因式分解的题目，大哥大姐帮帮！急
\u56e0\u5f0f\u5206\u89e3\u3001\u9898\u76ee......\u5927\u54e5\u5927\u59d0 \u5e2e\u5e2e\u5fd9\u554a\uff01\uff01\uff01\uff01\uff01\uff01\uff01\uff011.x\uff08x²-9\uff09=x\uff08x+3\uff09\uff08x-3\uff09
2.\uff084x²+1\uff09\uff084x²-1\uff09=\uff084x²+1\uff09\uff082x+1\uff09\uff082x-1\uff09
3.-y\uff089x²-6xy+y²\uff09=-y\uff083x-y\uff09²
4.\u7b2c\u56db\u9898\u662f\u4e0d\u662f\u9519\u4e86\uff0c\u6211\u6309\uff082a-b\uff09²+8ab=4a²+4ab+b²=\uff082a+b\uff09²
x^5-x^2
=x^2(x^3-1)
=x^2(x-1)(x^2+x+1)
(x-1)(x-2)(x-4)(x-8)-270x^2
=(x-1)(x-8)(x-2)(x-4)-270x^2
=(x²-9x+8)(x²-6x+8)-270x²
=(x²+8-9x)(x²+8-6x)-270x²
=(x²+8)²-15x(x²+8)+54x²-270x²
=(x²+8)²-15x(x²+8)-216x²
=[(x²+8)-24x][(x²+8)+9x]
=(x²-24x+8)(x²+9x+8)
=(x²-24x+8)(x+8)(x+1)
x(x+z)-y(y+z)
=x²+xz-y²-yz
=x²-y²+xz-yz
=(x-y)(x+y)+(x-y)z
=(x-y)(x+y+z)
2x^4+3x^3-6x^2-3x+2
2x^4+3x^3-6x^2-3x+2=0\u76844\u4e2a\u89e3\u5206\u5e03\u5728(-3,-2)(-1,-1/2)(0,1/2)(1,2)\u4e4b\u95f4\u65e0\u6574\u6570\u89e3\uff0c\u6545\u56e0\u5f0f\u5206\u89e3\u4e0d\u884c\uff01\u53ef\u80fd\u9898\u6284\u7684\u4e0d\u592a\u5bf9
\u5df2\u77e5x+y=m,x^3+y^3=n,m\u22600\uff0c\u6c42m^2+y^2\u7684\u503c
\u53ef\u77e5\u9053
x²+xy+y²=n/m ,
xy=(x+y)²-(x²+xy+y²)=m²-n/m,
x²+y²=(x+y)²-2xy=2n/m-m²
=(x^2+2x-8)(x^2+2x+1)
=(x+4)(x-2)(x+1)^2
ac-4a-4c+16
=(a-4)(c-4)
x^2+4x+4y^2-12y+13=0
(x+2)^2+(2y-3)^2=0
完全平方数都是大于等于0的
x+2=0,2y-3=0
x=-2,y=3/2
1,=[(x^+2x)-8][(x^+2x)+1]
=(x+4)(x-2)(x+1)^
2,ac-4a-4c+16
=(a-4)(c-4)
3,=(x+2)^+(2y-3)^=0
x+2=2y-3=0
x=-2,y=3/2
绛旓細=(x^2+2x-8)(x^2+2x+1)=(x+4)(x-2)(x+1)^2 ac-4a-4c+16 =(a-4)(c-4)x^2+4x+4y^2-12y+13=0 (x+2)^2+(2y-3)^2=0 瀹屽叏骞虫柟鏁伴兘鏄ぇ浜庣瓑浜0鐨 x+2=0,2y-3=0 x=-2,y=3/2
绛旓細锛1锛32a鐨勪笁娆℃柟-50ab鐨勫钩鏂 =2a(16a^2-25b^2)=2a(4a+5b)(4a-5b)锛2锛変節鍒嗕箣m鐨勫钩鏂-浜岀櫨浜斿崄鍏垎涔媙鐨勫洓娆℃柟 =(1/3m)^2-(1/16n^2)^2 =(1/3m+1/16n^2)(1/3m-1/16n^2)锛3锛4-x鐨2n娆℃柟 =(2+x^n)(2-x^n)(4)(a+b)鐨勫钩鏂-1 =(a+b+1)(a+b-1)锛5...
绛旓細1.鍋舵暟 濂囨暟 2.鍚堟暟 锛3a-4b锛壝楋紙7a-8b锛夛紜锛11a-12b锛壝楋紙8b-7a锛=锛3a-4b锛壝楋紙7a-8b锛-锛11a-12b锛壝楋紙7a-8b)=(3a-4b-11a+12b)脳(7a-8b锛=(8b-8a)脳(7a-8b)=8(b-a)脳(7a-8b)=-48
绛旓細1 銆 x³锛峹y²锛2xy锛峹 =x(x²-y²+2y-1)=x[x²-(y-1)²]=x(x+y-1)(x-y+1)2 x²锛峛x锛峚²锛媋b = (x+a)(x-a)-b(x-a)=(x-a)(x+a-b)3 x²锛4y²锛3x锛6y =(x+2y)(x-2y)-2(x-2y)=(x-2y)(x...
绛旓細1銆3-6x+3x鐨勫钩鏂 =3-3x-3x+3x^2 =3(1-x)+3x(1-x)=3(1-x)(1+x)=3(1-x^2)2銆乤+2a鐨勫钩鏂-a鐨3娆℃柟 =-a(a^2-2a+1)+2a =-a(a-1)^2+2a =-a[(a-1)^2-2]3銆乤鐨勫钩鏂癸紙2a-3锛+b鐨勫钩鏂癸紙3-2a锛=a^2(2a-3)-b^2(2a-3)=(2a-3)(a^2-b^2)=(2a-3)...
绛旓細(x-2)^2-x+2 =(x-2)^2-(x-2)=(x-2)(x-2-1)=(x-2)(x-3)x^3-x^2-x+1 =(x^3-x^2)-(x-1)=x^2(x-1)-(x-1)=(x-1)(x^2-1)=(x-1)^2(x+1)(a-2)^2-6(2-a)=(a-2)^2+6(a-2)=(a-2)(a-2+6)=(a-2)(a+4)鍏跺疄鍥犲紡鍒嗚В鍙澶氱粌缁冨氨濂藉挴...
绛旓細=(n-m)(-n-2m)2.3^2007-5*3^2006+6*3^2005 =9*3^2005-15*3^2005+6*3^2005 =(9+6-15)*3^2005 =0 3.6x^3y(x-y)^3-4xy^3(y-x)^2 =6x^3y(x-y)^3-4xy^3(x-y)^2 =2xy(x-y)^2[3x^2(x-y)-2y^2]=2xy(x-y)^2(3x^3-3x^2y-2y^2)4.(x-y)^4+x(...
绛旓細=(a-1)^2(a-1+鏍瑰彿2锛夛紙a+1-鏍瑰彿2锛夆憽(1-xy)^2+(x+y-2)(x+y-2xy)=1-2xy+x^2y^2+(x+y)^2-2(1+xy)(x+y)+4xy =1+2xy+x^2y^2+(x+y)^2-2(1+xy)(x+y)=(1+xy)^2+(x+y)^2-2(1+xy)(x+y)=(1+xy-x-y)^2 =(1-x)^2(1-y)^2 鈶㈡眰[(a^2+b...
绛旓細瑙ｏ細1. 169(a--b)^2--196(a+b)^2=[13(a--b)+14(a+b)][13(a--b)--14(a+b)]=(27a--b)(--a--27b)=(b--27a)(a+27b).2. 4--12(x+y)+9(x+y)^2=[2--3(x+y)]^2 =(2--3x--3y)^2.3. a^3+8b^3=(a+2b)(a^2--2ab+4b^2).4. 1-...
绛旓細a-b)(2x+3y-4z)(2a+b)(2a-3b)+a(2a+b)=(2a+b)(2a-3b+a)=(2a+b)(3a-3b)=3(2a+b)(a-b)6(x-y)^3+15(y-x)^2-9(y-x)^3 =6(x-y)^3+15(x-y)^2+9(x-y)^3 =(x-y)^2(6x-6y+15+9x-9y)=(x-y)(x+y)(15x-15y+15)=15(x+y)(x-y)(x-y+1)...
