Python,输入自然数N,得到大于或等于N的N个素数 Python,输入自然数N,得到大于或等于N的N个素数

python \u4ece\u952e\u76d8\u4efb\u610f\u8f93\u5165\u4e00\u4e2a\u6b63\u6574\u6570n,\u5e76\u627e\u51fa\u5927\u4e8en\u7684\u6700\u5c0f\u7d20\u6570\uff0c\u8fd9\u4e2a\u7a0b\u5e8f\u600e\u4e48\u5199

import mathm=input('\u8bf7\u8f93\u5165\u4e00\u4e2a\u6b63\u6574\u6570')n=int(m)while True: n+=1 print(n) f=True a=2 while a<=int(math.sqrt(n)): if n%a==0: f=False break a+=1 if f: print('\u5927\u4e8e\uff05s)\u7684\u6700\u5c0f\u7d20\u6570\u662f%s'%(m,n)) breakMy style:
import mathdef is_prime(n): if n % 2 == 0: return False for i in range(3, math.sqrt(n)+2, 2): if n % i == 0: return False return True def main(): m = n = int(input('\u8bf7\u8f93\u5165\u4e00\u4e2a\u6b63\u6574\u6570')) while True: n += 1 if is_prime(n): print(f'\u5927\u4e8e{m}\u7684\u6700\u5c0f\u7d20\u6570\u662f{n}') return if __name__ == '__main__': main()

N=0num=1n=input("How many prime numbers do you want to find?")while N<int(n): num+=1 div_num=2 while div_num<num: if num % div_num==0: break div_num+=1 else: N+=1 print("\u7b2c%s\u4e2a\u8d28\u6570\u4e3a%s" % (N, num))\u62ff\u8d70\u4e0d\u8c22

def fun(m):

    def isPrime(n):
        if n == 2:
            return True
        for i in range(2, n):
            if n % i == 0:
                return False
        else:
            return True

    res = []
    i = m
    while len(res) != m:
        if isPrime(i):
            res.append(i)
        i += 1
    return res


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