你能把多项式x2-2x-3因式分解吗?把多项式x2+5x-24因式分解

\u591a\u9879\u5f0fx2-5x-6\u56e0\u5f0f\u5206\u89e3\u6240\u5f97\u7ed3\u679c\u662f

x2-5x-6
=(x-6)(x+1)

x2\uff0d4x=y \u539f\u5f0f=\uff08y+2\uff09\uff08y+6\uff09+4 \uff08\u7b2c\u4e00\u6b65\uff09
= y2+8y+16 \uff08\u7b2c\u4e8c\u6b65\uff09
=\uff08y+4\uff092 \uff08\u7b2c\u4e09\u6b65\uff09
=\uff08x2\uff0d4x+4\uff092 \uff08\u7b2c\u56db\u6b65\uff09

1\uff09\u8be5\u540c\u5b66\u7b2c\u4e8c\u6b65\u5230\u7b2c\u4e09\u6b65\u8fd0\u7528\u4e86\u56e0\u5f0f\u5206\u89e3\u7684\u3010C\u3011\uff0e
A\uff0e\u63d0\u53d6\u516c\u56e0\u5f0f
B\uff0e\u5e73\u65b9\u5dee\u516c\u5f0f
C\uff0e\u4e24\u6570\u548c\u7684\u5b8c\u5168\u5e73\u65b9\u516c\u5f0f
D\uff0e\u4e24\u6570\u5dee\u7684\u5b8c\u5168\u5e73\u65b9\u516c\u5f0f

\uff082\uff09\u8be5\u540c\u5b66\u56e0\u5f0f\u5206\u89e3\u7684\u7ed3\u679c\u662f\u5426\u5f7b\u5e95\uff1f\u3010\u4e0d\u5f7b\u5e95\u3011\uff0e\uff08\u586b\u201c\u5f7b\u5e95\u201d\u6216\u201c\u4e0d\u5f7b\u5e95\u201d\uff09
\u82e5\u4e0d\u5f7b\u5e95\uff0c\u8bf7\u76f4\u63a5\u5199\u51fa\u56e0\u5f0f\u5206\u89e3\u7684\u6700\u540e\u7ed3\u679c\u3010(x-2)^4\u3011\uff0e

\uff083\uff09\u8bf7\u4f60\u6a21\u4eff\u4ee5\u4e0a\u65b9\u6cd5\u5c1d\u8bd5\u5bf9\u591a\u9879\u5f0f\uff08x2\uff0d2x\uff09\uff08x2\uff0d2x+2\uff09+1\u8fdb\u884c\u56e0\u5f0f\u5206\u89e3\uff0e
\uff08x2\uff0d2x\uff09\uff08x2\uff0d2x+2\uff09+1
= \uff08x2\uff0d2x\uff09^2 + 2\uff08x2\uff0d2x) + 1
= \uff08x2\uff0d2x+1\uff09^2
= \uff08x-1\uff09^4

用十字相乘法
x^2-2x-3=(x+1)(x-3)
x^2+5x-24=(x+8)(x-3)

(x+8)(x-3)=24
望采纳

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