2X的平方-5X-3怎么因式分解 2x-5x-3因式分解

2x\u7684\u5e73\u65b9-5x-3\u7528\u5341\u5b57\u76f8\u4e58\u6cd5\u56e0\u5f0f\u5206\u89e3

2x\u7684\u5e73\u65b9-5x-3\u7528\u5341\u5b57\u76f8\u4e58\u6cd5\u56e0\u5f0f\u5206\u89e3
\u89e3\uff1a
2 1
\u00d7
1 -3
\u6240\u4ee5
\u539f\u5f0f=(2x+1)(x-3)

\u9898\u76ee\u5e94\u8be5\u662f2x²-5x-3\u5427
\u5206\u89e3\u4e3a\uff082x+1\uff09\uff08x-3\uff09

用十字相乘法
2x`2-5x-3
x -3
2x 1

可以得出 (x-3)(2x+1) 在线教你

2x^2-5x-3=2[x^2-(5/2)x-(3/2)]=2[x^2-3x+(1/2)x-3·(1/2)]
=2[x(x-3)+(1/2)(x-3)]=2(x+1/2)(x-3) =(2x+1)(x-3)

2x^2-5x-3
=2x^2-6x+x-3
=2x(x-3)+(x-3)
=(x-3)(2x+1)

(2x+1)(x-3)

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