实验室需要0.1mol/L氢氧
\u5b9e\u9a8c\u5ba4\u9700\u89810.1mol/L\u6c22\u6c27\uff081\uff09\u7528\u6d53\u6eb6\u6db2\u914d\u5236\u7a00\u6eb6\u6db2\u5c31\u662f\u6eb6\u6db2\u7a00\u91ca\u8fc7\u7a0b\uff0c\u5728\u7a00\u91ca\u8fc7\u7a0b\u4e2d\u6eb6\u8d28\u7684\u7269\u8d28\u7684\u91cf\u4e0d\u53d8\uff0c\u5217\u5f0f\u4e3a\uff1a0.1mol/L\u00d70.1L=2mol/L\u00d7V\uff0c\u89e3\u5f97V=0.005mL=5mL\uff0c\u7b54\uff1a\u6240\u97002mol/L\u6c22\u6c27\u5316\u94a0\u6eb6\u6db2\u7684\u4f53\u79ef\u4e3a5mL\uff1b\uff082\uff0950mL\u76842mol/L\u7684\u6c22\u6c27\u5316\u94a0\u6eb6\u6db2\u542b\u6c22\u6c27\u5316\u94a0\u7269\u8d28\u7684\u91cf\u4e3a2mol/L\u00d70.05L=0.1mol\uff0c\u6839\u636e2NaOH-H2SO4\u77e5\u9053\uff0c\u4e0e\u6c22\u6c27\u5316\u94a0\u4e4b\u53cd\u5e94\u7684H2SO4\u7269\u8d28\u7684\u91cf\u4e3a0.1mol\u00d712=0.05mol\uff0c\u6240\u4ee5\u9700\u89810.5mol/L\u7684H2SO4\u4f53\u79ef\u4e3a0.05mol0.5mol/L=0.1L\uff0c\u7b54\uff1a\u5b8c\u5168\u4e2d\u548c50mL2mol/L\u6c22\u6c27\u5316\u94a0\u6eb6\u6db2\uff0c\u9700\u89810.5mol/L\u7684\u786b\u91780.1L\uff0e
Mg/Al\u51710.1mol\u5b8c\u5168\u6eb6\u4e8e0.4mol\u76d0\u9178\u4e2d\uff0c\u6eb6\u6db2\u4e2d\u4e3aMgCl2\u548cAlCl3\uff0c\u4ee5\u53ca\u6ca1\u6709\u5b8c\u5168\u53cd\u5e94\u7684\u76d0\u9178\u3002\u6ef4\u5165140mlNaOH\u65f6\u5f00\u59cb\u4ea7\u751f\u6c89\u6dc0\uff0c\u6b64\u65f6\u6070\u597d\u8fc7\u91cf\u7684\u76d0\u9178\u88ab\u4e2d\u548c\u3002\u5373\u5b9e\u9645\u4e0eMg/Al\u6df7\u5408\u7269\u53cd\u5e94\u7684\u76d0\u9178\u4e3a0.4-0.14=0.26mol
\u8bbeMg\u7684\u7269\u8d28\u7684\u91cf\u4e3axmol\uff0c\u5219\u4e0e\u6df7\u5408\u7269\u53cd\u5e94\u7684\u76d0\u9178\u7684\u91cf\u4e3a2x+3\uff080.1-x\uff09=0.26\uff0c\u6c42\u5f97x=0.04
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\u4e0d\u53d1\u751f\u6c89\u6dc0\u65f6\u5df2\u6ef4\u52a0\u6c22\u6c27\u5316\u94a0\u7684\u4f53\u79ef\u4e3a0.46L\u3002
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| （1）需氢氧化钠的质量=100mL×10 -3 ×0.1mol/L×40g/mol=0.4g （2）设需要0.5mol/L的硫酸的物质的量为x 50mL已配制溶液中氢氧化钠的物质的量=50mL×10 -3 ×0.1mol/L=0.005mol H 2 SO 4 +2NaOH═Na 2 SO 4 +2H 2 O 1 2 x 0.005mol
需要0.5mol/L的硫酸的体积=0.0025mol÷0.5mol/L×1000=5.0mL 答：（1）实验室需要0.1mol/L氢氧化钠溶液100mL需氢氧化钠的质量为0.4g； （2）完全中和50mL已配制溶液，需要0.5mol/L的硫酸5.0 mL． |
绛旓細闇瑕佺殑姘㈡哀鍖栭挔鐨勭墿璐ㄧ殑閲弉=c1脳V1=0.1mol/L脳100ml=0.01mol 鎵闇姘㈡哀鍖栭挔婧舵恫鐨勪綋绉疺2=n/c2=0.01mol/锛2mol/L锛=0.005L=5ml 50ml宸查厤缃憾娑蹭腑姘㈡哀鍖栭挔鐨勭墿璐ㄧ殑閲弉=2mol/L脳50ml=0.1mol NaOH+HCl=NaCl+H2O 涔熷氨鏄0.1mol姘㈡哀鍖栭挔闇瑕0.1mol鐩愰吀锛屽洜姝ょ洂閰哥殑浣撶НV=n/c=0.1...
绛旓細1銆0.1mol/L*0.1L*40g/mol=0.4g 2銆乶(NaOH)=0.1mol/L*0.05L=0.005mol 鏍规嵁鍙嶅簲鏂圭▼寮忥紝2NaOH---H2SO4 鎵浠ワ紝n(H2SO4)=0.0025mol锛孷(H2SO4)=0.0025mol/0.25mol/L=0.01L
绛旓細(1)0.1mol\L*0.1L=0.01mol 0.01mol闄や互2mol/L=0.005L=5ml (2)1mol纭吀闇瑕2molNaOH 鍙互涓拰纭吀鐗╄川鐨勯噺0.01mol闄や互2=0.005mol 0.005mol闄や互5mol/L=0.001L=1ml
绛旓細(1)绋閲婂畾寰 c娴揤娴=c绋V绋 2mol/L*V娴= 0.1mol/L*100mL (2) NaOH ~ HCl 1mol 1mol 0.1mol/L*0.05L 1mol/L*V(HCl)0.1mol/L*0.05L = 1mol/L*V(HCl)
绛旓細1銆0.1mol/L*0.1L/2mol/L=0.005L 2銆0.1mol/L*0.05L/1mol/L=0.005L
绛旓細銆1銆戦厤鍒 0.1mol/L姘㈡哀鍖栭挔婧舵恫450ml锛闇瑕绉伴噺姘㈡哀鍖栭挔澶氬皯鍏嬶紵绛旓細闇瑕佺О閲忔阿姘у寲閽 = 0.1mol/Lx450ml/1000L/mlx40g/mol = 1.8 鍏 銆2銆戦厤鍒 0.15mol/L纭吀婧舵恫500ml,闇瑕佹祿纭吀锛18mol/L锛夊灏戞鍗囷紵绛旓細闇瑕佹祿纭吀锛18mol/L锛=0.15mol/L x 500ml/18mol/L = 4.2 姣崌 ...
绛旓細闇瑕纭吀閾滅殑鐗╄川鐨勯噺涓0.1mol/L x 0.1L==0.01mol 鍒╃敤鍏冪礌鍘熷瓙涓暟瀹堟亽鐭ラ亾,涓涓猚uso4.5h2o 鍚湁涓涓狢uSO4,鍒檆uso4.5h2o鐨勭墿璐ㄧ殑閲忎篃鏄0.01mol,鎵浠ヨ川閲忎负0.01molx250g/mol ==2.5g
绛旓細灏忎簬锛岄厤鍒0.5mol/L纭吀婧舵恫500mL锛闇瑕H2SO4璐ㄩ噺=0.5*0.5*98=24.5g锛岄渶瑕佹祿纭吀鐨勮川閲忎负锛24.5/0.98=25g锛屽叾浣撶Н涓猴細25/1.84=13.6ml
绛旓細浣犺繖棰樻湁闂鍚э紝鏄笉鏄0.1mol/L,0.5mol/L 鎸夎川閲忓畧鎭掓潵绠楋紝绋閲婂墠婧舵恫姘㈡哀鍖栭挔鐗╄川鐨勯噺=绋閲婂悗姘㈡哀鍖栭挔鐗╄川鐨勯噺 鍋囪鎵闇0.5MOL姘㈡哀鍖栭挔婧舵恫鐨勪綋绉负x 0.5x=0.1脳100 x=20ml 锛2锛50ml0.1mol/L涓惈姘㈡哀鍖栭挔涓0.005mol锛屽嵆闇瑕0.01mol鐩愰吀 鎵闇鐩愰吀浣撶Н涓0.005/0.5*1000=10ml ...
绛旓細瑕侀厤缃960mL鐨勬憾娑茶偗瀹氳鐢1000mL鐨勫閲忕摱鍟︼紝鍥犱负娌℃湁960mL鐨勫閲忕摱鐨勩傞厤鎴1000mL鍚庝綘鍙互鍙960mL鏉ョ敤鐨勩傝绠楀涓嬶細1000mL鐨0.1mol/L鐨凜uSO4婧舵恫鍚獵uSO4鐨勭墿璐ㄧ殑閲忎负锛0.1X1=0.1mol銆傚嵆杩欎釜婧舵恫闇瑕0.1mol鐨凜uSO4.鍙堢煡CuSO4 鐨勬懇灏旇川閲忔槸160g/mol锛孋uSO4.5H2O鐨勬槸250 g/mol銆傛墍浠ラ渶瑕...
