从写有6.7.8.9的四张卡片中有放回各取一张,则两次取到数字和为偶数的概率为 一个盒子中装有5张卡片,每张卡片上写有一个数字,数字分别是1...

\u4ece\u5206\u522b\u5199\u67091\uff0c2\uff0c3\uff0c4\uff0c5\uff0c6\uff0c7\uff0c8\uff0c9\u76849\u5f20\u5361\u7247\u4e2d\uff0c\u4efb\u53d62\u5f20\uff0c\u89c2\u5bdf\u4e0a\u9762\u7684\u6570\u5b57\uff0c\u6c42\u4e0b\u5217\u4e8b\u4ef6\u7684\u6982\u7387\uff1a \uff081\uff09

\u89e3\uff1a\u5047\u8bbe\u62bd\u53d6\u5361\u7247\u6709\u5148\u540e\u987a\u5e8f\uff0c\u65e0\u653e\u56de\uff0c\u5219\u57fa\u672c\u4e8b\u4ef6\u4e0e\u70b9\u96c6S={\uff08x\uff0cy\uff09|x\u2208N*\uff0cy\u2208N*\uff0c1\u2264x\u22649\uff0c1\u2264y\u22649\u4e14x\u2260y} \u4e2d\u7684\u5143\u7d20\u4e00\u4e00\u5bf9\u5e94\uff0c\u800cS\u4e2d\u70b9\u7684\u4e2a\u6570\u67099\u00d78=72\uff08\u4e2a\uff09\uff0c\u6240\u4ee5\u57fa\u672c\u4e8b\u4ef6\u603b\u6570\u4e3a72\u4e2a\uff0c\u800c\u672c\u9898\u4e2d\u62bd\u53d6\u5361\u7247\u65e0\u5e8f\uff0c\u6240\u4ee5\u57fa\u672c\u4e8b\u4ef6\u603b\u6570\u4e3a36\u4e2a\uff1b\uff081\uff09\u548c\u4e3a\u5947\u6570\u7684\u6761\u4ef6\u662f\u62bd\u53d6\u7684\u4e24\u4e2a\u6570\u7684\u5947\u5076\u6027\u4e0d\u540c\uff0c\u5373\u4ece1\uff0c3\uff0c5\uff0c7\uff0c9\u4e2d\u53d61\u4e2a\u6570\uff0c\u4ece2\uff0c4\uff0c6\uff0c8\u4e2d\u53d61\u4e2a\u6570\u7684\u60c5\u51b5\uff0c\u4ece1\uff0c3\uff0c5\uff0c7\uff0c9\u4e2d\u62bd\u53d61\u4e2a\u6570\u7684\u60c5\u51b5\u67095\u79cd\uff0c\u4ece2\uff0c4\uff0c6\uff0c8\u4e2d\u62bd\u53d61\u4e2a\u6570\u7684\u60c5\u51b5\u67094\u79cd\uff0c\u6545\u201c\u4e24\u4e2a\u6570\u7684\u548c\u4e3a\u5947\u6570\u201d\u7684\u57fa\u672c\u4e8b\u4ef6\u5171\u67095\u00d74=20\uff08\u4e2a\uff09\uff0c\u6240\u4ee5\u6982\u7387 \uff1b \uff082\uff09\u4e24\u4e2a\u6570\u7684\u79ef\u4e3a\u5b8c\u5168\u5e73\u65b9\u6570\u5305\u62ec1\u00d74\uff0c1\u00d79\uff0c2\u00d78\uff0c4\u00d79 \u5171\u67094\u79cd\u60c5\u51b5\uff0c\u6240\u4ee5\u6982\u7387 \u3002

\uff08\u2160\uff09\u56e0\u4e3a1\uff0c3\uff0c5\u662f\u5947\u6570\uff0c2\u30014\u662f\u5076\u6570\uff0c\u8bbe\u4e8b\u4ef6A\u4e3a\u201c\u4e24\u6b21\u53d6\u5230\u7684\u5361\u7247\u7684\u6570\u5b57\u90fd\u4e3a\u5947\u6570\u6216\u5076\u6570\u201d\uff082\u5206\uff09 P(A)= C 23 + C 22 C 25 = 2 5 \uff084\u5206\uff09\uff08\u2161\uff09\u8bbeB\u8868\u793a\u4e8b\u4ef6\u201c\u6709\u653e\u56de\u5730\u62bd\u53d63\u6b21\u5361\u7247\uff0c\u6bcf\u6b21\u62bd\u53d6\u4e00\u5f20\uff0c\u6070\u6709\u4e24\u6b21\u53d6\u5230\u7684\u5361\u7247\u4e0a\u6570\u5b57\u4e3a\u5947\u6570\u201d\uff0c\uff085\u5206\uff09\u7531\u5df2\u77e5\uff0c\u6bcf\u6b21\u53d6\u5230\u7684\u5361\u7247\u4e0a\u6570\u5b57\u4e3a\u5947\u6570\u7684\u6982\u7387\u4e3a 3 5 \uff0c\uff086\u5206\uff09\u5219 P(B)= C 23 ? ( 3 5 ) 2 ?(1- 3 5 )= 54 125 \uff088\u5206\uff09\uff08\u2161\uff09\u4f9d\u9898\u610f\uff0cX\u7684\u53ef\u80fd\u53d6\u503c\u4e3a1\uff0c2\uff0c3\uff0e P(X=1)= 3 5 \uff0c P(X=2)= 2\u00d73 5\u00d74 = 3 10 \uff0c P(X=3)= 2\u00d71\u00d73 5\u00d74\u00d73 = 1 10 \uff0c\uff0811\u5206\uff09\u6240\u4ee5X\u7684\u5206\u5e03\u5217\u4e3a X 1 2 3 P 3 5 3 10 1 10 E(X)=1\u00d7 3 5 +2\u00d7 3 10 +3\u00d7 1 10 = 3 2 \uff0e\uff0813\u5206\uff09



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