关于sin,cos,tan 三角函数sin，cos，tan各等于什么边比什么边
tan \u548csin cos\u4ec0\u4e48\u5173\u7cfbtan \u548csin cos\u7684\u5173\u7cfb\u662f\u4e09\u89d2\u51fd\u6570\u5173\u7cfb\u3002
cos\u662f\u4e34\u8fb9\u6bd4\u659c\u8fb9\uff0csin\u662f\u5bf9\u8fb9\u6bd4\u659c\u8fb9\uff0ctan\u662f\u5bf9\u8fb9\u6bd4\u4e34\u8fb9\u3002
\u4e24\u89d2\u548c\u516c\u5f0f\uff1a
sin(A+B)=sinAcosB+cosAsinB
sin(A-B)=sinAcosB-sinBcosA
cos(A+B)=cosAcosB-sinAsinB
cos(A-B)=cosAcosB+sinAsinB
tan(A+B)=(tanA+tanB)/(1-tanAtanB)
tan(A-B)=(tanA-tanB)/(1+tanAtanB)
cot(A+B)=(cotAcotB-1)/(cotB+cotA)
cot(A-B)=(cotAcotB+1)/(cotB-cotA)\u500d\u89d2\u516c\u5f0f tan2A=2tanA/[1-(tanA)^2]
cos2a=(cosa)^2-(sina)^2=2(cosa)^2 -1=1-2(sina)^2
sin2A=2sinA*cosA\u4e09\u500d\u89d2\u516c\u5f0fsin3a=3sina-4(sina)^3
cos3a=4(cosa)^3-3cosa
tan3a=tana*tan(\u03c0/3+a)*tan(\u03c0/3-a)
\u534a\u89d2\u516c\u5f0f \uff1a
sin(A/2)=\u221a((1-cosA)/2) sin(A/2)=-\u221a((1-cosA)/2)
cos(A/2)=\u221a((1+cosA)/2) cos(A/2)=-\u221a((1+cosA)/2)
tan(A/2)=\u221a((1-cosA)/((1+cosA)) tan(A/2)=-\u221a((1-cosA)/((1+cosA))
cot(A/2)=\u221a((1+cosA)/((1-cosA)) cot(A/2)=-\u221a((1+cosA)/((1-cosA)) ?
tan(A/2)=(1-cosA)/sinA=sinA/(1+cosA)\u548c\u5dee\u5316\u79ef 2sinAcosB=sin(A+B)+sin(A-B)
2cosAsinB=sin(A+B)-sin(A-B) )
2cosAcosB=cos(A+B)+cos(A-B)
-2sinAsinB=cos(A+B)-cos(A-B)
sinA+sinB=2sin((A+B)/2)cos((A-B)/2
cosA+cosB=2cos((A+B)/2)sin((A-B)/2)
tanA+tanB=sin(A+B)/cosAcosB
\u79ef\u5316\u548c\u5dee\u516c\u5f0f\uff1a
sin(a)sin(b)=-1/2*[cos(a+b)-cos(a-b)]
cos(a)cos(b)=1/2*[cos(a+b)+cos(a-b)]
sin(a)cos(b)=1/2*[sin(a+b)+sin(a-b)]\u8bf1\u5bfc\u516c\u5f0fsin(-a)=-sin(a)
cos(-a)=cos(a)
sin(pi/2-a)=cos(a)
cos(pi/2-a)=sin(a)
sin(pi/2+a)=cos(a)
cos(pi/2+a)=-sin(a)
sin(pi-a)=sin(a)
cos(pi-a)=-cos(a)
sin(pi+a)=-sin(a)
cos(pi+a)=-cos(a)
tgA=tanA=sinA/cosA\u4e07\u80fd\u516c\u5f0fsin(a)= (2tan(a/2))/(1+tan^2(a/2))
cos(a)= (1-tan^2(a/2))/(1+tan^2(a/2))
tan(a)= (2tan(a/2))/(1-tan^2(a/2))
\u5176\u5b83\u516c\u5f0f\uff1a
a*sin(a)+b*cos(a)=sqrt(a^2+b^2)sin(a+c) [\u5176\u4e2d\uff0ctan(c)=b/a]
a*sin(a)-b*cos(a)=sqrt(a^2+b^2)cos(a-c) [\u5176\u4e2d\uff0ctan(c)=a/b] 1+sin(a)=(sin(a/2)+cos(a/2))^2
1-sin(a)=(sin(a/2)-cos(a/2))^2
\u5176\u4ed6\u975e\u91cd\u70b9\u4e09\u89d2\u51fd\u6570csc(a)=1/sin(a) sec(a)=1/cos(a)
\u6269\u5c55\u8d44\u6599
\u4e3e\u4f8b\uff1a
sin\uff1a\u76f4\u89d2\u4e09\u89d2\u5f62\u4e2d\u89d2\u7684\u6b63\u5f26\u51fd\u6570
cos\uff1a\u76f4\u89d2\u4e09\u89d2\u5f62\u4e2d\u89d2\u7684\u4f59\u5f26\u51fd\u6570
tan\uff1a\u76f4\u89d2\u4e09\u89d2\u5f62\u4e2d\u89d2\u7684\u6b63\u5207\u51fd\u6570
\u5df2\u77e5tan+1/tan\u03b8=2\uff0c\u6c42\uff1asin\u03b8cos\u03b8 \uff1bsin\u03b8+cos\u03b8\uff1bsin\u4e09\u6b21\u65b9\u03b8+cos\u4e09\u6b21\u65b9\u03b8tan\u03b8+1
tan+1/tan\u03b8=2
tan²\u03b8-2tan\u03b8+1=0
tan\u03b8=1
sin\u03b8=\u6839\u53f72/2\uff0ccos\u03b8=\u6839\u53f72/2
\u6216
sin\u03b8=-\u6839\u53f72/2\uff0ccos\u03b8=-\u6839\u53f72/2
\u2234sin\u03b8cos\u03b8=\u00b11/2
sin\u03b8+cos\u03b8=\u00b1\u6839\u53f72
\u53c2\u8003\u8d44\u6599\uff1a\u767e\u5ea6\u767e\u79d1\u2014\u4e09\u89d2\u51fd\u6570\u5173\u7cfb
\u5728\u76f4\u89d2\u4e09\u89d2\u5f62\u4e2d\uff0c\u4e09\u89d2\u51fd\u6570sin\u3001cos\u548ctan\u53ef\u4ee5\u88ab\u5b9a\u4e49\u4e3a\u4ee5\u4e0b\u6bd4\u503c\uff1a
1. \u6b63\u5f26\uff08sin\uff09\uff1a\u5b9a\u4e49\u4e3a\u4e09\u89d2\u5f62\u7684\u5bf9\u8fb9\u4e0e\u659c\u8fb9\u4e4b\u6bd4\u3002\u5373 sin(\u03b8) = \u5bf9\u8fb9 / \u659c\u8fb9\u3002
2. \u4f59\u5f26\uff08cos\uff09\uff1a\u5b9a\u4e49\u4e3a\u4e09\u89d2\u5f62\u7684\u90bb\u8fb9\u4e0e\u659c\u8fb9\u4e4b\u6bd4\u3002\u5373 cos(\u03b8) = \u90bb\u8fb9 / \u659c\u8fb9\u3002
3. \u6b63\u5207\uff08tan\uff09\uff1a\u5b9a\u4e49\u4e3a\u4e09\u89d2\u5f62\u7684\u5bf9\u8fb9\u4e0e\u90bb\u8fb9\u4e4b\u6bd4\u3002\u5373 tan(\u03b8) = \u5bf9\u8fb9 / \u90bb\u8fb9\u3002
\u8fd9\u4e9b\u5b9a\u4e49\u662f\u57fa\u4e8e\u76f4\u89d2\u4e09\u89d2\u5f62\u4e2d\u7684\u76f8\u5173\u957f\u5ea6\u5173\u7cfb\u5bfc\u51fa\u7684\u3002\u5176\u4e2d\uff0c\u659c\u8fb9\u662f\u76f4\u89d2\u4e09\u89d2\u5f62\u7684\u659c\u8fb9\uff08\u5373\u6700\u957f\u7684\u4e00\u8fb9\uff09\uff0c\u5bf9\u8fb9\u662f\u6307\u4e0e\u7ed9\u5b9a\u89d2\u5ea6\u03b8\u76f8\u5bf9\u5e94\u7684\u76f4\u89d2\u4e09\u89d2\u5f62\u4e2d\u4e0e\u8be5\u89d2\u5ea6\u76f8\u5bf9\u7684\u8fb9\uff0c\u90bb\u8fb9\u662f\u4e0e\u7ed9\u5b9a\u89d2\u5ea6\u03b8\u76f8\u90bb\u7684\u8fb9\u3002
\u4e09\u89d2\u51fd\u6570 sin\u3001cos \u548c tan \u5bf9\u5e94\u7684\u5e38\u7528\u516c\u5f0f\u5982\u4e0b
1. \u6b63\u5f26\u51fd\u6570\uff08sin\uff09\uff1a
\u2605\u4f59\u5f26\u5173\u7cfb\uff1asin(\u03b8) = cos(90\u00b0 - \u03b8)
\u2605 \u4e09\u89d2\u6052\u7b49\u5f0f\uff1asin(-\u03b8) = -sin(\u03b8)
\u2605 \u500d\u89d2\u516c\u5f0f\uff1asin(2\u03b8) = 2sin(\u03b8)cos(\u03b8)
\u2605 \u548c\u5dee\u516c\u5f0f\uff1a
\u2606 sin(\u03b1 + \u03b2) = sin(\u03b1)cos(\u03b2) + cos(\u03b1)sin(\u03b2)
\u2606 sin(\u03b1 - \u03b2) = sin(\u03b1)cos(\u03b2) - cos(\u03b1)sin(\u03b2)
2. \u4f59\u5f26\u51fd\u6570\uff08cos\uff09\uff1a
\u2605 \u6b63\u5f26\u5173\u7cfb\uff1acos(\u03b8) = sin(90\u00b0 - \u03b8)
\u2605 \u4e09\u89d2\u6052\u7b49\u5f0f\uff1acos(-\u03b8) = cos(\u03b8)
\u2605 \u500d\u89d2\u516c\u5f0f\uff1acos(2\u03b8) = cos²(\u03b8) - sin²(\u03b8)
\u2605 \u548c\u5dee\u516c\u5f0f\uff1a
\u2606 cos(\u03b1 + \u03b2) = cos(\u03b1)cos(\u03b2) - sin(\u03b1)sin(\u03b2)
\u2606 cos(\u03b1 - \u03b2) = cos(\u03b1)cos(\u03b2) + sin(\u03b1)sin(\u03b2)
3. \u6b63\u5207\u51fd\u6570\uff08tan\uff09\uff1a
\u2605 \u6b63\u5207\u5173\u7cfb\uff1atan(\u03b8) = sin(\u03b8) / cos(\u03b8)
\u2605 \u4e09\u89d2\u6052\u7b49\u5f0f\uff1atan(-\u03b8) = -tan(\u03b8)
\u2605 \u500d\u89d2\u516c\u5f0f\uff1atan(2\u03b8) = 2tan(\u03b8) / (1 - tan²(\u03b8))
\u2605 \u548c\u5dee\u516c\u5f0f\uff1a
\u2606 tan(\u03b1 + \u03b2) = (tan(\u03b1) + tan(\u03b2)) / (1 - tan(\u03b1)tan(\u03b2))
\u2606 tan(\u03b1 - \u03b2) = (tan(\u03b1) - tan(\u03b2)) / (1 + tan(\u03b1)tan(\u03b2))
\u8fd9\u4e9b\u516c\u5f0f\u5728\u89e3\u4e09\u89d2\u65b9\u7a0b\u3001\u6c42\u89e3\u4e09\u89d2\u51fd\u6570\u503c\u3001\u5316\u7b80\u590d\u6742\u8868\u8fbe\u5f0f\u7b49\u95ee\u9898\u4e2d\u975e\u5e38\u6709\u7528\u3002\u5b83\u4eec\u63d0\u4f9b\u4e86\u5bf9\u4e09\u89d2\u51fd\u6570\u4e4b\u95f4\u5173\u7cfb\u7684\u7406\u89e3\u548c\u8fd0\u7528\u3002
\u4e09\u89d2\u51fd\u6570 sin\u3001cos \u548c tan \u7684\u5e94\u7528\u793a\u4f8b
1. \u51e0\u4f55\u5b66\uff1a\u4e09\u89d2\u51fd\u6570\u53ef\u4ee5\u7528\u4e8e\u89e3\u51b3\u4e0e\u51e0\u4f55\u5f62\u72b6\u548c\u89d2\u5ea6\u76f8\u5173\u7684\u95ee\u9898\u3002\u4f8b\u5982\uff0c\u4f7f\u7528\u4e09\u89d2\u51fd\u6570\u53ef\u4ee5\u8ba1\u7b97\u4e09\u89d2\u5f62\u7684\u8fb9\u957f\u3001\u89d2\u5ea6\u548c\u9762\u79ef\uff0c\u4ee5\u53ca\u89e3\u51b3\u76f4\u7ebf\u548c\u5e73\u9762\u4e4b\u95f4\u7684\u65cb\u8f6c\u5173\u7cfb\u3002
2. \u7269\u7406\u5b66\uff1a\u4e09\u89d2\u51fd\u6570\u5728\u7269\u7406\u5b66\u4e2d\u7684\u5e94\u7528\u975e\u5e38\u5e7f\u6cdb\u3002\u4f8b\u5982\uff0c\u8fd0\u52a8\u5b66\u4e2d\u7684\u4f4d\u79fb\u3001\u901f\u5ea6\u548c\u52a0\u901f\u5ea6\u53ef\u4ee5\u7528\u4e09\u89d2\u51fd\u6570\u8fdb\u884c\u63cf\u8ff0\u548c\u8ba1\u7b97\u3002\u6b64\u5916\uff0c\u5728\u6ce2\u52a8\u3001\u632f\u52a8\u3001\u529b\u5b66\u548c\u7535\u78c1\u5b66\u7b49\u9886\u57df\uff0c\u4e09\u89d2\u51fd\u6570\u4e5f\u88ab\u5e7f\u6cdb\u5e94\u7528\u3002
3. \u5de5\u7a0b\u5b66\uff1a\u5de5\u7a0b\u5b66\u4e2d\u7ecf\u5e38\u4f7f\u7528\u4e09\u89d2\u51fd\u6570\u6765\u89e3\u51b3\u5404\u79cd\u95ee\u9898\u3002\u4f8b\u5982\uff0c\u5728\u5efa\u7b51\u548c\u571f\u6728\u5de5\u7a0b\u4e2d\uff0c\u4f7f\u7528\u4e09\u89d2\u51fd\u6570\u6765\u8ba1\u7b97\u5730\u5f62\u7684\u5761\u5ea6\u548c\u89d2\u5ea6\uff0c\u6d4b\u91cf\u8ddd\u79bb\u548c\u9ad8\u5ea6\uff0c\u4ee5\u53ca\u8bbe\u8ba1\u6865\u6881\u548c\u5efa\u7b51\u7269\u7684\u7ed3\u6784\u3002
4. \u5bfc\u822a\u548c\u822a\u6d77\uff1a\u4e09\u89d2\u51fd\u6570\u5728\u5bfc\u822a\u548c\u822a\u6d77\u4e2d\u662f\u4e0d\u53ef\u6216\u7f3a\u7684\u5de5\u5177\u3002\u4f7f\u7528\u4e09\u89d2\u51fd\u6570\u53ef\u4ee5\u8ba1\u7b97\u8239\u53ea\u6216\u98de\u673a\u7684\u4f4d\u7f6e\u3001\u65b9\u5411\u548c\u901f\u5ea6\uff0c\u4ee5\u53ca\u89e3\u51b3\u5bfc\u822a\u8def\u5f84\u89c4\u5212\u548c\u5b9a\u4f4d\u95ee\u9898\u3002
5. \u4fe1\u53f7\u5904\u7406\uff1a\u4e09\u89d2\u51fd\u6570\u5728\u4fe1\u53f7\u5904\u7406\u9886\u57df\u5177\u6709\u91cd\u8981\u4f5c\u7528\u3002\u4f8b\u5982\uff0c\u5728\u97f3\u9891\u548c\u56fe\u50cf\u5904\u7406\u4e2d\uff0c\u4f7f\u7528\u4e09\u89d2\u51fd\u6570\u6765\u8fdb\u884c\u4fe1\u53f7\u7684\u53d8\u6362\u3001\u6ee4\u6ce2\u548c\u9891\u8c31\u5206\u6790\u3002
6. \u7edf\u8ba1\u5b66\uff1a\u4e09\u89d2\u51fd\u6570\u5728\u7edf\u8ba1\u5b66\u4e2d\u7684\u5e94\u7528\u4e5f\u5f88\u5e38\u89c1\u3002\u4f8b\u5982\uff0c\u5728\u56de\u5f52\u5206\u6790\u548c\u65f6\u95f4\u5e8f\u5217\u5206\u6790\u4e2d\uff0c\u4f7f\u7528\u4e09\u89d2\u51fd\u6570\u6765\u5efa\u6a21\u548c\u9884\u6d4b\u6570\u636e\u7684\u5468\u671f\u6027\u548c\u8d8b\u52bf\u3002
\u4e09\u89d2\u51fd\u6570 sin\u3001cos \u548c tan \u7684\u4f8b\u9898
1. \u95ee\u9898\uff1a\u5df2\u77e5\u89d2\u5ea6 A \u7684\u6b63\u5f26\u503c\u4e3a 0.6\uff0c\u6c42\u89d2\u5ea6 A \u7684\u4f59\u5f26\u503c\u548c\u6b63\u5207\u503c\u3002
\u89e3\u7b54\uff1a
\u6b63\u5f26\u503c sin(A) = 0.6
\u7531\u4e09\u89d2\u6052\u7b49\u5f0f sin²(A) + cos²(A) = 1\uff0c\u53ef\u4ee5\u5f97\u5230 cos(A) = \u00b1sqrt(1 - sin²(A))
\u56e0\u4e3a\u89d2\u5ea6 A \u5728\u7b2c\u4e00\u8c61\u9650\uff0c\u6240\u4ee5 cos(A) > 0
\u6240\u4ee5 cos(A) = sqrt(1 - 0.6²) = sqrt(1 - 0.36) = sqrt(0.64) = 0.8
\u6b63\u5207\u503c tan(A) = sin(A) / cos(A) = 0.6 / 0.8 = 0.75
2. \u95ee\u9898\uff1a\u5df2\u77e5\u6b63\u5f26\u503c sin(B) = 0.8\uff0c\u6c42\u89d2\u5ea6 B \u7684\u4f59\u5f26\u503c\u548c\u6b63\u5207\u503c\u3002
\u89e3\u7b54\uff1a
\u6b63\u5f26\u503c sin(B) = 0.8
\u7531\u4e09\u89d2\u6052\u7b49\u5f0f sin²(B) + cos²(B) = 1\uff0c\u53ef\u4ee5\u5f97\u5230 cos(B) = \u00b1sqrt(1 - sin²(B))
\u56e0\u4e3a\u89d2\u5ea6 B \u5728\u7b2c\u4e00\u8c61\u9650\uff0c\u6240\u4ee5 cos(B) > 0
\u6240\u4ee5 cos(B) = sqrt(1 - 0.8²) = sqrt(1 - 0.64) = sqrt(0.36) = 0.6
\u6b63\u5207\u503c tan(B) = sin(B) / cos(B) = 0.8 / 0.6 = 1.33
3. \u95ee\u9898\uff1a\u5df2\u77e5\u89d2\u5ea6 C \u7684\u4f59\u5f26\u503c\u4e3a 0.4\uff0c\u6c42\u89d2\u5ea6 C \u7684\u6b63\u5f26\u503c\u548c\u6b63\u5207\u503c\u3002
\u89e3\u7b54\uff1a
\u4f59\u5f26\u503c cos(C) = 0.4
\u7531\u4e09\u89d2\u6052\u7b49\u5f0f sin²(C) + cos²(C) = 1\uff0c\u53ef\u4ee5\u5f97\u5230 sin(C) = \u00b1sqrt(1 - cos²(C))
\u56e0\u4e3a\u89d2\u5ea6 C \u5728\u7b2c\u4e00\u8c61\u9650\uff0c\u6240\u4ee5 sin(C) > 0
\u6240\u4ee5 sin(C) = sqrt(1 - 0.4²) = sqrt(1 - 0.16) = sqrt(0.84) \u2248 0.92
\u6b63\u5207\u503c tan(C) = sin(C) / cos(C) = 0.92 / 0.4 = 2.3
cos：邻比斜，30：（根号3）/2，60：1/2，90：0。
tan：对比邻，30：（根号3）/3，60：根号3，90：不存在。
在直角三角形中，某锐角的三角函数为：
如,
sinA=对边/斜边，sin30°=1/2;sin45°=√2/2,sin60=√3/2,sin90°=1；
cosA=邻边/斜边，cos30°=√3/2,cos45=√2/2,cos60=1/2,cos90°=0；
tanA=对边/邻边，tan30°=√3/3,tan45°=1,tan60°=3,tan90°不存在。
sin是对边比斜边
tan是对边比邻边
cos是邻边比斜边
sin30度是1/2
sin45度是根号2比2
sin60度是根号3/2
tan30是根号3/3
tan45度是1
tan60是根号3
cos30度是根号3/2
cos45度是根号2/2
cos60度是1/2
绛旓細sin锛氬姣旀枩锛30锛1/2锛60锛氾紙鏍瑰彿3锛/2锛90锛1 銆cos锛氶偦姣旀枩锛30锛氾紙鏍瑰彿3锛/2锛60锛1/2锛90锛0銆tan锛氬姣旈偦锛30锛氾紙鏍瑰彿3锛/3锛60锛氭牴鍙3锛90锛氫笉瀛樺湪銆
绛旓細sin鏄繖涓鐨勫杈瑰拰鏂滆竟鐨勬瘮銆cos涓鏄繖涓鎸ㄧ潃鐨勯偅鏉¤竟鍜屾枩杈圭殑姣旓紱tan鏄繖涓鐨勫杈瑰拰閭昏竟鐨勬瘮銆傚湪骞抽潰鐩磋鍧愭爣绯粁Oy涓鈭犖茬殑濮嬭竟涓簒杞寸殑姝ｅ崐杞达紝璁剧偣P锛坸锛寉锛変负鈭犖茬殑缁堣竟涓婁笉涓庡師鐐筄閲嶅悎鐨勪换鎰忎竴鐐癸紝璁緍=OP锛屼护鈭犖=鈭犖憋紝鍒欙細sin a=y/r锛沜os a=x/r銆
绛旓細姝ｅ鸡(sin)绛変簬瀵硅竟姣旀枩杈;sinA=a/c锛涗綑寮(cos)绛変簬閭昏竟姣旀枩杈;cosA=b/c锛涙鍒(tan)绛変簬瀵硅竟姣旈偦杈;tanA=a/b銆
绛旓細sin cos tan鍏紡鏄細sin搴︽暟鍏紡锛歴in30掳= 1/2锛泂in45掳=鏍瑰彿2/2锛泂in60掳= 鏍瑰彿3/2銆俢os搴︽暟鍏紡锛歝os30掳=鏍瑰彿3/2锛沜os45掳=鏍瑰彿2/2锛沜os60掳=1/2銆倀an搴︽暟鍏紡锛歵an30掳=鏍瑰彿3/3锛泃an45掳=1锛泃an60掳=鏍瑰彿3銆傛寮︽鍒囷細鐩磋涓夎褰腑锛屸垹A锛堥潪鐩磋锛夌殑瀵硅竟涓庢枩杈圭殑姣斿彨鍋氣垹A鐨...
绛旓細鍦ㄧ洿瑙掍笁瑙掑舰涓紝涓夎鍑芥暟sin銆cos鍜tan鍙互琚畾涔変负浠ヤ笅姣斿硷細1. 姝ｅ鸡锛坰in锛夛細瀹氫箟涓轰笁瑙掑舰鐨勫杈逛笌鏂滆竟涔嬫瘮銆傚嵆 sin(胃) = 瀵硅竟 / 鏂滆竟銆2. 浣欏鸡锛坈os锛夛細瀹氫箟涓轰笁瑙掑舰鐨勯偦杈逛笌鏂滆竟涔嬫瘮銆傚嵆 cos(胃) = 閭昏竟 / 鏂滆竟銆3. 姝ｅ垏锛坱an锛夛細瀹氫箟涓轰笁瑙掑舰鐨勫杈逛笌閭昏竟涔嬫瘮銆傚嵆 tan(胃) = ...
绛旓細1銆佹寮 鍦ㄧ洿瑙掍笁瑙掑舰涓紝浠绘剰涓閿愯鈭燗鐨勫杈逛笌鏂滆竟鐨勬瘮鍙仛鈭燗鐨勬寮︼紝璁颁綔sinA锛屽嵆sinA=鈭燗鐨勫杈/鏂滆竟銆2銆佷綑寮 鍦ㄧ洿瑙掍笁瑙掑舰涓紝浠绘剰涓閿愯鈭燗鐨勪复杈逛笌鏂滆竟鐨勬瘮鍙仛鈭燗鐨勪綑寮︼紝璁颁綔cosA锛屽嵆cosA=鈭燗鐨勪复杈/鏂滆竟銆3銆佹鍒 鍦ㄧ洿瑙掍笁瑙掑舰涓紝浠绘剰涓閿愯鈭燗鐨勫杈逛笌涓磋竟鐨勬瘮鍙仛鈭燗鐨勬鍒囷紝...
绛旓細sin锛歴ine 鐨勭畝鍐欙紝璇婚煶/saɪn/(璧涘洜)"璧"閲嶈锛"鍥"杞昏銆cos锛歝osine 鐨勭畝鍐欙紝璇婚煶 鑻/ˈkəʊsaɪn/ 缇/ˈkoʊsaɪn/(鎵ｈ禌鍥)"鎵"閲嶈,"璧涘洜"杞昏銆tan锛歵angent 鐨勭畝鍐欙紝璇婚煶 鑻/ˈtændʒənt/ 缇/ˈt&#...
绛旓細sin鏄寮﹀硷紝cos鏄綑寮﹀笺sin, cos, tan閮芥槸涓夎鍑芥暟锛屽垎鍒彨鍋氣滄寮︹濄佲滀綑寮︹濄佲滄鍒団濄傚湪鍒濅腑闃舵锛岃繖涓や釜涓夎鍑芥暟鏄繖鏍疯В閲婄殑:鍦ㄤ竴涓洿瑙掍笁瑙掑舰涓紝璁锯垹C=90掳锛屸垹A,B,C 鎵瀵圭殑杈瑰垎鍒浣渁,b,c锛 閭ｄ箞瀵逛簬閿愯鈭燗,瀹冪殑瀵硅竟a鍜屾枩杈筩鐨勬瘮鍊糰/c 鍙仛鈭燗鐨勬寮︼紝璁颁綔sinA; 瀹...
绛旓細瀹冧滑閮芥槸鍦ㄤ笁瑙掑嚱鏁伴噷浣跨敤鐨勩tan 灏辨槸姝ｅ垏鐨勬剰鎬濓紝鐩磋涓夎鍑芥暟涓紝閿愯瀵瑰簲鐨勮竟璺熷彟涓鏉＄洿瑙掕竟鐨勬瘮銆cos 灏辨槸浣欏鸡鐨勬剰鎬濓紝閿愯鐩搁偦鐨勯偅鏉＄洿瑙掕竟涓庢枩杈圭殑姣斻sin 灏辨槸姝ｅ鸡鐨勬剰鎬濓紝閿愯瀵瑰簲鐨勮竟涓庢枩杈圭殑杈广
绛旓細sincostan鍏崇郴瀵硅竟鍙ｈ瘈濡備笅锛氭寮in=瀵硅竟姣旀枩杈广佷綑寮os=閭昏竟姣旀枩杈广佹鍒噒an=瀵硅竟姣旈偦杈广俿in銆乧os銆乼an鍏崇郴瀵硅竟锛歴inA=a/c锛宑osA=b/c锛宼anA=a/b锛屼笁瑙掑嚱鏁版槸鍩烘湰鍒濈瓑鍑芥暟涔嬩竴锛屾槸浠ヨ搴︿负鑷彉閲忥紝瑙掑害瀵瑰簲浠绘剰瑙掔粓杈逛笌鍗曚綅鍦嗕氦鐐瑰潗鏍囨垨鍏舵瘮鍊间负鍥犲彉閲忕殑鍑芥暟銆備篃鍙互绛変环鍦扮敤涓庡崟浣嶅渾鏈夊叧鐨勫悇绉...
