三相电力变压器一次电流怎样计算 变压器的一次电流和二次电流怎么计算
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U₁/U₂=N₁/N₂\uff0cI₁/ I₂=N₂/N₁\u3002
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一次侧I=1250/（1.732*10）=72.2A，二次侧I=1250/（1.732*04）=1804.3A
容量KVA除以电压，就是电流
I＝P/1.732/U
绛旓細S=P涔樹互鍔熺巼鍥犳暟锛汸=1.732涔樹互鐢靛帇涔樹互鐢垫祦锛鎵浠ョ數娴佺瓑浜庡彉鍘嬪櫒鐨勫閲忎箻浠ュ姛鐜囧洜鏁板啀涔樹互鏁堢巼闄や互1.732鍐嶉櫎浠ョ數鍘
绛旓細涓夌浉鍙樺帇鍣ㄧ數娴佺殑璁＄畻鍏紡I=S/锛堟牴鍙3*U锛夛紝寮忎腑锛孶鏄彉鍘嬪櫒鐨勭嚎鐢靛帇锛KV 鍙樺帇鍣ㄧ數娴佺粡楠屽彛绠楁硶锛氫竴娆＄數娴両鈮圫*0.06 浜屾鐢垫祦I鈮圫*1.5 渚嬪锛氫竴鍙500KVA鐨勫彉鍘嬪櫒璁＄畻涓娆＄數娴佸拰浜屾鐢垫祦锛岀敤鐢垫祦鍏紡I=S/锛堟牴鍙3*U锛 I=500/鏍瑰彿3*10=500/17.32鈮28.8A I=500/鏍瑰彿3*0.4=500/0.69=...
绛旓細I绾匡細绾跨數娴侊紝A锛浳︼細鍒濈浉瑙 12銆鍙樺帇鍣宸ヤ綔鍘熺悊 U1/U2=N1/N2=I2/I1 U1銆乁2锛氫竴娆°佷簩娆＄數鍘嬶紝V锛汵1銆丯2锛氫竴娆°佷簩娆＄嚎鍦堝湀鏁帮紱I2銆両1锛氫簩娆°涓娆＄數娴锛孉锛13銆佺數闃汇佺數鎰熶覆鑱旂數璺 I=U/Z Z=锛圧2+XL2锛夊拰鐨勫紑骞虫柟 锛堝紡涓2涓哄钩鏂癸級Z锛氭婚樆鎶楋紝惟锛汭锛氱數娴侊紝A锛汻锛氱數闃伙紝惟锛沊L锛...
绛旓細涓娆′晶棰濆畾鐢垫祦 I=P/U 鈭3=2000/10/1.732=115.77A =116A銆備簩娆′晶棰濆畾鐢垫祦 I=P/U 鈭3=2000/0.4/1.732=2886.84A=2887A銆傚彉鍘嬪櫒鏄敤鏉ュ彉鎹氦娴佺數鍘嬨佺數娴佽屼紶杈撲氦娴佺數鑳界殑涓绉嶉潤姝㈢殑鐢靛櫒璁惧銆傚畠鏄牴鎹數纾佹劅搴旂殑鍘熺悊瀹炵幇鐢佃兘浼犻掔殑銆傚彉鍘嬪櫒灏卞叾鐢ㄩ斿彲鍒嗕负鐢靛姏鍙樺帇鍣ㄣ佽瘯楠屽彉鍘嬪櫒銆佷华鐢ㄥ彉鍘嬪櫒鍙...
绛旓細鍏紡娉曡绠楋細鍙樺帇鍣ㄤ竴娆＄數娴=S/锛1.732*10锛夛紝浜屾鐢垫祦=S/锛1.732*0.4锛銆備竴娆＄數娴佸叾浠栬绠楁柟娉曪細1銆蹇熶及绠楁硶 鍙樺帇鍣ㄥ閲/100锛屽彇鏁存暟鍊嶏紝鐒跺悗*5.5=楂樺帇渚х數娴佸硷紝濡傛灉瑕佹槸*144锛屽氨鏄綆鍘嬩晶鐢垫祦鍊硷紒涓句緥锛氬鏋滀互涓涓1000KVA鐨勫彉鍘嬪櫒锛/100鍙栨暣鏁板嶅悗鏄10锛岄偅涔堥珮鍘嬩晶鐢垫祦灏辨槸10*5.5=55A...
绛旓細/ 锛堟牴鍙3 X 鍙樺帇鍣ㄧ殑棰濆畾鐢靛帇锛塡x0d\x0a\x0d\x0a濡備竴鍙100kVA鐨涓夌浉鍙樺帇鍣锛屽叾涓娆＄數鍘嬩负10kV锛屼簩娆＄數鍘嬩负0.4kV锛屽垯锛歕x0d\x0a鍏涓娆＄數娴锛欼1=S/(1.732XU1)=100/(1.732X10)=5.77(A)\x0d\x0a鍏朵簩娆＄數娴侊細2=S/(1.732XU2)=100/(1.732X0.4)=144(A)
绛旓細1銆鐢靛姏绯荤粺涓夌浉鍙樺帇鍣涓锛屼簩娆＄數娴佺殑鐞嗚鍏紡濡備笅锛氫竴娆＄數娴=鍙樺帇鍣ㄨ鍦ㄥ姛鐜囷紙S锛夐櫎浠ユ牴鍙3鍐嶉櫎浠0.9鍐嶉櫎浠ヤ竴娆′晶鐢靛帇銆備簩娆＄數娴=鍙樺帇鍣ㄨ鍦ㄥ姛鐜囷紙S锛夐櫎浠ユ牴鍙3鍐嶉櫎浠0.9鍐嶉櫎浠ヤ簩娆′晶鐢靛帇銆2銆10KV鍙400V锛6KV鍙400V鐨勪笁鐩搁厤鐢鍙樺帇鍣ㄤ竴娆＄數娴缁忛獙鍏紡濡備笅锛10KV鐨勶紝涓娆＄數娴佺瓑浜庡彉鍘嬪櫒瑙嗗湪鍔熺巼锛圫锛夊墿...
绛旓細涓夌浉鍙樺帇鍣棰濆畾瀹归噺S锛屽崟浣峩VA锛屼竴/浜屾棰濆畾鐢靛帇U1/U2锛屼竴/浜屾棰濆畾鐢垫祦I1/I2 棰濆畾瀹归噺S=鈭3UI锛屼护S=1000kVA锛孶1/U2=10/0.4kV 涓娆棰濆畾鐢垫祦I1=S/鈭3U1=1000kVA梅锛1.732脳10kV锛夆増57.7A 浜屾棰濆畾鐢垫祦I2=S/鈭3U2=1000kVA梅锛1.732脳0.4kV锛夆増1443.4A ...
绛旓細濡傛灉鏄眰涓娆′晶棰濆畾鐢垫祦锛欼1n=鍙樺帇鍣ㄨ鍦ㄥ姛鐜嘢n/[鈭3(鍙樺帇鍣ㄤ竴娆棰濆畾鐢靛帇U1n)]I1n=500kVA/(鈭3*10000V)=50A
绛旓細鍙樺帇鍣ㄧ殑棰濆畾鐢靛帇 鎵浠ュ彉鍘嬪櫒鐨勭殑棰濆畾鐢垫祦=鍙樺帇鍣ㄧ殑棰濆畾瀹归噺 / 锛堟牴鍙3 X 鍙樺帇鍣ㄧ殑棰濆畾鐢靛帇锛夊涓鍙100kVA鐨涓夌浉鍙樺帇鍣锛屽叾涓娆＄數鍘嬩负10kV锛屼簩娆＄數鍘嬩负0.4kV锛屽垯锛氬叾涓娆＄數娴锛欼1=S/(1.732XU1)=100/(1.732X10)=5.77(A)鍏朵簩娆＄數娴侊細2=S/(1.732XU2)=100/(1.732X0.4)=144(A)...
