如何求解关于x的方程
用tan²x=sec²x-1降幂，再利用sec²xdx=dtanx，具体如下∫tanx^6dx=∫(tanx)^4·(sec²-1)dx=∫(tanx)^4 dtanx-∫(tanx)^4 dx
=∫(tanx)^4 dtanx-∫tan²x(sec²x-1)dx=∫(tanx)^4 dtanx-∫tan²x dtanx+∫tan²xdx
=∫(tanx)^4 dtanx-∫tan²x dtanx+∫sec²x dx-∫dx
=1/5(tanx)^5-1/3tan³x+tanx-x+C
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