C语言,从键盘输入一个正整数,判断它的奇偶性,在线等,急! 在文本框中输入任意一个正整数,判断奇偶性,vb编程的

C\u8bed\u8a00\u9898 \u8f93\u5165\u4e00\u4e2a\u6b63\u6574\u6570\uff0c\u5224\u65ad\u5176\u5947\u5076\u6027\u5e76\u8f93\u51fa \u5e0c\u671b\u5199\u4e0b\u7a0b\u5e8f \u975e\u5e38\u611f\u8c22

#include int main(){ int i; scanf("%d",&i);//\u8f93\u5165 if(i%2==0)printf("\u5076\u6570\n"); else printf("\u5947\u6570\n"); return 0; }

\u80fd\u88ab2\u6574\u9664\u7684\u662f\u5076\u6570..\u5176\u4ed6\u4e3a\u5947\u6570

\u4f7f\u7528mod\u51fd\u6570\u5224\u65ad\u662f\u5426\u80fd\u591f\u88ab\u6574\u9664\u5c31\u884c\u4e86..mod\u51fd\u6570 \u53d6\u4f59\u6570 \u4f59\u6570\u5927\u4e8e0 \u4e0d\u80fd\u88ab\u6574\u9664.\u7b49\u4e8e0 \u80fd\u88ab\u6574\u9664

if (3 mod 2) >0 then
msgbox "\u5947\u6570"

else
msgbox "\u5076\u6570"

end if

#include "stdio.h"
void main()
{
int n;
printf("请输入一个整数\n");
scanf("%d",&n);
if(n%2==0)
printf("n为偶数!");
else
printf("n为奇数!");
}

#include<stdio.h>
int main()
{
int n;
scanf("%d",&n);
if(n%2==0)
printf("n为偶数.");
else
printf("n为奇数.");
return 0;
}

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