求教编写一个C语言函数求出两个字符串包含的相同的单词 如何用C语言编写一个程序，统计输入字符串的相同单词个数 ?
c\u8bed\u8a00\u7edf\u8ba1\u4e24\u4e2a\u5b57\u7b26\u4e32\u4e2d\u76f8\u540c\u7684\u5355\u8bcd\u7684\u6570\u91cf
\u5982\u56fe\uff0c\u53ea\u6709\u4e00\u4e2a\u76f8\u540c\u5355\u8bcd
\u5f88\u7b80\u5355\u4e86\uff0c\u4ee3\u7801\u5982\u4e0b\uff1a#include <stdio.hvoid main(){char a[100];int i,count=0,flag=1,n=0;gets(a);//\u4ece\u952e\u76d8\u8f93\u5165\u5b57\u7b26\u4e32for(i=0;a[i];i++){if((a[i]='a' && a[i]<='z') || (a[i]='A' && a[i]<='Z'))//\u5224\u65ad\u662f\u4e0d\u662f\u5b57\u7b26{flag=0;//\u8bbe\u7f6e\u5b57\u7b26\u6807\u5fd7continue;//\u8fd4\u56de\u4e0b\u4e00\u4e2a\u5faa\u73af}if(!flag)//\u524d\u9762\u4e00\u4f4d\u662f\u5b57\u7b26\uff0c\u5373\u5f53\u524d\u662f\u67d0\u4e2a\u5355\u8bcd\u5b57\u7b26\u7ed3\u675f{count++;//\u7edf\u8ba1\u5355\u8bcd\u4e2a\u6570flag=1;//\u8bbe\u7f6e\u975e\u5b57\u7b26\u6807\u5fd7}}i--;if((a[i]='a' && a[i]<='z') || (a[i]='A' && a[i]<='Z'))count++;//\u589e\u52a0\u5b57\u7b26\u4e32\u7ed3\u675f\u7684\u5355\u8bcd
#include <stdio.h>
char *maxword(char*s, char*t)
{
int wordlen=0,maxlen = 0;
char *pt = t, *ps = s, *res = s;
while (*s != '\0')
{
while (*s == ' ')s++;
ps = s;
while (*s != ' '&&*s != '\0')//找到一个单词
s++;
wordlen = s - ps;//获取单词长度
while (*pt != '\0')//在t中找到s中当前单词相同的首字母
{
while (*pt == ' ')pt++;
if (*ps == *pt)
{
//找到首字母
s = ps;
while (*pt == *s&&*s != ' '&&*s!='\0')//找t中与当前单词相同的单词
{
s++; pt++;
}
if (*s != ' '&&*s != '\0') //没有找到对应的单词,t中不是一个完整的单词也不算找到,s长了
continue;
else if (*pt != ' '&&*pt != '\0')
{
while (*pt != ' ')pt++;
continue;//跳转找t的下一个单词的首字母
}
else if (wordlen > maxlen)//找到对应的单词了,与之前找到的单词对比长度，大于则记录，小于则过；
{
res = ps;
maxlen = wordlen;
pt = t;
break;
}
else
pt = t;
break;
}
while (*pt != ' '&&*pt!='\0')
pt++;
}
continue;
}
if (maxlen == 0)
return 0;
else
{
res[maxlen] = '\0';
return res;
}
}
int main()
{
char s[] = "text This is C Programmingg";
char t[] = "This is a Programmin text for C Programming ";
char *word = maxword(s, t);
printf("%s", word);
getchar();
return 0;
}
因为你的p,q两个指针数组的成员都没有申请内存，却在下面进行了访问（如p[m][j]=0; q[n][k]=0;）
修正方式，给p,q成员申请内存，将char *p[81],*q[81];语句修改为如下：
#define MAX_SIZE 81
#define BUF_SIZE 64
char *p[MAX_SIZE],*q[MAX_SIZE];
int temp = 0;
for (temp = 0; temp < MAX_SIZE; ++temp)
{
p[temp] = malloc(BUF_SIZE);
q[temp] = malloc(BUF_SIZE);
}
函数末尾记得进行遍历释放它们成员的堆内存。
#include<stdio.h>
#include<string.h>
void maxword(char *s,char *t)
{
int i,j=0,m=0;
char p[20][30]= {0};
for(i=0; s[i]!='\0'; i++)
{
if(s[i]!=' ')
p[m][j++]=s[i];
else
{ p[m][j]='\0';
m++;
j=0;
}}
for(i=0; i<m; i++) {
if(strstr(t,p[i])!=NULL) {
printf("the same word:%s\n",p[i]);
}}}
void main()
{
char s[]="This is C programming text ";
char t[]="This is a text for C programming";
maxword(s,t);
}
这个我运行出来是对的 你那个好像strstr函数参数用反了
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