视频分析2x05-x-1怎样用十字相乘法
\u7cfb\u6570\u4e0d\u4e3a1\u7684\u5341\u5b57\u76f8\u4e58\u6cd5\u89c6\u9891\u8bb2\u89e3\u5c06\u4e8c\u6b21\u9879\u7684\u7cfb\u6570\u4e5f\u5316\u4e3a\u76f8\u4e58\u7684\u5f62\u5f0f\uff0c\u7ed9\u4f60\u4e3e\u4e2a\u4f8b\u5b50
2x +x-1\u53ef\u4ee5\u914d\u4e3ax 1
2x -1
\u5373\u4e3a(x+1)(2x-1)
\u5173\u952e\u5c31\u662f\u628a\u4e8c\u6b21\u9879\u5199\u6210\u76f8\u4e58\u7684\u5f62\u5f0f\uff0c\u6211\u7684\u4e60\u60ef\u901a\u5e38\u662f\u5199\u4e3a1\u4e58\u4ee5\u53e6\u4e00\u4e2a\u6570
2x²\uff0bx\uff0d1
=(2x-1)(x+1)
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绛旓細浠1锛渪2锛0 f(x2)-f(x1) = 銆2x2^2-1銆-銆2x1^2-1銆= 2(x2^2-x1^2)= 2(x2+x1)(x2-x1)鈭祒1锛渪2锛0 鈭磝2+x1锛0锛寈2-x1锛0 鈭磃(x2)-f(x1) = 2(x2+x1)(x2-x1)锛0 鈭磃(x)鍦(-鈭烇紝0]涓婃槸鍑忓嚱鏁 鍚屽浣犲ソ锛屽鏋滈棶棰樺凡瑙ｅ喅锛岃寰楀彸涓婅閲囩撼鍝~~鎮...
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绛旓細鈶寸敤鍥犲紡鍒嗚В娉曡В姝ゆ柟绋嬶細2锛5x-1锛²=2锛5x-1锛夎В锛2锛5x-1锛²-2锛5x-1锛=0 2锛5x-1锛塠锛5x-1锛-1]=0 5x-1=0 5x-2=0 x1=1/5 x2=2/5 鈶佃В鏂圭▼(浠绘剰鏂规硶锛夛細7x锛2-x)=3(x-2)瑙ｏ細7x锛2-x)=-3(2-x)7x锛2-x)+3(2-x) =0 (2-x)(...
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