C语言,一个两个字符串相连接的函数,可以解释一下,为什么??谢谢 用C语言:写一个函数,将两个字符串连接

C\u8bed\u8a00\u5b57\u7b26\u4e32\u521d\u503c\u5bf9\u51fd\u6570\u8bf4\u660e

3 A \u5b9a\u4e49\u6307\u9488\uff0c\u5e76\u8d4b\u503c\u4e3a\u5e38\u91cf\u5b57\u7b26\u4e32\u5730\u5740\u3002 \u6b63\u786e\u3002
B \u5b9a\u4e49\u5b57\u7b26\u6570\u7ec4\uff0c\u521d\u59cb\u5316\u524d\u516d\u4e2a\u5143\u7d20\uff0c\u7b2c\u4e03\u4e2a\u81ea\u52a8\u4e3a\0\uff0c \u6b63\u786e\u3002
C \u5b9a\u4e49\u6570\u7ec4\u540e\uff0c\u4e0d\u53ef\u4ee5\u518d\u7528str1="string"\u65b9\u5f0f\u8d4b\u503c\uff0c\u9519\u8bef\u3002
D str1\u67097\u4e2a\u5143\u7d20\uff0cstr2\u67099\u4e2a\u5143\u7d20\u3002 \u5c06str1\u590d\u5236\u7ed9str2 \u6b63\u786e\u3002
\u9009C

4 str1\u4e3a\u957f\u5ea6\u4e3a4\u7684\u5b57\u7b26\u4e32\uff0c\u53605\u4e2a\u5b57\u7b26\u7a7a\u95f4
str2\u4e3a10\u4e2a\u7a7a\u95f4\u7684\u5b57\u7b26\u6570\u7ec4
str3\u4e3a\u5e38\u91cf\u5b57\u7b26\u4e32\uff0c\u957f\u5ea6\u4e3a7\uff0c\u53608\u4e2a\u5b57\u7b26\u7a7a\u95f4\u3002
str4\u4e3a\u4e0d\u786e\u5b9a\u6307\u9488\u3002
str5\u4e3a\u5e38\u91cf\u5b57\u7b26\u4e32\uff0c\u957f\u5ea6\u4e3a4\uff0c\u53605\u4e2a\u5b57\u7b26\u7a7a\u95f4\u3002
\u9009\u9879\u4e2d\uff0c\u4e25\u683c\u6765\u8bf4 \uff0c\u53ea\u6709A\u662f\u5bf9\u7684 \u3002
BD\u4e24\u4e2a\uff0c\u8d4b\u503c\u7ed9\u5e38\u91cf\u5b57\u7b26\u4e32\u4f1a\u5bfc\u81f4\u7a0b\u5e8f\u5d29\u6e83
C\u8d4b\u503c\u7ed9\u91ce\u6307\u9488\uff0c\u540c\u6837\u51fa\u9519\u3002

\u9009\u81ea\uff1a\u300a\u7a0b\u5e8f\u903b\u8f91\u53caC\u8bed\u8a00\u300b\uff0c\u672c\u89c6\u9891\u4e3a\u5b57\u7b26\u4e32\u7684\u7b2c04\u5c0f\u8282\u3002\u4e3b\u8981\u8bb2\u89e3\u56db\u4e2a\u5e38\u7528\u7684\u5b57\u7b26\u4e32\u5904\u7406\u51fd\u6570\uff0c\u5305\u62ec\uff1a\u6c42\u5b57\u7b26\u4e32\u7684\u957f\u5ea6\u3001\u5b57\u7b26\u4e32\u7684\u8d4b\u503c\u3001\u5b57\u7b26\u4e32\u7684\u8fde\u63a5\u5df2\u7ecf\u5b57\u7b26\u4e32\u5927\u5c0f\u7684\u6bd4\u8f83\u3002\u5177\u4f53\u6709\u6848\u4f8b\u8bb2\u89e3\u3002

#include <stdio.h>
void mystery1( char *s1, const char *s2 ); //声明函数
int main( void )
{
char string1[ 80 ]; //声明两个字符数组
char string2[ 80 ];
printf( "Enter two strings: " ); //打印提示信息
scanf( "%s%s", string1, string2 ); //输入两个字符串的内容
mystery1( string1, string2 ); //调用mystery1函数
printf( "%s\n", string1 ); //输出字符串string1的内容
return 0;
}
void mystery1( char *s1, const char *s2 ) //定义mystery1函数
{
while ( *s1 != '\0' ) { //逐位检测字符串中的内容直到字符串尾部为止
s1++;
}
for ( ; *s1 = *s2; s1++, s2++ ) { //把字符串s2中的内容逐个地添加到字符串s1的后面
;
}
}

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