C语言编程，关于银行利息 c语言编程 银行利率问题
c\u8bed\u8a00 \u94f6\u884c\u5229\u606f\u5229 \u7387
\u9879 \u76ee
\u6708\u5229\u7387\uff08\u2030\uff09 \u5e74\u5229\u7387\uff08%\uff09
\u6d3b \u671f 0.60 0.72
\u5b9a
\u671f
\u6574
\u5b58
\u6574
\u53d6
\u4e09\u4e2a\u6708 1.425 1.80
\u534a\u5e74 1.725 2.25
\u4e00\u5e74 1.875 2.52
\u4e8c\u5e74 2.25 3.06
\u4e09\u5e74 2.7 3.69
\u4e94\u5e74 3 4.14
\u96f6\u5b58
\u6574\u53d6
\u6574\u5b58
\u96f6\u53d6
\u5b58\u672c
\u53d6\u606f
\u4e00\u5e74 1.425 1.80
\u4e09\u5e74 1.725 2.25
\u4e94\u5e74 1.875 2.52
\u5355\u4f4d\u534f\u5b9a\u5b58\u6b3e 1.2 1.44
\u5b9a\u6d3b\u4e24\u4fbf \u6309\u4e00\u5e74\u671f\u4ee5\u5185\u5b9a\u671f\u6574\u5b58\u6574\u53d6
\u540c\u6863\u6b21\u5229\u7387\u6253\u516d\u6298\u6267\u884c \u540c\u524d
\u4eba\u6c11\u5e01\u901a\u77e5\u5b58\u6b3e\u5229\u7387\u8868
2002\u5e742\u670821\u65e5\u8d77\u6267\u884c
\u63d0\u524d\u901a\u77e5\u7684\u671f\u9650 \u5e74\u5229\u7387\uff08%\uff09
\u4e00\u5929 1.08
\u4e03\u5929 1.62
\u4e2d\u56fd\u94f6\u884c\u4e1a\u534f\u4f1a\u5c0f\u989d\u5916\u5e01\u5b58\u6b3e\u5229\u7387\u8868
2005\u5e7412\u670828\u65e5\u8d77\u6267\u884c
\u5e74\u5229\u7387\uff08%\uff09 \u6d3b\u671f \u4e00\u4e2a\u6708 \u4e09\u4e2a\u6708 \u534a\u5e74 \u4e00\u5e74 \u4e8c\u5e74
\u7f8e \u5143 1.1500 2.2500 2.7500 2.8750 3.0000 3.2500
\u82f1 \u9551 0.3000 1.7500 2.3125 2.6875 3.0625 3.1250
\u6b27 \u5143 0.1000 0.7500 1.0000 1.1250 1.2500 1.3125
\u65e5 \u5143 0.0001 0.0100 0.0100 0.0100 0.0100 0.0100
\u6e2f \u5e01 1.0000 1.8750 2.3750 2.5000 2.6250 2.7500
\u52a0\u62ff\u5927\u5143 0.1500 1.1250 1.3125 1.5000 1.5625 1.6250
\u745e\u58eb\u6cd5\u90ce 0.0500 0.1000 0.1250 0.2500 0.5000 0.5625
\u6fb3\u5143 1.0000 2.0625 2.3750 2.6875 3.3125 3.3750
#include"stdio.h"
void f1(float x)
{
int n;
float y=0.75*x,sum;
for(n=1;n<15;n++)
{
x=1.08*x;
y=x*0.0075;
y+=y;
x+=x;
}
printf("\u5b58\u5165\u73b0\u91d1%f,\u53ef\u5f97\u5229\u606f%f,\u5b83\u4eec\u4e4b\u548c%f",12*x,12*y,12*(x+y));
}
void f2(float x)
{
int n;
float y=0.0175*x,sum;
for(n=1;n<15;n++)
{
x+=0.08*x
y+=0.175*x;
}
printf("\u5b58\u5165\u73b0\u91d1%f,\u53ef\u5f97\u5229\u606f%f,\u5b83\u4eec\u4e4b\u548c%f",12*x,12*y,12*(x+y));
}
int main()
{
printf("\u5176\u591a\u4f59\u7684\u94b1\u662f\u7b2c\u4e00\u5e74\u6bcf\u67082000\u5143\uff0c\u4ee5\u540e\u6bcf\u5e74\u6bcf\u6708\u591a\u4f59\u7684\u94b1\u5728\u4e0a\u4e00\u5e74\u961f\u6bcf\u6708\u591a\u4f59\u94b1\u7684\u57fa\u7840\u4e0a\u518d\u589e\u52a08%\uff0c\u6d3b\u671f\u6708\u606f\u4e3a0.75%\uff0c\u4e00\u5e74\u671f\u6708\u606f\u4e3a1.75%\uff0c\u4e09\u5e74\u671f\u6708\u606f\u4e3a2.15%\uff0c\u4e94\u5e74\u671f\u6708\u606f\u4e3a2.75%\uff0c\u4e14\u94f6\u884c\u5bf9\u5b9a\u671f\u5b58\u6b3e\u8fc7\u671f\u90e8\u5206\u4e0d\u652f\u4ed8\u5229\u606f\u3002");
")
printf(">>>>>>>>>>>>>");
printf("\u8bf7\u6309\u6570\u5b57\u952e\u64cd\u4f5c\t"):
printf("\t1.\u7b54\u6d3b\u671f15\u5e74\u672c\u91d1\u4e0e\u5229\u606f\u4ee5\u53ca\u5b83\u4eec\u4e4b\u548c\n")\uff1b
printf("\t2.\u7b541\u5e74\u5b9a\u671f15\u5e74\u672c\u91d1\u4e0e\u5229\u606f\u4ee5\u53ca\u5b83\u4eec\u4e4b\u548c\n")\uff1b
printf("\t3.\u7b543\u5e74\u5b9a\u671f15\u5e74\u672c\u91d1\u4e0e\u5229\u606f\u4ee5\u53ca\u5b83\u4eec\u4e4b\u548c\n")\uff1b
printf("\t4.\u7b545\u5e74\u5b9a\u671f15\u5e74\u672c\u91d1\u4e0e\u5229\u606f\u4ee5\u53ca\u5b83\u4eec\u4e4b\u548c\n")\uff1b
printf("\t0\u9000\u51fa\t\t5\u6e05\u5c4f")\uff1b
switch(getchar())
{
case 1: f1(2000);break;
case 2: f2(2000);break;
case 3: f3(2000);break;
case 4: f4(2000);break;
case 5: system(cls");break;
case 0: exit(1);break;
\uff5d
\u90a3\u4e2a\u5176\u4ed6\u51fd\u6570\u7c7b\u662f\uff0c\u6211\u5c31\u4e0d\u518d\u8fd9\u91cc\u7f16\u4e86\uff0c\u65f6\u95f4\u7d27\u6025\uff0c\u6ca1\u7f16\u8bd1\u8fc7\uff0c\u6709\u95ee\u9898\u518d\u8bf7\u6559
void main(){
double sum,pri;
int y;
printf("请输入存款数目:");
scanf("%lf",&sum);
pri=sum;
printf("请输入存款年限:");
scanf("%d",&y);
switch (y)
{
case 1:
sum=sum*(1+3.66/100);
break;
case 2:
sum=sum*(1+4.50/100);
break;
case 3:
sum=sum*(1+5.28/100);
break;
case 5:
sum=sum*(1+5.8/100);
break;
default:
sum=sum*(1+2.92/100);
break;
}
printf("%d年过后你的资金总额为:%lf 利息为:%lf\n",y,sum-pri);
}
显示:
请输入存款数目:10000
请输入存款年限:5
5年过后你的资金总额为:10580.000000 利息为:580.000000
以没有了。
这应该简单的啊,
只是一个选择语句啊,if
绛旓細鍥炶溅閿粨鏉. scanf("%f", &year); //璧嬪肩粰鍙橀噺 year printf("input rate \n"); //绛夊緟鐢ㄦ埛杈撳叆骞村埄鐜, 鍥炶溅閿粨鏉. scanf("%f", &rate); //璧嬪肩粰鍙橀噺 rate sum
绛旓細涓銆c璇█閾惰璐锋鐨勬湀鍒╃巼绠鍗曚唬鐮 if璇彞閲岄潰鍔犱笂switch鍒ゆ柇璇彞鍗冲彲鍐嶇湅鐪嬪埆浜烘庝箞璇寸殑銆備簩銆c璇█锛岄摱琛璐锋鐨勬湀鍒╃巼锛岀畝鍗曚唬鐮侊紵璁鹃摱琛屽畾鏈熷瓨娆剧殑骞村埄鐜rate涓2.25%锛屽凡鐭ュ瓨娆炬湡涓簄骞达紝瀛樻鏈噾涓篶apital鍏冿紝璇缂栫▼璁＄畻骞惰緭鍑簄骞村悗鐨勬湰鍒╀箣鍜宒eposit銆傜▼搴忎腑鎵鏈夋诞鐐规暟鐨勬暟鎹被鍨嬪潎涓篸ouble绫诲瀷銆#in...
绛旓細5骞磋繃鍚庝綘鐨勮祫閲戞婚涓:10580.000000 鍒╂伅涓:580.000000
绛旓細include<stdio.h>銆銆double fun(double p,double i,int n)銆銆{銆銆double f=p;銆銆int m;銆銆for(m=n;m>0;m--)銆銆f*=(1+i);銆銆return f;銆銆}銆銆void main()銆銆{銆銆int n;銆銆double p,i;銆銆printf("瀛樻閲戦/鍏");銆銆scanf("%lf",&p);銆銆printf("骞村埄鐜锛...
绛旓細缁,宸茬粡缂栬瘧杩愯纭锛歩nclude<conio.h> include<stdio.h> int main(){ double capital,deposit,rate,temp=1.0;int n,i;printf("璇疯緭鍏ュ瓨娆炬湰閲慶apital: ");scanf("%lf",&capital);printf("璇疯緭鍏ュ畾鏈熷瓨娆剧殑骞村埄鐜rate(璇疯緭鍏%鍓嶇殑鍊,渚嬪rate涓2.25%鏃,璇疯緭鍏2.25): ");scanf("%lf",...
绛旓細绀轰緥浠ｇ爜濡備笅锛歩nclude<stdio.h> main(){ int n,capital;float rate,deposit;printf("input n,capital,rate:");scanf("%d%d%f",&n,&capital,&rate);deposit=capital + capital*n*(float)rate;printf("depsit=%f\n",deposit);return 0;} ...
绛旓細鏈堟伅鍒╃巼 锛 0.345% 鏈熼檺涓夊勾 0.375% 鏈熼檺浜斿勾 0.420% 鏈熼檺鍏勾 瑕佹眰杈撳叆瀛橀挶鐨勬湰閲戝拰鏈熼檺锛屾眰鍒版湡鏃惰兘浠閾惰寰楀埌鐨鍒╂伅涓庢湰閲戠殑鍚堣銆傘4.2銆戣緭鍏ュ勾浠統ear鍜屾湀month锛屾眰璇ユ湀鏈夊灏戝ぉ銆傚垽鏂槸鍚︿负闂板勾锛屽彲鐢ㄥ涓C璇█琛ㄨ揪寮忥細year%4==0 && year0!=0 || year@0==0銆傝嫢琛ㄨ揪寮忔垚绔嬶紙鍗宠〃杈惧紡...
绛旓細int n;float y=0.0175*x,sum;for(n=1;n<15;n++){x+=0.08*xy+=0.175*x;}printf("瀛樺叆鐜伴噾%f,鍙緱鍒╂伅%f,瀹冧滑涔嬪拰%f",12*x,12*y,12*(x+y));}int main(){printf("鍏跺浣欑殑閽辨槸绗竴骞存瘡鏈2000鍏冿紝浠ュ悗姣忓勾姣忔湀澶氫綑鐨勯挶鍦ㄤ笂涓骞撮槦姣忔湀澶氫綑閽辩殑鍩虹涓婂啀澧炲姞8%锛屾椿鏈熸湀鎭负0....
绛旓細009,0.01,0.0111,0.012}; int n; printf("璇疯緭鍏ユ湰閲戝拰鏈熼檺(骞)\n"); scanf("%lf%d",&capital,&n); if(n>3) money=capital*pow((1+rate[3]),12*n); else money=capital*pow((1+rate[n-1]),12*n); printf("%d骞村悗鏈噾鍜鍒╂伅鍚堣涓猴細%.2lf\n",n,money); } ...
绛旓細i]=max(put_in(0.69,save[i-3],3),save[i]);if(i>=5)save[i]=max(put_in(0.75,save[i-5],5),save[i]);if(i>=8)save[i]=max(put_in(0.84,save[i-8],8),save[i]);}printf("%lf",save[20]-save[0]);}杈撳嚭鐨勬槸20骞存墍寰楃殑鏈澶鍒╂伅鍏蜂綋杩囩▼璇稤P+memorize ...
