标况下224ml二氧化硫溶于水
V=224Lc=(224/22.4)/2=5mol/L
n=98/98=1mol
c=1/1=1mol/L
绛旓細c=(224/22.4)/2=5mol/L n=98/98=1mol c=1/1=1mol/L
绛旓細224mlCO2涓 0.01mol 涓0.44g 0.36gH2O 鏄0.02mol 鏍规嵁璐ㄩ噺瀹堟亽锛屽弬鍔犲弽搴旂殑姘ф皵鐨勮川閲忎负 0.44+0.36-0.16=0.64g 姘ф皵鐨勭墿璐ㄧ殑閲忎负0.02mol 鎵浠ユ牴鎹師瀛愬畧鎭 鍙嶅簲鍓嶆湁0.04molO 鍙嶅簲鍚庢湁0.01molC 0.04molO 0.04molH 璇存槑鍙嶅簲鍓嶆湁0.01molC 0.04molH 鎵浠ヤ负CH4 CH4+2O2=CO...
绛旓細鏍囧喌224L姘ㄦ皵鐗╄川鐨勯噺涓10mol銆佽川閲忎负170g锛1000mL姘磋川閲忎负1000g.锛鎵寰楁皑姘存憾娑茶川閲忎负1170g锛屾憾娑蹭綋绉负1.17L銆傝川閲忓垎鏁帮細170g梅1170g=14.53锕 鐗╄川鐨勯噺娴撳害锛10mol梅1.17L=8.55 mol/L
绛旓細鍥犱负HNO3鍒氬ソ瀹屽叏鍙嶅簲锛屽垯婧舵恫涓璑(NO3-)=0.1*0.6-0.224/22.4=0.05mol 鏍规嵁姝ｈ礋鐢佃嵎浠ｆ暟鍜屼负0鍙緱锛孋u锛圢O3锛20.25mol 鏈塁u 0.01mol鍙繕鍘烴O3- 2/300mol锛屽垯杩樻湁1/300mol鐨勬湁Cu2O杩樺師锛屽垯Cu2O 0.005mol鍒機uCu2O鍏辨秷鑰楃幇鍦ㄦ憾娑蹭腑鐨凬O3-绂诲瓙0.02mol锛屽垯鏈塁uO0.03mol 鏈搴旂墷鐗㈡姄浣廋uO...
绛旓細224mLCl2鍚0.02molCl锛屾瘡涓狢l闄嶄綆1浠凤紝涓鍏遍檷浣0.02浠枫傜～浠ｇ～閰告牴鐗╄川鐨勯噺涓0.025*0.1=0.0025mol銆0.02/0.0025=8浠凤紝涔熷氨鏄瘡涓～浠ｇ～閰告牴鍗囬珮8浠凤紝姣忎釜S鍗囬珮4浠枫傜～浠ｇ～閰告牴涓璖涓+2浠凤紝鍙嶅簲鍚庡彉涓虹～閰告牴涓殑+6浠枫傜函鎵嬫墦~甯屾湜鑳藉府鍒版偍~鏈変笉鎳傜殑娆㈣繋杩介棶~鏈涢噰绾砠_^ ...
绛旓細100ml 1mol/L鐨勭洂閰告伆濂藉弽搴旓紝璇存槑鎬诲惈鍚勭褰㈡侀搧0.1/2=0.05mol锛屾斁鍑篐2 224ml鍗0.01mol锛屾墍浠ョ浉褰撲簬娣峰悎鐗〧e/FeO涓惈20%Fe锛80%FeO锛屼笉绠″摢绉嶅舰寮忥紝CO杩樺師鏈缁堝緱鍒伴搧锛屽嵆0.05*55.85绾︾瓑浜2.8鍏嬨
绛旓細鍦鏍囧喌涓锛224L HCl姘斾綋鐗╄川鐨勯噺鏄224/22.4 = 10.0 mol;HCl璐ㄩ噺: 36.5*10.0 = 365 g 婧舵恫璐ㄩ噺: HCl璐ㄩ噺 +635mL姘璐ㄩ噺 = 365 + 635*1 = 1000g 鐩愰吀鐨勮川閲忓垎鏁: 365/1000 = 36.5 婧舵恫浣撶Н: 1000/1.18 = 847 mL = 0.847L 鐗╄川鐨勮川閲忔祿搴: 10.0/0.847 = 11.8 mol/L ...
绛旓細:1.06/(106*0.1)=0.1mol/L 锛2锛塏a锕㈢墿璐ㄧ殑閲忔祿搴:0.1*2=0.2mol/L 锛3锛夐渶瑕佸姞鍏ュ灏 ml 鐨 1mol/L 绋鐩愰吀 鎭板ソ涓1.06g Na2Co3 瀹屽叏鍙嶅簲锛鏍囧喌涓锛岀敓鎴愬灏戜綋绉殑Co2锛烴a2Co3:0.01mol 鏁呴渶瑕佺洂閰革細0.02mol 鎵浠=0.02/1=20ml 鐢熸垚鐨凜O2锛歏=0.01*22.4=0.224L=224ml ...
绛旓細鍥炵瓟锛4銆丅C A銆佸垎瀛愭暟瑕佺浉鍚,鍙互杞负鐗╄川鐨勯噺鐩稿悓銆傜墿璐ㄩ噸閲忕浉绛,鐩稿鍒嗗瓙璐ㄩ噺涓嶇瓑,鍒欑墿璐ㄧ殑閲忎笉 绛夈侶2鏄5mol,O2鏄10/32mol(鍒╃敤鍏紡n=m/M) B銆鏍囧喌涓鐨5.6L N2涓0.25mol,11g CO2鏄0.25mol銆傜墿璐ㄧ殑閲忕浉绛,鍒欏垎瀛愭暟鐩稿悓銆傛纭 C銆9g H2O鏄0.5mol,0.5mol Br2,鐩哥瓑銆傛纭 D銆...
绛旓細鏍囧噯鐘跺喌涓姘ㄦ按鍦ㄦ按涓涓瀹氱殑婧惰В搴︼紝涓嶈兘鍏ㄩ儴婧惰В锛屾渶澶у彧鑳 17mol/L,瑙佷笅鍥
