C语言从键盘输入任意字符串,以回车符结束 从键盘输入任意字符串,以回车符结束。将字符串保存为中的数字 C语言,如何输入一个以回车结束的字符串??

\u7528C\u8bed\u8a00\u5b9e\u73b0 \u4ece\u952e\u76d8\u8f93\u5165\u4e00\u4e2a\u4e00\u4e2a\u4ee5\u56de\u8f66\u7b26\u7ed3\u675f\u7684\u5b57\u7b26\u4e32\uff0c\u7136\u540e\u5c06\u5176\u9006\u5e8f\u8f93\u51fa

#include
#include

void main()
{
int i, len;
char temp;
char buf[512] = { 0 };

scanf("%s", buf);
len = strlen(buf);

for (i = 0; i < len/2; i++)
{
temp = buf[i];
buf[i] = buf[len - 1 - i];
buf[len - 1 - i] = temp;
}

printf("%s", buf);
}

\u5e93\u51fd\u6570fgets\u628a'\n'\u4f5c\u4e3a\u7ed3\u675f\u547d\u4ee4\uff0c\u540c\u65f6\u4e5f\u5f53\u4f5c\u4e00\u4e2a\u5b57\u7b26\u5b58\u50a8\u5230\u76ee\u6807\u7a7a\u95f4\u91cc\uff0c\u5e76\u5728\u5176\u540e\u52a0\u4e00\u4e2a'\0'\u3002\u6240\u4ee5\u7528fgets\u63a5\u6536\u952e\u76d8\u8f93\u5165\u5c31\u80fd\u65b9\u4fbf\u5730\u8fbe\u5230\u9898\u9762\u7684\u8981\u6c42\u3002\u53ef\u7528\u4e0b\u5217\u4ee3\u7801\u6d4b\u8bd5\uff1a
//#include "stdafx.h"//If the vc++6.0, with this line.#include "stdio.h"int main(void){ char a[100]; fgets(a,100,stdin);//stdin\u8868\u793a\u4ece\u952e\u76d8\u8f93\u5165\u800c\u4e0d\u662f\u4ece\u6587\u4ef6 printf("%s",a);//\u8fd9\u91cc%s\u540e\u6ca1\u6709\n,\u4f46\u8f93\u51fa\u662f\u6709\u56de\u8f66\u7684 return 0;} \u8fd9\u91cc\u4f7f\u7528\u4e86printf("%s",a);(\u8f93\u51fa\u5b57\u7b26\u4e32)\u800c\u975eprintf("%s\n",a);(\u8f93\u51fa\u5b57\u7b26\u4e32\u52a0'\n')\uff0c\u5374\u80fd\u8fbe\u5230\u540e\u8005\u7684\u6548\u679c\uff0c\u662f\u56e0\u4e3afgets\u51fd\u6570\u628a\u6700\u540e\u8f93\u5165\u7684'\n'\u4f5c\u4e3a\u4e00\u4e2a\u5b57\u7b26\u5b58\u50a8\u5728\u5b57\u4e32\u672b\u5c3e\u4e86\uff0c\u5728'\n'\u4e4b\u540e\u624d\u52a0\u4e00\u4e2a'\0'\uff0c\u6240\u4ee5\u8fd9\u91cc\u7684\u56de\u8f66\u662f\u7531\u5b57\u7b26\u4e32\u7684\u6700\u540e\u4e00\u4e2a\u5b57\u7b26'\n'\u4ea7\u751f\u7684\u3002\u6b63\u597d\u8fbe\u5230\u9898\u9762\u7684\u8981\u6c42\u2014\u2014\u201c\u8f93\u5165\u4e00\u4e2a\u4ee5\u56de\u8f66\u7ed3\u675f\u7684\u5b57\u7b26\u4e32\u201d\uff01

#include<stdio.h>
void main() { char str[256],str1[256],str2[256],*p,*q,*r;
  gets(str); p=str1; q=str2; r=str;
  while ( *r ) {
    if ( *r>='0' && *r<='9' ) { *p=*r; p++; }
    else if ( *r>='a' && *r<='z' ) { *q=*r; q++; }
    else if ( *r>='A' && *r<='Z' ) { *q=*r; q++; }
    r++;
  }
  *p=*q=0;
  printf("%s
%s
",str1,str2);
}


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