C语言数组题:循环输入10个元素的整型数组,倒序输出数组元素。把代码写下来,谢谢! 输入10个整数到数组A中,将数组各元素依次向后循环移动一个位...

\u5b9a\u4e49\u4e00\u4e2a\u670910\u4e2a\u5143\u7d20\u7684\u4e00\u7ef4\u6574\u578b\u6570\u7ec4\uff0c\u4ece\u952e\u76d8\u8f93\u5165\u7ed9\u6570\u7ec4\u7684\u6bcf\u4e2a\u5143\u7d20\u8d4b\u503c\uff0c\u5e76\u628a\u6bcf\u4e2a\u5143\u7d20\u8fdb\u884c\u8f93\u51fa\u3002

#include
printf("\u8bf7\u8f93\u516510\u4e2a\u6574\u6570\uff1a\n");
for(i=0;i<n;i++)
scanf("%d",&a[i]);
printf("\n\u8f93\u5165\u768410\u4e2a\u6570\u662f\uff1a\n");
printf("\u8f93\u51fa\u4f60\u8f93\u5165\u7684\u5143\u7d20:\n");
for(int i=0;i<10;i++){
printf("arr[%d]=%d\n",i,arr[i]);
}
printf("\u6570\u7ec4\u603b\u548c\u4e3a:%d\n",sum);
}

\u4e0e\u7ed3\u6784\u6216\u7c7b\u4e2d\u7684\u5b57\u6bb5
\u6570\u7ec4\u4e2d\u7684\u6240\u6709\u5143\u7d20\u90fd\u5177\u6709\u76f8\u540c\u7c7b\u578b\uff08\u8fd9\u4e00\u70b9\u548c\u7ed3\u6784\u6216\u7c7b\u4e2d\u7684\u5b57\u6bb5\u4e0d\u540c\uff0c\u5b83\u4eec\u53ef\u4ee5\u662f\u4e0d\u540c\u7c7b\u578b\uff09\u3002\u6570\u7ec4\u4e2d\u7684\u5143\u7d20\u5b58\u50a8\u5728\u4e00\u4e2a\u8fde\u7eed\u6027\u7684\u5185\u5b58\u5757\u4e2d\uff0c\u5e76\u901a\u8fc7\u7d22\u5f15\u6765\u8bbf\u95ee\uff08\u8fd9\u4e00\u70b9\u4e5f\u548c\u7ed3\u6784\u548c\u7c7b\u4e2d\u7684\u5b57\u6bb5\u4e0d\u540c\uff0c\u5b83\u4eec\u901a\u8fc7\u540d\u79f0\u6765\u8bbf\u95ee\uff09\u3002
\u6570\u7ec4\u5143\u7d20\u5e76\u975e\u53ea\u80fd\u662f\u57fa\u5143\u6570\u636e\u7c7b\u578b\uff0c\u8fd8\u53ef\u4ee5\u662f\u7ed3\u6784\u3001\u679a\u4e3e\u6216\u7c7b\u3002
\u4ee5\u4e0a\u5185\u5bb9\u53c2\u8003\uff1a\u767e\u5ea6\u767e\u79d1-\u6570\u7ec4

#include
#include

#define N 10 /*N\u4e3a\u6570\u7ec4\u53ef\u80fd\u7684\u6700\u5927\u503c*/

int main(void)
{
int a[N];
int temp;
int i;

for(i = 0;i < N;i ++) /*\u4f9d\u6b21\u8bfb\u5165*/
{
scanf("%d", &a[i]);
}

temp = a[N - 1]; /*\u5148\u7f6e\u51fa\u6700\u540e\u4e00\u9879*/

for(i= N - 2;i >= 0;i --) /*\u81ea\u540e\u5411\u524d\u7f6e\u5165*/
{
a[i + 1] = a [i];
}

a[0] = temp; /*\u5c06\u7b2c\u4e00\u4e2a\u503c\u8bfb\u5165*/

for(i = 0;i < N;i ++)
{
printf("%d\t", a[i]);
}

getch();
}

#include<stdio.h>
int main()
{
int a[10],i;
printf("input 10 int data\n");
for (i=0;i<10;i++) scanf("%d",&a[i]); //输入10个
printf("\n");
for (i=9;i>=0;i--) printf("%d ",a[i]); //倒序输出
printf("\n");
return 0;
}
例:
input 10 int data
1 2 3 4 5 6 7 8 9 10
10 9 8 7 6 5 4 3 2 1



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