初二上学期物理计算题（含答案） 30道初二上学期物理计算题及答案
\u8981\u521d\u4e8c\u4e0a\u518c\u7269\u7406\u8ba1\u7b97\u9898100\u9053\uff0c\u542b\u89e3\u7b54\u8fc7\u7a0b\u548c\u7b54\u6848\u3000\u4e00\u8f86\u6c7d\u8f66\u6cbf\u5e73\u76f4\u516c\u8def\u671d\u5c71\u5d16\u5300\u901f\u884c\u9a76\uff0c\u5728\u79bb\u5c71\u5d16s1\u5904\u9e23\u7b1b\uff0c\u6c7d\u8f66\u7ee7\u7eed\u5411\u524d\u884c\u9a76\uff0c\u6c7d\u8f66\u79bb\u9e23\u7b1b\u5904\u4e3as2\u65f6\uff0c\u53f8\u673a\u521a\u597d\u542c\u5230\u521a\u624d\u9e23\u7b1b\u7684\u56de\u58f0\uff0c\u5df2\u77e5s1:s2=12:1\uff0c\u58f0\u97f3\u5728\u7a7a\u6c14\u4e2d\u7684\u4f20\u64ad\u901f\u5ea6\u662f340m/s\uff0c\u6c42\u6c7d\u8f66\u884c\u9a76\u7684\u901f\u5ea6\u7684\u5927\u5c0f\uff08\u5728\u6574\u4e2a\u8fc7\u7a0b\u4e2d\uff0c\u6c7d\u8f66\u4e00\u76f4\u5728\u4f5c\u5300\u901f\u884c\u9a76\uff1b\u56de\u58f0\u7531\u5c71\u5d16\u53cd\u5c04\u9e23\u7b1b\u58f0\u6240\u5f62\u6210\uff09
\u89e3\uff1a\u56e0\u4e3as1\uff1as2=12\uff1a1,
\u3000\u3000\u6240\u4ee5S1=12S2\u58f0\u97f3\u4f20\u64ad\u7684\u8ddd\u79bb\uff1a
\u3000\u3000\u58f0= 2S1-S2=2*12S2-S2=23S2\uff0c
\u3000\u3000\u6240\u7528\u7684\u65f6\u95f4\uff1at=S\u58f0/v\u58f0=23S2/340
\u3000\u3000\u56e0\u6b64\u8f66\u901f\uff1aV\u8f66=S\u8f66/t= S2/(23S2/340)=340/23=14.78m/s
\u7b54\uff1a\u6c7d\u8f66\u884c\u9a76\u7684\u901f\u5ea6\u4e3a14.78m/s
\u4e00\u652f\u961f\u4f0d\u957f50m\uff0c\u4ee55m\u6bcf\u79d2\u7684\u901f\u5ea6\u901a\u8fc7\u4e00\u5ea7\u957f100m\u7684\u6865\uff0c\u4ece\u7b2c\u4e00\u4eba\u4e0a\u6865\u5230\u6700\u540e\u4e00\u4eba\u79bb\u5f00\u6865\u7528\u4e86\u591a\u5c11\u65f6\u95f4\uff1f
\u5df2\u77e5\uff1av=5m/s\uff0cS\u961f=50m\uff0cS\u6865\uff1d100m
\u6c42\uff1at
\u89e3\uff1at=S/v=(S+S)/v=(50m+100m)/5m/s=30s
\u7b54\uff1a\u4ece\u7b2c\u4e00\u4eba\u4e0a\u6865\u5230\u6700\u540e\u4e00\u4eba\u79bb\u5f00\u6865\u7528\u4e8630s\u7684\u65f6\u95f4
\u7532\u3002\u4e59\u4e24\u5730\u76f8\u8ddd162km\uff0c\u6c7d\u8f66\u4ee510m/s\u7684\u901f\u5ea6\u4ece\u7532\u5730\u51fa\u53d1\uff0c\u884c\u9a76\u4e8672\u5343\u7c73\u540e\uff0c\u63a5\u7740\u4ee545km/s\u7684\u901f\u5ea6\u884c\u9a76\u5230\u4e59\u5730\uff0c\u6c42\u6c7d\u8f66\u4ece\u7532\u5230\u4e59\u7684\u5e73\u5747\u901f\u5ea6
\u5df2\u77e5\uff1aS\uff1d162km\uff0cS1=72km v2=45km/h
\u6c42\uff1a\u5168\u7a0b\u7684\u5e73\u5747\u901f\u5ea6v\u89e3\uff1a10m/s=36km/hv=S/t=162/[72/36+(162-72)/45]=162/4=40.5(km/h)\u7b54\uff1a\u6c7d\u8f66\u4ece\u7532\u5230\u4e59\u7684\u5e73\u5747\u901f\u5ea6\u662f40.5km/h
\u4e00\u5217\u957f200\u7c73\u7684\u706b\u8f66\u4e0054\u5343\u7c73/\u65f6\u7684\u901f\u5ea6\u901a\u8fc7\u4e00\u4e2a\u957f700\u7c73\u7684\u5c71\u4e1c\u9700\u8981\u591a\u5c11\u65f6\u95f4?
\u7b54 4km/h=15m/s
t=s/v=(200+700)/15=60s
2.\u8774\u8776\u98de\u7fd4\u7684\u901f\u5ea6\u662f5\u7c73/\u79d2,\u8981\u975e\u5230\u8ddd\u51fa\u53d1\u70b90.6\u5343\u7c73\u7684\u82b1\u56ed,\u5b83\u8981\u82b1\u591a\u5c11\u65f6\u95f4?
\u7b54 t=s/v=600/5=120s
3.\u7532\u3001\u4e59\u4e24\u8f66\u5728\u540c\u4e00\u5e73\u76f4\u516c\u8def\u4e0a\u540c\u5411\u5f62\u5f0f,\u7532\u8f66\u901f\u5ea6\u4e3a10\u5343\u7c73/\u5c0f\u65f6,\u4e59\u8f66\u7684\u901f\u5ea6\u662f30\u5343\u7c73/\u5c0f\u65f6,\u4e59\u8f66\u53d1\u73b0\u5230\u8ffd\u4e0a\u7532\u8f66\u5f62\u5f0f\u4e8615\u5343\u7c73,\u6c42\u4e59\u8f66\u53d1\u73b0\u7532\u8f66\u65f6\u4e24\u8f66\u76f8\u8ddd\u591a\u5c11\u5343\u7c73
\u7b54 \u8bbe\u76f8\u8dddX.
t=15/10=1.5s
30*1.5=10*1.5+X
4.\u7532\u4e59\u4e24\u62b5\u76f8\u8ddd70\u5343\u7c73,\u4e00\u8f86\u6c7d\u8f66\u4ece\u7532\u5730\u5411\u4e59\u5730\u5f00\u51fa,\u901f\u5ea6\u662f15\u7c73/\u79d2,\u4e00\u8f86\u81ea\u884c\u8f66\u540c\u65f6\u4ece\u4e59\u5730\u51fa\u53d1\u9a76\u5411\u7532\u5730,\u4ed6\u4eec\u5728\u79bb\u7532\u573054\u5343\u7c73\u5904\u76f8\u9047.\u6c42\u81ea\u884c\u8f66\u7684\u901f\u5ea6\u662f\u591a\u5c11\u5343\u7c73/\u65f6
\u7b54 15m/s=54km/h
t=54/54=1h
v=s/t=(70-54)/1=16m/s
5.\u4e00\u8258\u5de1\u6d0b\u8230\u752870\u5343\u7c73/\u5c0f\u65f6\u7684\u901f\u5ea6\u8ffd\u8d76\u5728\u5b83\u524d\u976210\u5343\u7c73\u7684\u4e00\u8258\u6218\u6597\u8230,\u5de1\u6d0b\u8230\u8ffd\u4e86210\u5343\u7c73,\u6070\u597d\u8d76\u4e0a\u6218\u6597\u8230,\u6c42\u6218\u6597\u8230\u7684\u901f\u5ea6.
\u7b54 t=s/v=210/70=3h
\u8bbe\u901f\u5ea6\u4e3aV
210=3*V+10
6 \u7528\u4e00\u53ea\u73bb\u7483\u676f\u3001\u6c34\u548c\u5929\u5e73\u6d4b\u5b9a\u77f3\u5b50\u5bc6\u5ea6\uff0c\u5b9e\u9a8c\u8bb0\u5f55\u5982\u4e0b\uff1a\u676f\u5b50\u88c5\u6ee1\u6c34\u540e\u7684\u603b\u8d28\u91cfm1\uff1d200g\uff0c\u653e\u5165\u77f3\u5b50\u540e\uff0c\u676f\u5b50\u3001\u6c34\u3001\u77f3\u5b50\u603b\u8d28\u91cfm2\uff1d215g\uff0c\u53d6\u51fa\u77f3\u5b50\u540e\uff0c\u676f\u5b50\u548c\u6c34\u7684\u603b\u8d28\u91cf\u4e3am3\uff1d190g\uff0c\u6c42\u77f3\u5b50\u5bc6\u5ea6\u3002
\u7b54 m\u77f3=m2-m3=215g-190g=25g
v\u77f3=v\u6c34=\u5012\u51fa\u6c34\u7684\u8d28\u91cf/\u5012\u51fa\u6c34\u7684\u5bc6\u5ea6=200g-190g/1g/cm3=2.5g/cm3
7 \u7532\u4e59\u4e24\u540c\u5b66\u5206\u522b\u5728\u4e00\u8ddf\u94c1\u7ba12\u4fa7\uff0c\u94c1\u7ba1\u957f153\u7c73\uff0c\u7532\u5728\u5176\u4e00\u7aef\u6572\u51fb\u4e86\u4e00\u4e0b\uff0c\u4e59\u540c\u5b66\u542c\u89c1\u4e86\u4e24\u6b21\u58f0\u97f3\u3002\u5df2\u77e5\u542c\u5230\u4e24\u6b21\u58f0\u97f3\u7684\u95f4\u9694\u4e3a0.42\u79d2\u3002\u6c42\u58f0\u97f3\u5728\u94c1\u7ba1\u4e2d\u4f20\u64ad\u7684\u901f\u5ea6\u3002
\u89e3\uff1aT\u7a7a=S\u7a7a\u00f7V\u7a7a=153M\u00f7340M/S=0.45S
T\u94c1=T\u7a7a-0.42S=0.45S-0.42S=0.03S
V\u94c1=S\u00f7T\u94c1=153M\u00f70.03S=5100M/S
\u7b54\uff1a\u58f0\u97f3\u5728\u94c1\u7ba1\u4e2d\u4f20\u64ad\u901f\u5ea6\u4e3a5100\u7c73/\u79d2\u3002
8 \u9898\u76ee\uff1a\u6709\u4e00\u5c71\u5ce1\u5bbd1200\u7c73\uff0c\u4e24\u65c1\u90fd\u662f\u7ad6\u76f4\u5f92\u58c1\uff0c\u6709\u4e00\u4eba\u5728\u5c71\u5ce1\u5185\u653e\u4e00\u67aa\uff0c\u5934\u4e24\u6b21\u56de\u58f0\u95f4\u96945\u79d2\uff0c\u5219\u4eba\u79bb\u4e24\u58c1\u7684\u8ddd\u79bb\u662f\u591a\u5c11\uff1f\uff08\u8bbe\u58f0\u901fv\uff1d340\u7c73\uff0f\u79d2\uff09
\u7b54\u6848\uff1a1025\u7c73\uff0c175\u7c73\u3002
\u89e3\uff1a\u8bbe\u8ddd\u79bb\u4e3as,1200-s
s/340-(1200-s)/340=1200
s=1025
9 \u6709\u4e00\u5c71\u5ce1\u5bbd1200\u7c73\uff0c\u4e24\u65c1\u90fd\u662f\u5ced\u58c1\u3002\u6709\u4eba\u5728\u5c71\u5ce1\u5185\u653e\u4e00\u67aa\uff0c\u4ed6\u542c\u5230\u5934\u4e24\u6b21\u56de\u58f0\u95f4\u96945\u79d2\uff0c\u6c42\u8fd9\u4e2a\u4eba\u79bb\u4e24\u5ced\u58c1\u7684\u8ddd\u79bb\u3002\uff08\u7a7a\u6c14\u4e2d\u58f0\u901f\u4e3a340m/s\uff09
\u89e3\uff1a\u8bbe\u4eba\u79bb\u4e00\u5ced\u58c1\u7684\u8ddd\u79bb\u4e3ax,\u79bb\u53e6\u4e00\u5ced\u58c1\u7684\u8ddd\u79bb\u4e3a1200-x
\u5219\u58f0\u97f3\u5230\u4e24\u5ced\u58c1\u5e76\u8fd4\u56de\u7684\u65f6\u95f4\u5206\u522b\u4e3a\uff1a2x/340,2(1200-x)/340.
\u7531\u9898\u610f\uff0c2x/340-2(1200-x)/340=5
\u89e3\u5f97x=1025,1200-x=175
\u6240\u4ee5\u4eba\u79bb\u4e24\u5ced\u58c1\u7684\u8ddd\u79bb\u5206\u522b\u4e3a1025\u7c73\u548c175\u7c73\u3002
10 \u4e00\u95e8\u53cd\u5766\u514b\u70ae\u7784\u51c6\u4e00\u8f86\u5766\u514b\uff0c\u5f00\u70ae\u540e\u7ecf\u8fc70.6s\u770b\u5230\u70ae\u5f39\u5728\u5766\u514b\u4e0a\u7206\u70b8\uff0c\u7ecf\u8fc72.1s\u542c\u5230\u7206\u70b8\u7684\u58f0\u97f3\uff0c\u6c42\u5927\u70ae\u8ddd\u5766\u514b\u591a\u5143\uff1f\u70ae\u5f39\u7684\u98de\u884c\u901f\u5ea6\u591a\u5927\uff1f
\u8ddd\u79bbS\uff1d2.1*340m=714m
\u7b54 \u98de\u884c\u901f\u5ea6\uff1av=S/t=714/0.6=1190m/s
1\u3001 \u4e00\u5757\u4f53\u79ef\u4e3a100\u5398\u7c733\u7684\u51b0\u5757\u7194\u5316\u6210\u6c34\u540e\uff0c\u4f53\u79ef\u5982\u4f55\u6539\u53d8\uff0c\u6539\u53d8\u591a\u5c11\uff1f
m = \u03c1V = 100cm^3 * 0.9g/cm^3 =90g -------\u51b0\u5757\u7684\u8d28\u91cf
V = m/\u03c1 = 90g / 1g/cm^3 = 90cm^3 -------\u878d\u5316\u540e\u8d28\u91cf\u4e0d\u53d8\uff0c\u7b97\u51fa\u6c34\u7684\u4f53\u79ef\u4e3a90cm^3(90ml)
2\u3001\u6709\u4e00\u7a7a\u74f6\u5b50\u8d28\u91cf\u662f50\u514b\uff0c\u88c5\u6ee1\u6c34\u540e\u79f0\u5f97\u603b\u8d28\u91cf\u4e3a250\u514b\uff0c\u88c5\u6ee1\u53e6\u4e00\u79cd\u6db2\u4f53\u79f0\u5f97\u603b\u8d28\u91cf\u4e3a200\u514b\uff0c\u6c42\u8fd9\u79cd\u6db2\u4f53\u7684\u5bc6\u5ea6\uff1f
3\u3001\u6709\u4e00\u8282\u6cb9\u8f66\uff0c\u88c5\u6ee1\u4e8630\u7c733\u7684\u77f3\u6cb9\uff0c\u4e3a\u4e86\u4f30\u7b97\u8fd9\u8282\u6cb9\u8f66\u6240\u88c5\u77f3\u6cb9\u7684\u8d28\u91cf\uff0c\u4ece\u4e2d\u53d6\u51fa\u4e8630\u5398\u7c733\u77f3\u6cb9\uff0c\u79f0\u5f97\u8d28\u91cf\u662f24.6\u514b\uff0c\u95ee\uff1a\u8fd9\u8282\u6cb9\u8f66\u6240\u88c5\u77f3\u6cb9\u8d28\u91cf\u662f\u591a\u5c11\uff1f
4\u3001\u6709\u4e00\u8d28\u91cf\u4e3a5.4\u5343\u514b\u7684\u94dd\u7403\uff0c\u4f53\u79ef\u662f3000\u5398\u7c733\uff0c\u8bd5\u6c42\u8fd9\u4e2a\u94dd\u7403\u662f\u5b9e\u5fc3\u8fd8\u662f\u7a7a\u5fc3\uff1f\u5982\u679c\u662f\u7a7a\u5fc3\uff0c\u5219\u7a7a\u5fc3\u90e8\u5206\u4f53\u79ef\u591a\u5927\uff1f\u5982\u679c\u7ed9\u7a7a\u5fc3\u90e8\u5206\u704c\u4e00\u534a\u6c34\uff0c\u5219\u7403\u7684\u603b\u8d28\u91cf\u662f\u591a\u5927\uff1f
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\u4f8b3 \u4f53\u79ef\u4e3a30 cm3\uff0c\u8d28\u91cf\u4e3a178g\u7684\u7a7a\u5fc3\u94dc\u7403\uff0c\u5982\u679c\u5728\u5176\u7a7a\u5fc3\u90e8\u5206\u94f8\u6ee1\u94dd\uff0c\u95ee\u94dd\u7684\u8d28\u91cf\u4e3a\u591a\u5c11\uff1f \u8981\u6c42\u51fa\u7a7a\u5fc3\u90e8\u5206\u94f8\u6ee1\u7684\u94dd\u7684\u8d28\u91cf\uff0c\u53ef\u5229\u7528\u516c\u5f0fm\uff1d\u03c1V\u6c42\u5f97\uff0c\u4f46\u8fd9\u91cc\u7684\u5173\u952e\u662f\u6c42\u51fa\u94dd\u7684\u4f53\u79ef\u3002\u6839\u636e\u9898\u610f\u53ef\u77e5\uff0c\u94dd\u7684\u4f53\u79ef\u7b49\u4e8e\u94dc\u7403\u7a7a\u5fc3\u90e8\u5206\u7684\u4f53\u79ef\uff0c\u800c\u7a7a\u5fc3\u90e8\u5206\u7684\u4f53\u79ef\u7b49\u4e8e\u7403\u7684\u4f53\u79ef\u51cf\u53bb\u94dc\u7684\u4f53\u79ef\u3002\u25b3V\uff1dV\u7403\uff0dV\u94dc\uff1d30\u00d710\uff0d6 m3\uff0d2\u00d710\uff0d5 m3\uff1d1\u00d710\uff0d5 m3\uff1dV\u94ddm\u94dd\uff1d\u03c1\u94ddV\u94dd\uff1d2.7\u00d7103 kg/m3\u00d71\u00d710\uff0d5 m3\uff1d27g\u4e13\u9898\u70b9\u8bc4 \u672c\u9898\u7684\u5173\u952e\u662f\u5148\u7528\u94dd\u7684\u4f53\u79ef\u4e0e\u7a7a\u5fc3\u90e8\u5206\u7684\u4f53\u79ef\u76f8\u7b49\uff0c\u518d\u501f\u52a9\u4e8e\u5bc6\u5ea6\u7684\u53d8\u5f62\u516c\u5f0f\u6c42\u51fa\u3002
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1\u3001\u4e00\u4e2a\u74f6\u5b50\u7684\u8d28\u91cf\u662f0.2 kg\uff0c\u88c5\u6ee1\u6c34\u65f6\u603b\u8d28\u91cf\u4e3a0.7 kg.\u5f53\u88c5\u6ee1\u53e6\u4e00\u79cd\u6db2\u4f53\u65f6\uff0c\u603b\u8d28\u91cf\u4e3a0.8 kg\uff0c\u5219\uff1a\uff081\uff09 \u6c42\u6b64\u6db2\u4f53\u7684\u5bc6\u5ea6\uff1b\uff082\uff09 \u82e5\u7528\u8fd9\u4e2a\u74f6\u5b50\u88c5\u5bc6\u5ea6\u4e3a0.8 g/cm3\u7684\u7164\u6cb9\uff0c\u6c42\u6700\u591a\u53ef\u88c5\u591a\u5c11\u5343\u514b\u7684\u7164\u6cb9\u3002
2\u3001\u4e00\u4e2a\u8d28\u91cf\u4e3a232g\u7684\u94dc\u94dd\u5408\u91d1\u7403\uff0c\u5176\u4e2d\u542b\u94dd54g\uff0c\u94dc\u7684\u5bc6\u5ea6\u4e3a\u03c1\u94dc\uff1d8.9 g/cm3\uff0c\u94dd\u7684\u5bc6\u5ea6\u4e3a\u03c1\u94dd\uff1d2.7\u00d7103 kg/m3\uff0c\u6c42\u5408\u91d1\u7403\u7684\u5bc6\u5ea6\u4e3a\u591a\u5c11\uff1f
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A\uff0e\u8d28\u91cf B\uff0e\u4f53\u79ef C\uff0e\u5bc6\u5ea6 D\uff0e\u8868\u9762\u79ef
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声学：1. 在雷雨交加的晚上，某人为了测量打雷处与自己的距离，他手里拿着停表，当他看见闪电时，立即按下停表计时，当他听到雷声时，立即停止计时。一次看见闪电刀听到雷声间隔了5秒40，请问打雷处距他多远？解：5.4×340=1839m
2. 汽车在笔直的公路上做匀速（速度不变）直线运动，速度为v1=20m/s，在汽车正前方L=270m处有一山崖。此时汽车鸣笛，又前进一段路程s听到回声，已知声速为v2=340m/s，求s。
解：已知v1=20m/s，v2=340m/s,L=270m,可求出时间t。
t=2L÷（v1+v2）=2×270÷（20+340）=1.5s
汽车前进的路程s=v1×t=20×1.5=30m
即s=30m
电学：1. 某研究所研究灯丝温度对白炽灯平均使用寿命的影响，做了一个实验。测得灯泡的平均使用寿命与灯丝温度及电流间的关系如下：
灯丝温度：2400K 电流：6.05A 平均使用寿命：8000h
--------：2600K 电流：6.61A ------------：377h
--------：2800K 电流：7.48A ------------：29.5h
--------：3000K 电流：8.34A ------------：3.4h
分析数据可以预测：当钨丝温度在2200K时，其平均使用寿命最接近于（ ）
A. 50h B.500h C. 8000h D. 16000h
解：选D
解析：分析数据，温度越低，灯丝平均使用寿命越长，且变化越明显。当温度由2400K降为2200K时，灯丝平均使用寿命的增加量应大于（8000-377）h，即总平均寿命应大于（8000-377+8000）h。
故选D。
光学要附图，所以没办法啦╮(╯_╰)╭
我做的几道经典就是这些了，其他一些简单的相信你应该会的。
如果还有不会的再问我哈~~
看我打的这么辛苦，给我好啦~~~~都是我自己打的呢！
电学：一个并联电路中，干路上接有一个电流表A1，两个支路上分别有两个小灯泡L1、L2。接在L1处的电流表A2显示电流为0.25A，A1显示电流为0.61A，则接在L2处的电流表A3显示电流为多少？
答案：0.36A。
一个并联电路中，支路A1显示电流为0.9A，A2为0.4A，问干路电流？ 答案：1.3A
你没笔记吗
绛旓細鐢遍鎰忕煡:t澹-t鍏=t,鍥犱负澹伴煶鍦ㄧ┖姘斾腑鐨勪紶鎾熷害鏄340m/s,鍏夊湪绌烘皵涓殑浼犳挱閫熷害鎺ヨ繎3脳10^8m/s,浼犳挱鐩稿悓鐨勮窛绂,鍏夌殑浼犳挱鏃堕棿姣斿０闊崇殑浼犳挱鏃堕棿蹇緱澶,鍗冲厜鐨勪紶鎾椂闂村ぇ澶у皬浜庡０闊崇殑浼犳挱鏃堕棿,鍏夌殑浼犳挱鏃堕棿鍙互蹇界暐涓嶈,寰楀埌t澹=t,鎵浠ユ墦闆峰绂诲皬鐜嬬殑璺濈 s=vt=340m/s脳5s=1700m=1.7km7銆佹湁涓鏉″啺灏佺殑...
绛旓細2锛庤溅闂村畨瑁呯數璺鐢ㄦí鎴潰绉负25mm2鐨勯摐瀵肩嚎8000m锛屽簲璐拱閾滃绾垮灏戝崈鍏?(蟻閾 =8.9脳103 kg / m3 )3锛庝竴涓┖鐡惰川閲忎负200g 锛岃婊℃按鏃舵昏川閲忎负700g锛岃嫢鐢ㄦ潵瑁呭彟涓绉嶆恫浣擄紝瑁呮弧鍚庢昏川閲忔槸600g锛岄壌鍒繖绉嶆恫浣撶殑绉嶇被銆4. 浣撶Н鏄30cm3鐨勯摑鐞冿紝璐ㄩ噺鏄27g锛岃繖涓摑鐞冩槸绌哄績鐨勮繕鏄疄蹇冪殑?绛旀锛...
绛旓細16銆佷竴鍒楃伀杞﹂暱200m锛屼互20m/s鐨勯熷害閫氳繃闀1800m鐨勯搧璺ˉ锛岃繖鍒楃伀杞﹂氳繃澶фˉ鐢ㄤ簡澶氬皯鏃堕棿锛 17銆佹苯杞﹀湪鍑哄巶鍓嶈杩涜娴嬭瘯銆傛煇娆℃祴璇曚腑锛屽厛璁╂苯杞﹀湪妯℃嫙灞辫矾涓婁互8m/s鐨勯熷害琛岄┒500s锛岀揣鎺ョ潃鍦ㄦā鎷熷北璺笂浠20m/s鐨勯熷害琛岄┒100s銆傛眰锛氾紙1锛夎姹借溅鍦ㄦā鎷熶笂璺笂琛岄┒鐨勮矾绋嬶紱锛2锛夋苯杞﹀湪杩欐鏁翠釜娴嬭瘯...
绛旓細绛旀锛1锛岄噾灞炵殑浣撶Н绛変簬涓鍑烘按鐨勪綋绉负V=800-700=100绔嬫柟鍘樼背 閲戝睘鐨勮川閲廙=1200-700=500鍏 瀵嗗害=M/V=5鍏/绔嬫柟鍘樼背 2锛岃M,V M+M姘=32锛孧+M娌=28 M姘-M娌=4 M姘=V*1g/绔嬫柟鍘樼背锛孧娌=V*0.8g/绔嬫柟鍘樼背 M姘-M娌=0.2V=4 V=20绔嬫柟鍘樼背 M=32-M姘=32-V*P=32-20=12g...
绛旓細25銆佷汉浠父鐢ㄢ濆啺灞变竴瑙掓潵褰㈠浜嬬墿鏄鹃湶鍑烘潵鐨勪粎浠呮槸鍏跺緢灏忕殑涓閮ㄥ垎锛屾洿澶氱殑杩橀殣钘忓湪琛ㄩ潰鐜拌薄涔嬩笅銆備簨瀹炰笂锛屽啺灞辨诞鍦ㄦ捣姘翠腑鐨勭‘鍙湶鈥濅竴瑙掆,閭ｄ箞闇插嚭鐨勨滀竴瑙掆濆埌搴曞崰鍐板北澶у皬鐨勫灏戝憿锛熻浣犵敤鐗╃悊鐭ヨ瘑閫氳繃璁＄畻鍜岀畝瑕佺殑鏂囧瓧鍏蜂綋璇存槑銆(宸辩煡P鍐帮紳0.9 脳103kg/m3, P娴锋按锛1.03脳103 kg/m3)26...
绛旓細1銆佹妸閲嶄负200N鐨勭瀛愭惉涓10m楂樼殑妤间笂锛屼汉瀵圭瀛愬仛浜嗗灏戝姛锛2.姹借溅缁忚繃鏌愮珯鏃讹紝涔樺鐨勬墜琛ㄦ寚閽堟寚鍦8鏃32鍒嗭紝鍒拌揪涓嬩竴绔欐椂锛屾墜琛ㄦ寚閽堟寚鍦8鏃36鍒20绉掞紝濡傛灉鍦ㄨ繖娈垫椂闂撮噷锛屾苯杞︾殑閫熷害淇濇寔54鍗冪背锛忓皬鏃讹紝姹傝繖涓ょ珯闂寸殑璺濈鏄灏戝崈绫筹紵3.瀛︽牎缁勭粐鍚屽浠箻杞﹀埌宸ュ巶鍘诲弬瑙傦紝宸ュ巶璺熷鏍″湪鍚屼竴鏉＄瑪鐩寸殑...
绛旓細1锛庢湁涓涓摱瀛愯婊℃补鏃讹紝鎬昏川閲忔槸1.2kg锛岃婊℃按鏃舵昏川閲忔槸1.44kg锛屾按鐨勮川閲忔槸1.2kg锛屾眰娌圭殑瀵嗗害锛2锛庣敳鐗╀綋鐨勮川閲忔槸涔欑墿浣撶殑3鍊嶏紝浣跨敳銆佷箼涓や釜鐗╀綋鐨勪綋绉箣姣3锛2锛屾眰鐢层佷箼涓ょ墿浣撶殑瀵嗗害涔嬫瘮锛3锛庡皬鐡跺唴鐩涙弧姘村悗绉板緱璐ㄩ噺涓210g锛岃嫢鍦ㄧ摱鍐呭厛鏀句竴涓45g鐨勯噾灞炲潡鍚庯紝鍐嶈婊℃按锛岀О寰楃殑璐ㄩ噺...
绛旓細瑙ｏ細T绌=S绌好稸绌=153M梅340M/S=0.45S T閾=T绌-0.42S=0.45S-0.42S=0.03S V閾=S梅T閾=153M梅0.03S=5100M/S 绛旓細澹伴煶鍦ㄩ搧绠′腑浼犳挱閫熷害涓5100绫/绉掋2.涓闂ㄥ弽鍧﹀厠鐐瀯鍑嗕竴杈嗗潶鍏嬶紝寮鐐悗缁忚繃0.6s鐪嬪埌鐐脊鍦ㄥ潶鍏嬩笂鐖嗙偢锛岀粡杩2.1s鍚埌鐖嗙偢鐨勫０闊筹紝姹傚ぇ鐐窛鍧﹀厠澶氬厓锛熺偖寮圭殑椋炶...
绛旓細姹傝嚦灏20閬鍒濅簩涓婄墿鐞瀵嗗害璁＄畻棰銆绛旀涔熻銆傝绠楅涓嶈濉┖,绛旀瑕佽繃绋嬨2涓洖绛 #鐑# 涓轰粈涔堟湁...(鍗虫瘡绔嬫柟绫崇殑娲按鎵鍚偿娌欑殑璐ㄩ噺),娌荤悊鐜涔嬪墠,浠栦滑鍏遍噰闆嗕簡40绔嬫柟鍒嗙背鐨勬按鏍,绉板叾鎬昏川閲忎负40.56
绛旓細5.鍥犱负g鍊兼槸鍦伴潰闄勮繎鐗╀綋鎵鍙楀埌鐨勶紝.鍏跺疄浣犲彲浠ュ弬鐓х墰椤跨殑涓囨湁寮曞姏鍏紡鍏紡鍜屽渾鍛ㄨ繍鍔ㄦ潵璁＄畻锛屼粠鏈堜寒鍜屽湴鐞冪殑鐩镐簰浣滅敤鏉ヨ冭檻锛屽彲浠ョ敤鏈堜寒鐨勫叕杞懆鏈熷弽鎺ㄥ緱鍦扮悆鐨勮川閲忋6璁:姹借溅閫熷害涓篤 閭ｄ箞姹借溅浠嶴1鍒癝2鎵闇鏃堕棿涓:(S1-S2)/V 绌烘皵涓墍浼犳挱鐨勬椂闂翠负:(S1+S2)/340 浜屼釜鏃堕棿鐩稿悓:(S1-S2)/V=(S1+...
