从键盘上输入一个三位整数n,判断各位数字之和是否为3的倍数，若是输出yes,否则输出no(c语言)？ "从键盘输入一个正整数判断他是否为3和5倍数是则输出yes否...
\u8bf7\u8bbe\u8ba1\u4e00\u4e2a\u8ba1\u7b97\u673a\u7a0b\u5e8f\u6765\u5224\u65ad,\u4ece\u952e\u76d8\u8f93\u5165\u7684\u6574\u6570\u662f\u5426\u662f3\u7684\u500d\u6570,\u5982\u679c\u662f\u5c31\u8f93\u201cyes\u201d\u3001\u5426\u5c31\u8f93\u5165\u201cNo\u201d#include
void main(){
int a;
scanf("%d",a);
if(a%3==0)
printf("a\u662f3\u7684\u500d\u6570");}
\u4f60\u597d\uff0c\u6d4b\u8bd5\u901a\u8fc7\u671b\u91c7\u7eb3\uff01#includevoid main(){ int n; scanf("%d",&n); if(n%3==0 && n%5==0) printf("yes\n"); else printf("no\n");}
两种方法：
一、用字符串保存输入，输入3个数字字符。
二、用int型保存输入，通过整除、求余的操作获取每一位数字，再将3位数和与3求余，余为0就是3的倍数。
下面用方法二写：
#include <stdio.h>
int main()
{
int num,g,s,b;
printf("请输入一个三位数:"),scanf("%d",&num);
g=num%10,s=(num%100)/10,b=num/100;
if((g+s+b)%3==0) printf("yes
");
else printf("No
");
return 0;
}
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绛旓細int main(void){ int num, hundred, ten, indiv;printf("璇杈撳叆涓涓笁浣嶆暣鏁:");scanf("%d",&num);hundred=num/100;ten=(num-hundred*100)/10;indiv=num-hundred*100-ten*10;printf("浠庡彸鍒板乏鐨勫悇浣嶆暟瀛%d%d%d\n", indiv, ten, hundred);return 0;} ...
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绛旓細浣犲ソ锛氳繖涓緢绠鍗曠殑瀹炵幇鏂规硶锛屼綘鍙互鍙傝冧笅 int i = 12343465; int m = 0; while (i != 0) { m =i%10; System.out.print(m); i = i/10; }
绛旓細int main(){ int num;scanf("%d",&num);printf("鐧句綅鏁板瓧锛%d\n",num / 100);printf("涓綅鏁板瓧锛%d\n",num % 10);return 0;} 杩欏凡缁忔槸杈冨畬鏁寸殑浠ｇ爜浜嗭紒鍓嶆彁鏄綘鐨勬寜浣犺嚜宸辫瀹氱殑瑕佹眰杈撳叆鏁板硷紒锛佲/鈥濆拰鈥%鈥濅负闄ゆ硶杩愮畻鍜屽彇妯★紙浣欙級杩愮畻銆傝繖棰樻槸寰堢畝鍗曠殑锛乪g锛歩nclude<stdio.h> in...
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绛旓細鐢╟璇█鍒嗗埆杈撳嚭涓綅鍗佷綅鍜岀櫨浣嶇殑鏁板瓧锛屽彲浠ユ牴鎹笅闈㈡楠よ繘琛岋紝c璇█浣滀负涓绉嶇▼搴忎唬鐮侊紝鍥犳鍦杈撳叆鏃剁粷瀵逛笉鑳藉紕閿欎换浣曠鍙枫俰nclude<stdio.h> int main(){int x;scanf("%d",&x);printf("%d鐨勭櫨浣=%d锛屽崄浣=%d锛屼釜浣=%d\n",x,x/100,x/10%10,x%10);return 0;} ...
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