求各位大佬帮忙求这道不定积分 求大佬教教我这道不定积分怎么求！
\u6c42\u6b64\u9898\u7684\u4e0d\u5b9a\u79ef\u5206\uff0c\u6c42\u5404\u4f4d\u6570\u5b66\u5927\u4f6c\u5e2e\u5e2e\u5fd9\uff0c\u6551\u6551\u5b69\u5b50\u3002\u8c22\u8c22\uff1f
\u56e0\u4e3a\u51fd\u6570y=max\uff5b1\uff0c|x|\uff5d\u672c\u6765\u5c31\u662f\u4e00\u4e2a\u5206\u6bb5\u51fd\u6570\uff0c\u51fd\u6570y\u8868\u793a1\u548c|x|\u4e2d\u5927\u7684\u90a3\u4e2a\u6570\uff0c\u5206\u4e09\u6bb5\u5f53x\u5728-1\u52301\u4e4b\u95f4\u65f6\u5019\uff0cx\u7684\u7edd\u5bf9\u503c|x|\u5c0f\u4e8e1\uff0c\u6240\u4ee5y=1\uff1b\u5f53x\uff1e1\u65f6\uff0c|x|=x\u5927\u4e8e1\uff0c\u6240\u4ee5y=x\uff1b\u5f53x\uff1c-1\u65f6\uff0c|x|=-x\u5927\u4e8e1\uff0c\u6240\u4ee5y=-x\uff1b
\u89e3\u7b54:
方法如下，
请作参考：
若有帮助，
请采纳。
见下图：
∫ dx/(1-3x)^2013
=-(1/3)∫ d(1-3x)/(1-3x)^2013
=(1/6036)[1/(1-3x)^2012] + C
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绛旓細=secx tanx - 鈭玹anx d secx 鈥斺 鍒嗛儴绉垎娉 =secx tanx - 鈭玸ecx (tanx)^2 dx 鈥斺 (secx)' = secx tanx =secx tanx - 鈭玸ecx [ 1 - (secx)^2 ] dx 鈥斺 1 + (tanx)^2 = (secx)^2 =secx tanx - 鈭玸ecx dx + 鈭(secx)^3 dx 鈥斺 涓嶅畾绉垎鎬ц川 =secx tanx - ln...
