因式分解题。初二数学。5道。谢谢

\u521d\u4e8c\u6570\u5b66\u56e0\u5f0f\u5206\u89e3\u9898

1. \u6839\u636e\u56e0\u5f0f\u5206\u89e3\u7684\u6982\u5ff5\uff0c\u5224\u65ad\u4e0b\u5217\u5404\u7b49\u5f0f\u54ea\u4e9b\u662f\u56e0\u5f0f\u5206\u89e3\uff0c\u54ea\u4e9b\u4e0d\u662f\uff0c\u4e3a\u4ec0\u4e48\uff1f
\uff081\uff096abxy=2ab•3xy;
\uff082\uff09
\uff083\uff09\uff082x-1\uff09•2=4x-2
\uff084\uff094x2-4x+1=4x\uff08x-1\uff09+1.
2. \u586b\u7a7a
\uff081\uff09\uff082m+n\uff09\uff082m-n\uff09=4m2-n2\u6b64\u8fd0\u7b97\u5c5e\u4e8e \u3002
\uff082\uff09x2-2x+1=\uff08x-1\uff092\u6b64\u8fd0\u7b97\u5c5e\u4e8e \u3002
\uff083\uff09\u914d\u5b8c\u5168\u5e73\u65b9\u5f0f 49x2+y2+ =\uff08 -y\uff092
2. \u8ba1\u7b97\u4e0b\u5217\u5404\u5f0f\uff1a
\uff081\uff09\uff08m+4\uff09\uff08m-4\uff09= ;
\uff082\uff09\uff08y-3\uff092= \uff1b
\uff083\uff093x\uff08x-1\uff09= \uff1b
\uff084\uff09m\uff08a+b+c\uff09= .
\u6839\u636e\u4e0a\u9762\u7684\u7b97\u5f0f\u586b\u7a7a\uff1a
\uff081\uff093x2-3x=\uff08 \uff09\uff08 \uff09
\uff082\uff09m2-16=\uff08 \uff09\uff08 \uff09
\uff083\uff09ma+mb+mc=\uff08 \uff09\uff08 \uff09
\uff084\uff09y2-6y+9=\uff08 \uff09\uff08 \uff09
3. \u5c06\u4e0b\u5217\u5404\u5f0f\u5206\u89e3\u56e0\u5f0f\uff1a
3x+6\uff1b 7x2-21x\uff1b 8a3b2-12ab3c+abc\uff1b a\uff08x-3\uff09+2b\uff08x-3\uff09\uff1b 5\uff08x-y\uff093+10\uff08y-x\uff092\u3002
\u7b54\u6848\uff1a\uff081\uff093x+6=3x+3\u00d72=3\uff08x+2\uff09 \uff082\uff097x2-21x=7x•x-7x•3=7x\uff08x-3\uff09
\uff083\uff098a3b2-12ab3c+abc=ab•8a2b-ab•12b2c+ab•c=ab\uff088a2b-12b2c+c\uff09
\uff084\uff09a\uff08x-3\uff09+2b\uff08x-3\uff09=\uff08x-3\uff09\uff08a+2b\uff09
\uff085\uff095\uff08x-y\uff093+10\uff08y-x\uff092=5\uff08x-y\uff093+10[-\uff08x-y\uff09]2=5\uff08x-y\uff093+10\uff08x-y\uff092=5\uff08x-y\uff092\uff08x-y+2\uff09
4. \u628a\u4e0b\u5217\u5404\u5f0f\u5206\u89e3\u56e0\u5f0f\uff1a
\uff081\uff093x2-6xy+x \uff082\uff09-4m3+16m2-26m
6. \u628a\u4e0b\u5217\u5404\u5f0f\u5206\u89e3\u56e0\u5f0f\uff1a
\uff081\uff09 4q\uff081-p\uff093+2\uff08p-1\uff092
\uff082\uff09 3m\uff08x-y\uff09-n\uff08y-x\uff09
\uff083\uff09 m\uff085ax+ay-1\uff09-m\uff083ax-ay-1\uff09

\uff081\uff09x²-4xy+4y²-10x+20y+25
=x²-2\u00d72xy+\uff082y\uff09²-\uff0810x-20y\uff09+25
=(x-2y)²-2\u00d75\uff08x-2y)+5²
=(x-2y-5)²
(2)(n+1)(n+2)(n+3)(n+4)+1
=(n+1)(n+4)(n+2)(n+3)+1
=(n²+5n+4)(n²+5n+6)+1
=[\uff08n²+5n\uff09+4][(n²+5n)+6]
=(n²+5n)²+2\u00d75(n²+5n)+24+1
=(n²+5n)²+2\u00d75(n²+5n)+5²
=(n²+5n+5)²



(1)原式=xy(x-1)
(2)原式=(x-y)(a²-16)
=(x-y)(a+4)(a-4)
(3)原式=(-x²+y²+2xy)(-x²+y²-2xy)
(4) 原式=(x+2y+y)(x+2y-y)
=(x+3y)(x+y)
(5)原式=2a(m²-4)
=2a(m+2)(m-2)



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