试编写Python程序,根据哥德巴赫猜想一:任何大于6的偶数都可表示为两个素数之和,对100000内的偶数进行验证 C语言编程验证“哥德巴赫猜想”,任何大于2的偶数都是两个素数...
\u9a8c\u8bc1\u54e5\u5fb7\u5df4\u8d6b\u731c\u60f3\uff1a\u4efb\u4f55\u4e00\u4e2a\u5927\u4e8e6\u7684\u5076\u6570\u5747\u53ef\u8868\u793a\u4e3a\u4e24\u4e2a\u7d20\u6570\u4e4b\u548c\u3002\u8bf7\u7528C\u7a0b\u5e8f\u7f16\u5199#include
#include
int prime(int m)
{
int i,n;
if(m==1)return 0;
n=(int)sqrt((double)m);
for(i=2;i<=n;i++)
if(m%i==0)return 0;
return 1;
}
void main()
{
int count,i,number;
count=0;
for(number=6;number<=20;number=number+2)
{
for(i=3;i<=number/2;i=i+2)
if(prime(i)&&prime(number-i))
{
printf("%d=%d+%d ",number,i,number-i);
count++;
if( count%5==0 )printf("\n");
continue;
}
}
}
#coding=utf-8
import sys,time
from math import sqrt
def isprime(num):
for i in range(2,int(sqrt(num))+1):
if num%i==0:
return False
return True
def gedebahe(num):
for i in range(2,num//2+1):
if isprime(i) and isprime(num-i):
return True
return Falsese
def main(n):
for i in range(6,n+1,2):
if not gedebahe(i,L):
print('fail at number {}'.format(i))
break
else:
tip='success: all evens in {} can be the sum of two primes.'
print(tip.format(n))
if __name__=='__main__':
start=time.time()
n=100000
if len(sys.argv)>1:
n=int(sys.argv[1])
main(n)
end=time.time()
print('cost {} seconds'.format(end-start))
[willie@bogon pys]$ python gedebahe.py
success: all evens in 100000 can be the sum of two primes.
cost 24.8260421753 seconds
#coding=utf-8
import sys,time
from math import sqrt
def primes(n):
# prepair data space
plist = [0, 0] + list(range(2,n+1))
for i in range(2, int(sqrt(n))+1):
if plist[i]:
plist[i+i::i] = [0] * len(plist[i+i::i])
return filter(None, plist)
def gedebahe(n,L):
for i in L:
if (n-i) in L:
return True
elif i>n//2+1:
return False
def main(n):
L=list(primes(n))
for i in range(6,n+1,2):
if not gedebahe(i,L):
print('fail at number {}'.format(i))
break
else:
tip='success: all evens in {} can be the sum of two primes.'
print(tip.format(n))
if __name__=='__main__':
start=time.time()
n=100000
if len(sys.argv)>1:
n=int(sys.argv[1])
main(n)
end=time.time()
print('cost {} seconds'.format(end-start))
[willie@bogon pys]$ python gedebahe.py
success: all evens in 100000 can be the sum of two primes.
cost 70.5533659458 seconds
# -*- coding: utf-8 -*-
"""
Created on Thu Apr 5 01:14:35 2018
@author: pandeer
# Any question if you have ,pls contact my WeChat：yangpan4997
"""
list = []
def isPrise(n):
#验证输入的数值是否符合要求，即：是否为大于6的偶数，否则重新输入
while n <= 6 or (n % 2 != 0 and n > 6):
n = int(input("输入错误，请重新输入,输入值必须大于6的偶数:"))
#输出所有的n以内的质数，并将所有的质数存储于list[]列表中等待处理
for j in range(2,n+1):
for i in range(2, j):
if j % i == 0:
break
else:
print(j,'是一个质数')
list.append(j)
# 输出所有的质数列表，仅做最终表的列出，故做判定语句处理
if j == n - 1:
print(list)
#对列表中的质数进行进行计算，若存在两个质数的和等于输入的偶数n，则输出这两个质数
#为避免出现A+B与B+A(质数相加）的等价情况，增加list[i] > list[j]语句进行过滤
for i in range(len(list)) :
for j in range(len(list)) :
if list[i] + list[j] == n and list[i] > list[j]:
print ("偶数%d等于两个质数的和："%n,list[i],'+',list[j])
n = isPrise(int(input("请输入大于等于6的偶数:")))
绛旓細': start=time.time() n=100000 if len(sys.argv)>1: n=int(sys.argv[1]) main(n) end=time.time() print('cost {} seconds'.format(end-start))[willie@bogon pys]$ python gedebahe.pysuccess: all evens in 100000 can be the sum of two primes.cost 24....
绛旓細success: all evens in 100000 is the sum of two primes consum time: 16.739 seconds usr/bin/env python3import sysimport timefrom math import sqrtfrom threading import Threadisprime=lambda p: all([p%d for d in range(2,int(sqrt(p))+1)])def sum_of_two_evens(num): for ...
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