物理题求解“五一”假期，小明一家驱车外出旅游．当汽车以108km/h的速度在高速公路上匀速直线行驶时，汽
\u201c\u4e94\u4e00\u201d\u5047\u671f\uff0c\u5c0f\u660e\u4e00\u5bb6\u9a71\u8f66\u5916\u51fa\u65c5\u6e38\uff0e\u5f53\u6c7d\u8f66\u4ee5108km/h\u7684\u901f\u5ea6\u5728\u9ad8\u901f\u516c\u8def\u4e0a\u5300\u901f\u76f4\u7ebf\u884c\u9a76\u65f6\uff0c\u6c7d\u8f66\u53d7\u5230\u7684\u963b\uff081\uff09\u2235m=1375kg\uff0cg=10N/kg\uff0c\u2234\u7269\u4f53\u7684\u91cd\u529b\u4e3a\uff1aG=mg=1375kg\u00d710N/kg=13750N\uff0c\u6c7d\u8f66\u53d7\u5230\u7684\u963b\u529b\u662f\u6574\u8f66\u91cd\u76840.08\u500d\uff0c\u5373f=0.08G=0.08\u00d713750N=1100N\uff0c\u2235\u6c7d\u8f66\u505a\u5300\u901f\u8fd0\u52a8\uff0c\u5219F=f=1100N\uff0c\u2235v=108km/h=30m/s\uff0c\u2234\u6c7d\u8f66\u7275\u5f15\u529b\u505a\u529f\u7684\u529f\u7387\u4e3a\uff1aP=Wt=Fst=Fv=1100N\u00d730m/s=33000W\uff0e\uff082\uff09\u2235v=50L\uff0cq=3.3\u00d7107J/L\uff0c\u2234\u6c7d\u6cb9\u5b8c\u5168\u71c3\u70e7\u653e\u51fa\u7684\u70ed\u91cf\u4e3a\uff1aQ\u653e=qv=3.3\u00d7107J/L\u00d750L=1.65\u00d7109J\uff0c\u800c\u6c7d\u8f66\u7684\u6548\u7387\u4e3a4O%\uff0c\u800cW\u603b=Q\u653e=1.65\u00d7109J\uff0c\u2234\u7275\u5f15\u529b\u505a\u7684\u6709\u7528\u529f\u4e3a\uff1aW\u6709\u7528=\u03b7W\u603b=40%\u00d71.65\u00d7109J=6.6\u00d7108J\uff0c\u6c7d\u8f66\u884c\u9a76\u7684\u8def\u7a0b\u4e3a\uff1as=W\u6709\u7528F=6.6\u00d7108J1100N=6\u00d7105m\uff0e\u7b54\uff1a\uff081\uff09\u8fd9\u65f6\u6c7d\u8f66\u7275\u5f15\u529b\u505a\u529f\u7684\u529f\u7387\u662f33000W\uff0e\uff082\uff09\u8be5\u8f66\u52a0\u4e00\u6ee1\u7bb1\u6c7d\u6cb9\uff0c\u6309\u7167\u4ee5\u4e0a\u901f\u5ea6\u5300\u901f\u76f4\u7ebf\u884c\u9a76\u6700\u8fdc\u901a\u8fc7\u7684\u8def\u7a0b\u4e3a6\u00d7105m\uff0e
1\u3001\u56e0\u4e3a\u6c7d\u8f66\u5300\u901f\u884c\u9a76\uff0c\u6240\u4ee5\u6c7d\u8f66\u5728\u6c34\u5e73\u65b9\u5411\u53d7\u5e73\u8861\u529b\u7684\u4f5c\u7528\uff0c\u5373F\u7275\u5f15=f\u963b=0.08X1375X10=1100N
V=108km/h=30m/S
P=FV=1100X30=33000W=33KW
2\u3001Q\u653e=qm=3.3X10^7X50=1.65X10^9J
\u56e0\u4e3an=W/Q
\u6240\u4ee5W=nQ=1.65X10^9X40%=6.6X10^8J
\u800cW=FS
\u6240\u4ee5S=W/F=6.6X10^8/1100=6X10^5m=600km
108KM/H转换单位后是108*1000m/3600s=30m/s
而功率P=F*v=1085.6 N*30m/s=32 568W;
2)我查过汽油热值；你题目有误；汽油热值应该为3.3*(10^7)才合理；
总热量W=3.3*(10^7)J/L*50L=1 650 000 000J;因为效率是40%。所以有用功为W*40%=660000000=6.6*(10^8)J;因为W=Pt可得t=W/P=(6.6*10^8)J/(32568)W=20265.29108327(s);
S=V*t=30m/s*20265.29108327s=607958.7324980999m
大约等于608KM
绛旓細鍥炵瓟锛1)鍖閫熺洿绾胯繍鍔ㄥ氨璇存槑鐗靛紩鍔涚瓑浜庨樆鍔,鐗靛紩鍔汧=1357*0.08N*g=1085.6N; 108KM/H杞崲鍗曚綅鍚庢槸108*1000m/3600s=30m/s 鑰屽姛鐜嘝=F*v=1085.6 N*30m/s=32 568W; 2)鎴戞煡杩囨苯娌圭儹鍊;浣棰樼洰鏈夎;姹芥补鐑煎簲璇ヤ负3.3*(10^7)鎵嶅悎鐞; 鎬荤儹閲廤=3.3*(10^7)J/L*50L=1 650 000 000J;鍥犱负鏁...
绛旓細108km/h=30m/s F=f=0.08mg=0.08*1375*10=1100N P=FV=1100*30=33000W=33kW 姹芥补瀵嗗害 Q=qm1=3.3脳 107*50L*0.71kg/L=1.175脳 10^9J 40%Q=Pt 1.175脳 10^9J*0.4=33000t t=14200s S=Vt=30*14200=426000m
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