求解因式分解难题，初二数学！谢谢！ 初二 数学 难题 请详细解答,谢谢! (5 10:33...
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\uff081\uff09\u5728\u4e0a\u8ff0\u8fc7\u7a0b\u4e2d\uff0c\u7531\u2460\u5230\u2461\u6240\u7528\u7684\u6570\u5b66\u65b9\u6cd5\u662f____\u914d\u65b9\u6cd5____\uff0c\u5176\u4e2d\u8fd0\u7528\u4e86____\u5b8c\u5168\u5e73\u65b9___\u516c\u5f0f\uff0c\u7531\u2462\u3001\u2463\u5f97\u5230\u2464\u6240\u7528\u7684\u6570\u5b66\u65b9\u6cd5\u662f___\u6362\u5143\u6cd5___\uff0e
\uff082\uff09\u6839\u636e\u9605\u8bfb\u6750\u6599\u63d0\u4f9b\u7684\u65b9\u6cd5\uff0c\u786e\u5b9a\u629b\u7269\u7ebfy=x2-2mx+2m2-3m+1\u9876\u70b9\u7684\u7eb5\u5750\u6807y\u4e0e\u6a2a\u5750\u6807x\u4e4b\u95f4\u7684\u5173\u7cfb\u5f0f\u3002
\u914d\u65b9\u540e\u5f97\u5230\uff1ay=(x-m)^2+m^2-3m+1
\u5c06x=m\u4ee3\u5165\u4e0a\u5f0f\uff0c\u5f97\u5230y=m^2-3m+1
\u7136\u540e\u5c06m\u4ee5x\u66ff\u4ee3\u56de\u53bb\uff0c\u5219\u6709 y=x^2-3x+1 \uff0c\u5373\u4e3a\u6240\u6c42\u3002
=(x^2+1)^2-9x^2
=(x^2+3x+1)(x^2-3x+1)
②x^4+2x^3+3x^2+2x+1
=(x^2+1)^2+2x(x^2+1)+x^2
=(x^2+x+1)^2
9)设x^2-2xy+ky^2+3x-5y+2
=(x+ay+1)(x+by+2)
a+b=-2 ,2(x+ay)+(x+by)=3x-5y->2a+b=-5
解得a=-3,b=1
∴k=ab=-3
10)x^8+x^6+x^4+x^2+1
=(x^2-1)(x^8+x^6+x^4+x^2+1)/(x^2-1)
=(x^10-1)/(x^2-1)
=(x^5+1)(x^5-1)/(x^2-1)
=(x+1)(x^4-x^3+x^2-x+1)(x-1)(x^4+x^3+x^2+x+1)/[(x+1)(x-1)]
=(x^4-x^3+x^2-x+1)(x^4+x^3+x^2+x+1)
11)两个已知等式相加得
(x+y)^2+(x+y)-42=0
(x+y+7)(x+y-6)=0
∴x+y=-7或x+y=6
因式分解可以采用十字相乘法，通用。
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绛旓細x^2灏辫〃绀哄钩鏂癸紝渚濇锛寈^3琛ㄧず3娆℃柟 1.12x^2-6x-2x+1+3x^2-3x-x+1+x^2=16x^2-12x+2=(2x^2-1)(8x^2-2)=2(x^2-1)(2x^2-1)2.浠^3=t锛屽垯鍘熷紡=t^3+t^2+t-3锛屼护t^3+t^2+t-3锛屽彂鐜皌=1鏄柟绋嬬殑鏍癸紝(t^3+t^2+t-3)/(t-1)=t^2+2t+3锛屾墍浠^3+t^...
绛旓細鍘熷紡=a^2+ab^2-2ab-b^3+b^2 =a^2-2ab+b^2+ab^2-b^3 =(a-b)^2+b^2(a-b)=(a-b)[(a-b)+b^2]=(a-b)(a-b+b^2)
绛旓細鍥炵瓟锛21銆佸師寮 =a(x-y)+b(x-y) =(x-y)(a+b)
绛旓細=(a-b)(x-y)+(a-b)(x+y)=(a-b)(x-y+x+y)=2x(x-b)3x²=1 x²=1/3 x=卤鈭3/3 =7.46脳13.6+0.54脳13.6+27.2 =13.6脳(7.46+0.54)+27.2 =13.6脳8+27.2 =27.2脳4+27.2 =27.2脳(4+1)=27.2脳5 =136 ...
绛旓細=(m3+1)(m12+m6++1)=(m3+1)[(m6+1)2-m6]=(m+1)(m2-m+1)(m6+1+m3)(m6+1-m3)渚2鍒嗚В鍥犲紡锛歺4+5x3+15x-9 瑙ｆ瀽鍙牴鎹郴鏁扮壒寰佽繘琛屽垎缁 瑙ｅ師寮=锛坸4-9锛+5x3+15x =(x2+3)(x2-3)+5x(x2+3)=(x2+3)(x2+5x-3)闄勶細浠呬緵鍙傝 绗4璇 鍥犲紡鍒嗚В 銆栫煡璇嗙偣銆楀洜寮忓垎瑙...
绛旓細锛1锛墆²-13y+12=(y-1)(y-12)锛2锛塶²-n=n(n-1)鍥犱负n涓巒-1涓绘湁涓涓负鍋舵暟 鎵浠²-n鎬讳负鍋舵暟 锛3锛塵=10+(-8)=2 n=10*(-8)=-80 锛4锛墄²+11x+m=(x-3)(x-m/3)鎵浠-3+(-m/3)=11 鎵浠=42 锛5锛堿+B=(2x²+3xy+y²)+...
绛旓細1.=2ab(2ab-3)2.=3(x^2-1)=3(x-1)(x+1)3.=x(x^2-1)=x(x-1)(x+1)4.=a(a^2+4a+4)=a(a+2)^2 5.=a(a+x+1)6.=-4x(x^2+4x+6)7.=(3a)^4-(2b)^4=[(3a)^2+(2b)^2][(3a)^2(2b)^2]=[(3a)^2+(2b)^2][(3a-2b)(3a+2b)]8.=(x+y+z)(...
绛旓細浜斻鍒嗚В鍥犲紡(x2+5x+3)(x2+5x-23)+k=(x2+5x-10)2鍚,姹俴鐨勫笺(6') 鍏佸凡鐭ュ叧浜巟鐨勪簩娆′笁椤瑰紡x2+mx+n鏈変竴涓洜寮(x+5),涓攎+n=17,璇曟眰m銆乶鐨勫笺(6') 涓冦佽澶氶」寮廇=(a2+1)(b2+1)-4ab (1)璇曞皢澶氶」寮忓啓鎴愪袱涓潪璐熸暟鐨勫拰鐨勫舰寮忋 (2)浠=0,姹俛銆乥鐨勫笺 (6') 涓銆侀夋嫨...
绛旓細涓 宸茬煡 2^48 - 1 鍙互琚60涓70涔嬮棿鐨勪袱涓暣鏁版暣闄わ紝姹傝繖涓や釜鏁存暟銆2^48-1 =(2^24+1)(2^12+1)(2^6+1)(2^3+1)(2^3-1)=(2^24+1)(2^12+1)*65*9*7 =(2^24+1)(2^12+1)*65*63 鎵浠ワ紝杩欎袱涓暣鏁版槸63鍜65銆備簩 鑻ユ暟a銆乥銆乧 婊¤冻 a锛18锛漛锛14锛漜锛35 姹俛^...
