用c语言中*号表示出一个爱心,并在爱心中穿插着文字,怎么弄? 用C语言编一个程序,使之用“*”打印出一个爱心的图案

\u5982\u4f55\u7528C\u8bed\u8a00\u5148\u8f93\u51fa\u4e00\u6bb5\u6587\u5b57\u5982\u4f55\u518d\u8f93\u51fa\u5fc3\u5f62\u56fe\u6848\uff1f

#include void heart() {printf(" ** ** \n");printf(" * * * * \n");printf(" * * * \n");printf(" * * \n");printf(" * * \n");printf(" * * \n");printf(" * * \n");printf(" * * \n");printf(" * * \n");printf(" * * \n");printf(" * * \n");printf(" * * \n");printf(" * * \n");printf(" * * \n");printf(" * \n");}int main() {heart();return 0; }

\u4e2a\u4eba\u8ba4\u4e3a\u8fd8\u884c\uff0c7\u4ee5\u4e0a\u6548\u679c\u8f83\u597d\uff0c\u4e0d\u77e5\u9053\u4f60\u8981\u7a7a\u5fc3\u7684\u8fd8\u662f\u5b9e\u5fc3\u7684\uff0c\u90fd\u9644\u4e0a\u5427\uff08\u767e\u5ea6\u77e5\u9053\u597d\u50cf\u628a\u4e24\u4e2a\u7a7a\u683c\u7684\u4f4d\u7f6e\u4e0a\u4f20\u540e\u53d8\u6210\u4e86\u4e00\u4e2a\u7a7a\u683c\uff0c\u4f60\u81ea\u5df1\u8981\u6539\u4e00\u4e0b\uff0c\u8f93\u51fa\u4f4d\u7f6e\u4e3a\u4e00\u4e2a\u7a7a\u683c\u7684\u5168\u90e8\u6539\u6210\u4e24\u4e2a\uff0c\u5176\u4ed6\u7684\u4e0d\u7528\u6539\uff09\uff1a

\u5b9e\u5fc3\u7684\uff1a
#include
int n;
void draw(int n)
{
int i,j;
for (i=1-(n>>1);i<=n;i++)
if (i>=0)
{
for (j=0;j<i;j++) printf(" ");
for (j=1;j<=2*(n-i)+1;j++) printf(" *");
printf("\n");
}
else
{
for (j=i;j<0;j++) printf(" ");
for (j=1;j<=n+2*i+1;j++) printf(" *");
for (j=1;j<=-1-2*i;j++) printf(" ");
for (j=1;j<=n+2*i+1;j++) printf(" *");
printf("\n");
}
}
int main()
{
printf("Please input the size (n>=4):");
scanf("%d",&n);
draw(n);
return 0;
}


\u7a7a\u5fc3\u7684\uff1a
#include
int n;
void draw(int n)
{
int i,j;
for (i=1-(n>>1);i<=n;i++)
if (i>0)
{
for (j=0;j<i;j++) printf(" ");
for (j=1;j<=2*(n-i)+1;j++)
if (j==1||j==2*(n-i)+1) printf(" *");
else printf(" ");
printf("\n");
}
else
if (i==0)
{
printf(" *");
for (j=1;j<n;j++) printf(" ");
printf(" *");
for (j=1;j<n;j++) printf(" ");
printf(" *\n");
}
else
{
for (j=i;j<0;j++) printf(" ");
for (j=1;j<=n+2*i+1;j++)
if (i==1-(n>>1)) printf(" *");
else if (j==1||j==n+2*i+1) printf(" *");
else printf(" ");
for (j=1;j<=-1-2*i;j++) printf(" ");
for (j=1;j<=n+2*i+1;j++)
if (i==1-(n>>1)) printf(" *");
else if (j==1||j==n+2*i+1) printf(" *");
else printf(" ");
printf("\n");
}
}
int main()
{
printf("Please input the size (n>=4):");
scanf("%d",&n);
draw(n);
return 0;
}

最简单的就是你用printf来实现

或者你要用函数来画心就很麻烦了

比如
#include<stdio.h>
void main()
{
    printf("*                 *");
     printf("*               *");
      printf("*             *");
       printf("*           *");
        printf("*         *");
         printf("*        *");
       
}

就这种样子,自己布局吧,如果想用画图函数,要么在tc环境下,要么在vc下获取控制台句柄,调用api,然后写一个画心形的函数



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