16平方的铜线有多粗，我的意思是，假设铜线是单根，不计外皮的情况下，怎么计算， 16平方的电线大概是多粗
16\u5e73\u65b9\u6beb\u7c73\u7684\u7535\u7ebf\u591a\u7c97\u600e\u4e48\u7b9716\u5e73\u65b9\u6beb\u7c73\u7684\u7535\u7ebf\u76f4\u5f844.51466\u6beb\u7c73\u3002
\u8ba1\u7b97\u65b9\u6cd5\u5982\u4e0b\uff1a
\u7535\u7ebf\u622a\u9762\u4e00\u822c\u90fd\u662f\u5706\u3002
\u5706\u7684\u9762\u79ef=\u03c0r²=0.25\u03c0d²\uff08\u03c0\u662f\u5706\u5468\u7387\uff0cr\u662f\u5706\u7684\u534a\u5f84\uff0cd\u662f\u5706\u7684\u76f4\u5f84\uff09
16=0.25\u00d73.14\u00d7d²
d²=16\u00f70.25\u00f73.14
d=\u221a\uff0816\u00f70.25\u00f73.14\uff09=4.51466\uff08\u6beb\u7c73\uff09
\u6269\u5c55\u8d44\u6599\uff1a
\u5bfc\u7ebf\u622a\u9762\u90fd\u662f\u5706\uff0c\u5706\u7684\u9762\u79ef=\u03c0r²=0.25\u03c0d²\uff08\u03c0\u662f\u5706\u5468\u7387\uff0cr\u662f\u5706\u7684\u534a\u5f84\uff0cd\u662f\u5706\u7684\u76f4\u5f84\uff09
\u5728\u4e00\u4e2a\u5e73\u9762\u5185\uff0c\u4e00\u52a8\u70b9\u4ee5\u4e00\u5b9a\u70b9\u4e3a\u4e2d\u5fc3\uff0c\u4ee5\u4e00\u5b9a\u957f\u5ea6\u4e3a\u8ddd\u79bb\u65cb\u8f6c\u4e00\u5468\u6240\u5f62\u6210\u7684\u5c01\u95ed\u66f2\u7ebf\u53eb\u505a\u5706\u3002\u5706\u6709\u65e0\u6570\u6761\u5bf9\u79f0\u8f74\u3002
\u5728\u540c\u4e00\u5e73\u9762\u5185\uff0c\u5230\u5b9a\u70b9\u7684\u8ddd\u79bb\u7b49\u4e8e\u5b9a\u957f\u7684\u70b9\u7684\u96c6\u5408\u53eb\u505a\u5706\u3002\u5706\u53ef\u4ee5\u8868\u793a\u4e3a\u96c6\u5408{M||MO|=r},\u5706\u7684\u6807\u51c6\u65b9\u7a0b\u662f(x - a) ² + (y - b) ² = r ²\u3002\u5176\u4e2d\uff0cO\u662f\u5706\u5fc3\uff0cr \u662f\u534a\u5f84\u3002
\u5706\u5f62\u662f\u4e00\u79cd\u5706\u9525\u66f2\u7ebf\uff0c\u7531\u5e73\u884c\u4e8e\u5706\u9525\u5e95\u9762\u7684\u5e73\u9762\u622a\u5706\u9525\u5f97\u5230\u3002
\u5706\u662f\u4e00\u79cd\u51e0\u4f55\u56fe\u5f62\u3002\u6839\u636e\u5b9a\u4e49\uff0c\u901a\u5e38\u7528\u5706\u89c4\u6765\u753b\u5706\u3002 \u540c\u5706\u5185\u5706\u7684\u76f4\u5f84\u3001\u534a\u5f84\u957f\u5ea6\u6c38\u8fdc\u76f8\u540c\uff0c\u5706\u6709\u65e0\u6570\u6761\u534a\u5f84\u548c\u65e0\u6570\u6761\u76f4\u5f84\u3002\u5706\u662f\u8f74\u5bf9\u79f0\u3001\u4e2d\u5fc3\u5bf9\u79f0\u56fe\u5f62\u3002\u5bf9\u79f0\u8f74\u662f\u76f4\u5f84\u6240\u5728\u7684\u76f4\u7ebf\u3002 \u540c\u65f6\uff0c\u5706\u53c8\u662f\u201c\u6b63\u65e0\u9650\u591a\u8fb9\u5f62\u201d\uff0c\u800c\u201c\u65e0\u9650\u201d\u53ea\u662f\u4e00\u4e2a\u6982\u5ff5\u3002\u5f53\u591a\u8fb9\u5f62\u7684\u8fb9\u6570\u8d8a\u591a\u65f6\uff0c\u5176\u5f62\u72b6\u3001\u5468\u957f\u3001\u9762\u79ef\u5c31\u90fd\u8d8a\u63a5\u8fd1\u4e8e\u5706\u3002\u6240\u4ee5\uff0c\u4e16\u754c\u4e0a\u6ca1\u6709\u771f\u6b63\u7684\u5706\uff0c\u5706\u5b9e\u9645\u4e0a\u53ea\u662f\u6982\u5ff5\u6027\u7684\u56fe\u5f62\u3002
\u5706\u5468\u957f\uff08c\uff09\uff1a\u5706\u7684\u76f4\u5f84\uff08D\uff09\uff0c\u90a3\u5706\u7684\u5468\u957f\uff08c\uff09\u9664\u4ee5\u5706\u7684\u76f4\u5f84\uff08D\uff09\u7b49\u4e8e\u03c0\uff0c\u90a3\u5229\u7528\u4e58\u6cd5\u7684\u610f\u4e49\uff0c\u5c31\u7b49\u4e8e \u03c0\u4e58\u5706\u7684\u76f4\u5f84\uff08D\uff09\u7b49\u4e8e\u5706\u7684\u5468\u957f\uff08C\uff09\uff0cC=\u03c0d\u3002\u800c\u540c\u5706\u7684\u76f4\u5f84\uff08D\uff09\u662f\u5706\u7684\u534a\u5f84\uff08r\uff09\u7684\u4e24\u500d\uff0c\u6240\u4ee5\u5c31\u5706\u7684\u5468\u957f\uff08c\uff09\u7b49\u4e8e2\u4e58\u4ee5\u03c0\u4e58\u4ee5\u5706\u7684\u534a\u5f84\uff08r\uff09\uff0cC=2\u03c0r\u3002
\u628a\u5706\u5e73\u5747\u5206\u6210\u82e5\u5e72\u4efd\uff0c\u53ef\u4ee5\u62fc\u6210\u4e00\u4e2a\u8fd1\u4f3c\u7684\u957f\u65b9\u5f62\u3002\u957f\u65b9\u5f62\u7684\u5bbd\u5c31\u7b49\u4e8e\u5706\u7684\u534a\u5f84\uff08r\uff09\uff0c\u957f\u65b9\u5f62\u7684\u957f\u5c31\u662f\u5706\u5468\u957f\uff08C\uff09\u7684\u4e00\u534a\u3002\u957f\u65b9\u5f62\u7684\u9762\u79ef\u662fab\uff0c\u90a3\u5706\u7684\u9762\u79ef\u5c31\u662f\uff1a\u5706\u7684\u534a\u5f84\uff08r\uff09\u7684\u5e73\u65b9\u4e58\u4ee5\u03c0\uff0cS=\u03c0r²=0.25\u03c0d²
\u53c2\u8003\u8d44\u6599\u6765\u6e90\uff1a\u767e\u5ea6\u767e\u79d1-\u5706
\u53c2\u8003\u8d44\u6599\u6765\u6e90\uff1a\u767e\u5ea6\u767e\u79d1-\u5706\u7684\u9762\u79ef
16\u5e73\u65b9\u6beb\u7c73\u7684\u7535\u7ebf\u76f4\u5f844.51466\u6beb\u7c73\u3002
\u8ba1\u7b97\u65b9\u6cd5\u5982\u4e0b\uff1a
\u7535\u7ebf\u622a\u9762\u4e00\u822c\u90fd\u662f\u5706\u3002
\u5706\u7684\u9762\u79ef=\u03c0r²=0.25\u03c0d²\uff08\u03c0\u662f\u5706\u5468\u7387\uff0cr\u662f\u5706\u7684\u534a\u5f84\uff0cd\u662f\u5706\u7684\u76f4\u5f84\uff09
16=0.25\u00d73.14\u00d7d²
d²=16\u00f70.25\u00f73.14
d=\u221a\uff0816\u00f70.25\u00f73.14\uff09=4.51466\uff08\u6beb\u7c73\uff09
\u6269\u5c55\u8d44\u6599\uff1a
\u5bfc\u7ebf\u622a\u9762\u90fd\u662f\u5706\uff0c\u5706\u7684\u9762\u79ef=\u03c0r²=0.25\u03c0d²\uff08\u03c0\u662f\u5706\u5468\u7387\uff0cr\u662f\u5706\u7684\u534a\u5f84\uff0cd\u662f\u5706\u7684\u76f4\u5f84\uff09
\u5728\u4e00\u4e2a\u5e73\u9762\u5185\uff0c\u4e00\u52a8\u70b9\u4ee5\u4e00\u5b9a\u70b9\u4e3a\u4e2d\u5fc3\uff0c\u4ee5\u4e00\u5b9a\u957f\u5ea6\u4e3a\u8ddd\u79bb\u65cb\u8f6c\u4e00\u5468\u6240\u5f62\u6210\u7684\u5c01\u95ed\u66f2\u7ebf\u53eb\u505a\u5706\u3002\u5706\u6709\u65e0\u6570\u6761\u5bf9\u79f0\u8f74\u3002
\u5728\u540c\u4e00\u5e73\u9762\u5185\uff0c\u5230\u5b9a\u70b9\u7684\u8ddd\u79bb\u7b49\u4e8e\u5b9a\u957f\u7684\u70b9\u7684\u96c6\u5408\u53eb\u505a\u5706\u3002\u5706\u53ef\u4ee5\u8868\u793a\u4e3a\u96c6\u5408{M||MO|=r},\u5706\u7684\u6807\u51c6\u65b9\u7a0b\u662f(x - a) ² + (y - b) ² = r ²\u3002\u5176\u4e2d\uff0cO\u662f\u5706\u5fc3\uff0cr \u662f\u534a\u5f84\u3002
\u5706\u5f62\u662f\u4e00\u79cd\u5706\u9525\u66f2\u7ebf\uff0c\u7531\u5e73\u884c\u4e8e\u5706\u9525\u5e95\u9762\u7684\u5e73\u9762\u622a\u5706\u9525\u5f97\u5230\u3002
\u5706\u662f\u4e00\u79cd\u51e0\u4f55\u56fe\u5f62\u3002\u6839\u636e\u5b9a\u4e49\uff0c\u901a\u5e38\u7528\u5706\u89c4\u6765\u753b\u5706\u3002 \u540c\u5706\u5185\u5706\u7684\u76f4\u5f84\u3001\u534a\u5f84\u957f\u5ea6\u6c38\u8fdc\u76f8\u540c\uff0c\u5706\u6709\u65e0\u6570\u6761\u534a\u5f84\u548c\u65e0\u6570\u6761\u76f4\u5f84\u3002\u5706\u662f\u8f74\u5bf9\u79f0\u3001\u4e2d\u5fc3\u5bf9\u79f0\u56fe\u5f62\u3002\u5bf9\u79f0\u8f74\u662f\u76f4\u5f84\u6240\u5728\u7684\u76f4\u7ebf\u3002 \u540c\u65f6\uff0c\u5706\u53c8\u662f\u201c\u6b63\u65e0\u9650\u591a\u8fb9\u5f62\u201d\uff0c\u800c\u201c\u65e0\u9650\u201d\u53ea\u662f\u4e00\u4e2a\u6982\u5ff5\u3002\u5f53\u591a\u8fb9\u5f62\u7684\u8fb9\u6570\u8d8a\u591a\u65f6\uff0c\u5176\u5f62\u72b6\u3001\u5468\u957f\u3001\u9762\u79ef\u5c31\u90fd\u8d8a\u63a5\u8fd1\u4e8e\u5706\u3002\u6240\u4ee5\uff0c\u4e16\u754c\u4e0a\u6ca1\u6709\u771f\u6b63\u7684\u5706\uff0c\u5706\u5b9e\u9645\u4e0a\u53ea\u662f\u6982\u5ff5\u6027\u7684\u56fe\u5f62\u3002
\u5706\u5468\u957f\uff08c\uff09\uff1a\u5706\u7684\u76f4\u5f84\uff08D\uff09\uff0c\u90a3\u5706\u7684\u5468\u957f\uff08c\uff09\u9664\u4ee5\u5706\u7684\u76f4\u5f84\uff08D\uff09\u7b49\u4e8e\u03c0\uff0c\u90a3\u5229\u7528\u4e58\u6cd5\u7684\u610f\u4e49\uff0c\u5c31\u7b49\u4e8e \u03c0\u4e58\u5706\u7684\u76f4\u5f84\uff08D\uff09\u7b49\u4e8e\u5706\u7684\u5468\u957f\uff08C\uff09\uff0cC=\u03c0d\u3002\u800c\u540c\u5706\u7684\u76f4\u5f84\uff08D\uff09\u662f\u5706\u7684\u534a\u5f84\uff08r\uff09\u7684\u4e24\u500d\uff0c\u6240\u4ee5\u5c31\u5706\u7684\u5468\u957f\uff08c\uff09\u7b49\u4e8e2\u4e58\u4ee5\u03c0\u4e58\u4ee5\u5706\u7684\u534a\u5f84\uff08r\uff09\uff0cC=2\u03c0r\u3002
\u628a\u5706\u5e73\u5747\u5206\u6210\u82e5\u5e72\u4efd\uff0c\u53ef\u4ee5\u62fc\u6210\u4e00\u4e2a\u8fd1\u4f3c\u7684\u957f\u65b9\u5f62\u3002\u957f\u65b9\u5f62\u7684\u5bbd\u5c31\u7b49\u4e8e\u5706\u7684\u534a\u5f84\uff08r\uff09\uff0c\u957f\u65b9\u5f62\u7684\u957f\u5c31\u662f\u5706\u5468\u957f\uff08C\uff09\u7684\u4e00\u534a\u3002\u957f\u65b9\u5f62\u7684\u9762\u79ef\u662fab\uff0c\u90a3\u5706\u7684\u9762\u79ef\u5c31\u662f\uff1a\u5706\u7684\u534a\u5f84\uff08r\uff09\u7684\u5e73\u65b9\u4e58\u4ee5\u03c0\uff0cS=\u03c0r²=0.25\u03c0d²
\u53c2\u8003\u8d44\u6599\u6765\u6e90\uff1a\u767e\u5ea6\u767e\u79d1-\u5706
\u53c2\u8003\u8d44\u6599\u6765\u6e90\uff1a\u767e\u5ea6\u767e\u79d1-\u5706\u7684\u9762\u79ef
计算方法：D=√（16/3.14）*2
指的是16平方毫米，直径大概为4.5毫米，计算方法同上。
圆的面积=半径的平方乘π
是指16平方毫米,直径是大概在4.5左右,这个就是单指铜线的粗度,未计外皮情况下的铜线粗度,如果再不清楚的话,大概是你的提问有问题了~
绛旓細16骞虫柟鐨勯摐绾鐩村緞绾4.5mm銆傝绠楁柟娉曪細D=鈭氾紙16/3.14锛*2
绛旓細鐞嗚璁＄畻鐩村緞锛 D=1.13脳鈭16=4.52(mm) 16骞虫柟鐢电嚎瀹為檯涓婄殑鐩村緞浼氱暐澶т簬4.52,鍥犱负鐢电嚎鏄敱澶氳偂灏忕嚎寰勭嚎缁為挳鑰岀粍鎴愮殑,瀵肩嚎闂存湁绌洪殭銆
绛旓細16骞虫柟閾滅嚎鏄竴绉嶅父瑙佺殑鐢电嚎瑙勬牸锛屽畠閫氬父鐢ㄤ簬浣庣數鍘嬭澶囨垨閰嶇數绯荤粺涓傞偅涔堬紝杩欑閾滅嚎澶氱矖鍛紵绛旀鏄細瀹冪殑鐩村緞澶х害涓1.29姣背锛屼篃灏辨槸璇达紝杩欑鐢电嚎闈炲父缁嗐傝繖涔熸槸涓轰粈涔16骞虫柟閾滅嚎閫氬父鍙敤浜庝綆鐢垫祦鍜屼綆鐢靛帇鐨勫満鍚堬紝鑰屼笉鑳界敤浜庢壙鍙楅珮杞芥祦閲忕殑鏈哄櫒鍜岃澶囦腑鐨勫師鍥犮傞摐绾挎槸涓绉嶉噾灞炲浣擄紝瀹冨叿鏈夎壇濂界殑瀵肩數鎬...
绛旓細16骞虫柟閾滅嚎鐨勭洿寰勭害涓2.26mm銆傞摐绾跨殑鎴潰绉拰鐩村緞涔嬮棿鏈変竴涓浐瀹氱殑鏁板鍏崇郴锛屽彲浠ラ氳繃鍏紡鏉ヨ绠椼傚浜16骞虫柟姣背鐨勬埅闈㈢Н锛屾垜浠娇鐢ㄥ叕寮忓彲浠ュ緱鍑哄叾鐩村緞绾︿负2.26mm銆傞摐绾跨殑澶у皬閫氬父浠ュ叾鎴潰绉潵琛￠噺锛屽崟浣嶉氬父涓哄钩鏂规绫炽傛埅闈㈢Н瓒婂ぇ锛岄摐绾跨殑瀵肩數鑳藉姏瓒婂己锛岃兘澶熸壙杞界殑鐢垫祦涔熻秺澶с傚洜姝わ紝鍦ㄩ夋嫨鐢电嚎鏃讹紝...
绛旓細16骞虫柟姣背鐨勭數绾跨洿寰4.51466姣背銆傝绠楁柟娉曞涓嬶細鐢电嚎鎴潰涓鑸兘鏄渾銆傚渾鐨勯潰绉=蟺r²=0.25蟺d²锛埾鏄渾鍛ㄧ巼锛宺鏄渾鐨勫崐寰勶紝d鏄渾鐨勭洿寰勶級16=0.25脳3.14脳d²d²=16梅0.25梅3.14 d=鈭氾紙16梅0.25梅3.14锛=4.51466锛堟绫筹級...
绛旓細4.5姣背銆傛牴鎹煡璇㈡ゼ鐩樼綉鏄剧ず锛16骞虫柟鐨勯摐绾鐩村緞鏄4.5姣背銆傝繖涓篃涓嶆槸鍥哄畾鐨勶紝鍥犱负姣忎釜鍘傚鐢熶骇鐨勫伐鑹轰笉鍚岋紝鎵浠ュ灏戜細瀛樺湪涓浜涘亸宸紝鏈嬪弸浠湪璐拱鏃讹紝鏍规嵁鐢佃矾浠ュ強鐢靛櫒鐨勯渶姹傛潵閫夋嫨锛屽鏋滈夋嫨瑙勬牸涓嶅锛屼細瀵艰嚧鏁翠釜鐢佃矾閮借閲嶆柊閾鸿銆
绛旓細杩欑閫氫織璇存硶鐨勬剰鎬鏄粯璁ゅ崟浣嶄负鈥滃钩鏂规绫斥濓紝姣斿鏈鐨勨16骞虫柟閾滅嚎鈥濆氨鏄í鎴潰绉槸16骞虫柟姣背鐨勯摐绾銆傜敱浜庨摐鐨勫瘑搴 蟻=8.9鍏/绔嬫柟鍘樼背锛岄摐绾挎í鎴潰绉 S=16骞虫柟姣背=0.16骞虫柟鍘樼背锛岄暱搴=1绫=100鍘樼背锛屾墍浠ユ湁璇ラ摐绾跨殑璐ㄩ噺鏄 m=蟻SL 锛屽嵆 m=8.9*0.16*100=142.4(鍏) 銆
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绛旓細涓銆16骞虫柟閾滅嚎甯﹀灏戝崈鐡 1銆佷笁鐩哥數璺 16骞虫柟閾滆姱鐢电嚎杩愮敤鍦ㄤ笁鐩哥數璺腑澶х害鍙甫51鍗冪摝銆傚ぇ瀹跺彲鏍规嵁鍏紡P=1.732UIcosφ璁＄畻銆16骞虫柟閾滆姱鐢电嚎鏄庢暦鐨勫畨鍏ㄦ壙杞界數娴佷负91A銆佺數鍘嬩负380V銆乧osφ涓鑸彇0.85锛1.732×0.38×91×0.85≈51鍗冪摝銆2銆佸崟鐩哥數璺 濡傛灉16骞虫柟閾滆姱...
绛旓細绛旀锛氭牴鎹绠锛16骞虫柟閾滅嚎鍦380V鐨勭數鍘嬩笅锛屽彲浠ユ壙鍙楃殑鏈澶ц礋杞界害涓57鑷73鍗冪摝鐨勫姛鐜囥傝В閲婏細1. 浜嗚В鐢电紗杞芥祦閲忕殑鎰忎箟锛閾滅嚎鐨杞芥祦閲忔寚鐨勬槸鐢电嚎鍦ㄩ暱鏃堕棿杩愯涓嬩笉浼氳繃鐑殑瀹夊叏鐢垫祦鍊笺備簡瑙ｈ繖涓鐐瑰浜庤绠楃數绾挎墍鑳芥壙杞界殑鍔熺巼鑷冲叧閲嶈銆傚姛鐜囩殑璁＄畻娑夊強鍒扮數娴佸拰鐢靛帇涓や釜鍙傛暟銆2. 鍏充簬鐢电紗瑙勬牸鍜岀數鍘嬬殑搴旂敤...
