏍瑰彿涓嬮潰鏄垎瀛愪笌鍒嗘瘝鐨勮瘽锛瀵兼暟鏄2Xcos(X鐨骞虫柟鍔犱竴)锛(2x鐨勫钩鏂逛箻(鏍瑰彿涓媂鍒嗕箣1鍑廥)鍒嗕箣涓锛涘鏋滄牴鍙峰彧鏄垎姣嶇殑璇濓細2Xcos锛坸^2鍔犱竴锛夊噺x鍒嗕箣(鏍瑰彿涓媥鍔2鏍瑰彿涓媥鍒嗕箣涓鍑弜)
绛旓細姹傚灏变娇鐢ㄩ摼寮忔硶鍒 y=鈭sin(x^2)閭ｄ箞姹傚寰楀埌 y'=1/ 2鈭歴in(x^2) * [sin(x^2)]'=1/ 2鈭歴in(x^2) * cos(x^2) *(x^2)'=2x / 2鈭歴in(x^2) * cos(x^2)=x / 鈭歴in(x^2) * cos(x^2)
绛旓細绛旓細y=sinx+鈭 [ 1+(cosx)^2 ]璁綼=sinx锛宐=鈭歔1+(cosx)^2]>=1 鍒檃^2=(sinx)^2锛沚^2=1+(cosx)^2鎵浠ワ細a^2+b^2=2锛宐>=1 琛ㄧず鍦嗙己锛屽涓嬪浘鎵绀洪粦鑹插尯鍩 鎵浠ワ細y=a+b琛ㄧず鐩寸嚎b=-a+y 褰撶洿绾跨粡杩囩偣锛1,1锛夋椂锛寉鍊兼渶澶т负2 褰撶洿绾跨粡杩囩偣锛-1,1锛夋椂锛寉鍊兼渶灏忎负0 ...
绛旓細瑙佸浘
绛旓細=cosln鈭(2x+1)*1/鈭(2x+1)*1/2鈭(2x+1)*2 (姹傚椤哄簭渚濇鏄sin銆乴n銆佲垰(2x+1) )=cosln鈭(2x+1)/(2x+1)
