python用字典统计不同字符的个数
这里用到了字典基本的建立，value调用，键值对增加，value修改，以及items（）函数。编程实现
流程：文件遍历-除去空白——判断字典中有无该字符——有则Value加1，无则新建为1——按Value排序并返回
具体实现代码如下：
#统计txt文件中的字符频率
def countwords(txt):
stat = {}#建立字典存储存储字符和对应频率
for line in txt:
line = line.strip()
if len(line) == 0:
continue
for i in range(len(line)):
#判断有无该字符的键
if(line[i] in stat):
stat[line[i]]+=1
else:
stat[line[i]]=1
result=sorted(stat.items(),key = lambda x:x[1],reverse = True)#按value大小排序
return result
xyj = open('xyj.txt' ,'r',encoding = 'utf-8')#读文件
r=countwords(xyj)#调用函数
xyj.close
绛旓細鎵惧嚭鍙ュ瓙涓嚭鐜板湪璇嶅吀涓殑璇峸ord_set = {'apple', 'doctor', 'day', 'dummy'}sentence = 'An apple a day keeps the doctor away'for word in sentence.split(): if word.lower() in word_set: print(word)
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