请教大虾：C语言里要表示m的n次方怎么表示
\u7528C\u8bed\u8a00\u8868\u793aM\u7684N\u6b21\u65b9\uff1fmain()
{
double a,M,N,sum=1,;
scanf("%f,%f",&M,&N);
for(a=1;a<=(int)N;a++)
sum=sum*M;
printf("s=%f",sum);
}
\u7531\u4e8e\u4e0d\u662f\u6574\u578b,\u6240\u4ee5\u4e0d\u80fd\u7528pow(a,b)\u6765\u641e,\u5982\u679c\u8981\u6c42M\u7684N\u6b21\u65b9,N\u5fc5\u987b\u662f\u6574\u578b\u7684\u624d\u884c,\u6240\u4ee5\u5fc5\u987b\u5f3a\u5236\u8f6c\u6362\u6210\u6574\u578b.~
\u9700\u8981\u51c6\u5907\u7684\u6750\u6599\u5206\u522b\u6709\uff1a\u7535\u8111\u3001C\u8bed\u8a00\u7f16\u8bd1\u5668\u3002
1\u3001\u9996\u5148\uff0c\u6253\u5f00C\u8bed\u8a00\u7f16\u8bd1\u5668\uff0c\u65b0\u5efa\u4e00\u4e2a\u521d\u59cb.cpp\u6587\u4ef6\uff0c\u4f8b\u5982\uff1atest.cpp\u3002
2\u3001\u5728test.cpp\u6587\u4ef6\u4e2d\uff0c\u8f93\u5165C\u8bed\u8a00\u4ee3\u7801\uff1aint n = 5;printf("%lf", pow(10, n)); \u3002
3\u3001\u7f16\u8bd1\u5668\u8fd0\u884ctest.cpp\u6587\u4ef6\uff0c\u6b64\u65f6\u8ba1\u7b97\u51fa\u4e8610\u7684n\u6b21\u65b9\uff0c\u4f8b\u59825\u6b21\u65b9\u3002
然后将 m=power(m,2);
改成 n=pow(m,2);
程序用到了系统函数power,应该加上这个函数所用的到库:math.h.
还有你代码最后的那个while实在想不出来是干什么用的...
绛旓細鏀规垚 n=pow(m,2);
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