最近有科学家提出“绿色自由”构想：把空气吹入K2CO3溶液，然后再把CO2从生成物中提取出来，再经过化学反 最近科学家提出“绿色自由”构想：把空气吹入碳酸钾溶液，然后再...
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（1）从图示看出二氧化碳与碳酸钾能反应生成碳酸氢钾，它分解应该是此反应的可逆过程，可循环物质为碳酸钾，故答案为：B（2）从叙述中可以看出反应物是氢气与二氧化碳；生成物是CH30H和H2O，故答案为：3H2+CO2=CH3OH+H2O
绛旓細D 璇曢鍒嗘瀽锛氱敱杞寲鍥惧彲鐭閫夐」纰抽吀閽炬憾娑叉墍璧风殑浣滅敤鏄細瀵岄泦绌烘皵涓殑CO 2 锛屼负鍚堟垚鐢查唶鎻愪緵CO 2 鏄纭殑鍙欒堪锛汢閫夐」鍙惊鐜埄鐢ㄧ殑鐗╄川鏄疜 2 CO 3 鏄纭殑鍙欒堪锛汣閫夐」閫氬叆楂樻俯姘磋捀姘旂殑浣滅敤鏄細鍔犲揩CO 2 鐨勯稿嚭锛屼互渚垮強鏃朵负鍚堟垚濉旀彁渚汣O 2 鏄纭殑鍙欒堪锛汥閫夐」鏄敊璇殑鍙欒堪锛屽弽搴斿墠搴斾负3...
绛旓細锛1锛変粠鍥剧ず鐪嬪嚭浜屾哀鍖栫⒊涓庣⒊閰搁捑鑳藉弽搴旂敓鎴愮⒊閰告阿閽撅紝瀹冨垎瑙ｅ簲璇ユ槸姝ゅ弽搴旂殑鍙嗚繃绋嬶紝鍙惊鐜墿璐ㄤ负纰抽吀閽撅紝鏁呯瓟妗堜负锛欱锛2锛変粠鍙欒堪涓彲浠ョ湅鍑哄弽搴旂墿鏄阿姘斾笌浜屾哀鍖栫⒊锛涚敓鎴愮墿鏄疌H30H鍜孒2O锛屾晠绛旀涓猴細3H2+CO2=CH3OH+H2O
绛旓細鎵浠ュ噺缂撲簡娓╁鏁堝簲锛屾墍浠ヨ鈥滅豢鑹茶嚜鐢辨瀯鎯鈥濈殑浼樼偣鏄細鍚告敹浜屾哀鍖栫⒊锛屽噺缂撴俯瀹ゆ晥搴旓紟鏁呯瓟妗堜负锛氾紙1锛夊惛鏀剁┖姘斾腑鐨勪簩姘у寲纰筹紱锛2锛2KHCO3 鈻 . K2CO3+CO2鈫+H2O锛涳紙3锛塁O2+3H2 300鈩 .2KPaH2O+CH3OH锛
绛旓細锛1锛変粠鍥剧ず鐪嬪嚭浜屾哀鍖栫⒊涓庣⒊閰搁捑鑳藉弽搴旂敓鎴愮⒊閰告阿閽撅紝瀹冨垎瑙ｅ簲璇ユ槸姝ゅ弽搴旂殑鍙嗚繃绋嬶紝鍏跺弽搴旂殑鍖栧鏂圭▼寮忎负锛2KHCO3=K2CO3+H2O+CO2鈫戯紱锛2锛変粠鍙欒堪涓彲浠ョ湅鍑哄弽搴旂墿鏄阿姘斾笌浜屾哀鍖栫⒊锛涚敓鎴愮墿鏄疌H30H鍜孒2O锛屽叾鍙嶅簲鐨勫寲瀛︽柟绋嬪紡涓猴細3H2+CO2=CH3OH+H2O锛涙晠绛旀涓猴細锛1锛2KHCO3 鈻 . K2CO3+H2O+...
绛旓細1mol浜屾哀鍖栫⒊鍜岃冻閲忔阿姘斿弽搴旀斁鍑49.5KJ鐑噺锛屾墍浠ュ叾鐑寲瀛﹀弽搴旀柟绋嬪紡涓猴細CO2锛坓锛+3H2锛坓锛=CH3OH锛坓锛+H2O锛坓锛夆柍H=-49.5KJ/mol锛涙牴鎹悎鎴愮敳閱囩殑鏂圭▼鍙煡锛屽弽搴旂敓鎴愮敳閱囧拰姘磋捀姘旓紝姘磋捀姘斿彲浠ョ粰纰抽吀姘㈤捑鍒嗚В鎻愪緵鑳介噺锛屾墍浠ヨ浆鍖栬繃绋嬩腑鍙惊鐜埄鐢ㄧ殑鐗╄川闄や簡K2CO3澶栵紝杩樻湁姘磋捀姘旓紱鏁呯瓟妗堜负锛欳O2锛坓...
绛旓細浜屾哀鍖栫⒊鍚庨潰鏍囦笂涓婂崌绗﹀彿锛屾墍浠ユ柟绋嬪紡鏄細2KHCO 3 鈻 . K 2 CO 3 +CO 2 鈫+H 2 O锛屾晠B璇存硶姝ｇ‘锛汣銆佺敱棰樻剰鐭ワ紝鍚告敹姹犲唴鍙嶅簲鐗╂槸纰抽吀閽俱佹按銆佷簩姘у寲纰筹紝鐢熸垚鐗╂槸纰抽吀姘㈤捑锛岀敤瑙傚療娉曢厤骞冲嵆鍙紝鎵浠ュ彂鐢熺殑涓昏鍙嶅簲涓篊O 2 +K 2 CO 3 +H 2 O 鈻 . 2KHCO 3 锛屾晠C...
绛旓細瀹僶l-1锛屾晠绛旀涓猴細CO1锛坓锛+yH1锛坓锛=H1O锛坓锛+CHyOH锛坓锛夆柍H=-49.47k鍏/瀹僶l锛涳紙y锛夆憼浠庡钩琛＄Щ鍔ㄥ師鐞嗗垎鏋愶紝浣庢俯鏈夊埄浜庡師鏂欐皵鐨勮浆鍖栵紝浣嗘俯搴﹁秺楂橈紝鍙嶅簲瓒婂揩锛屾墍浠ュ疄闄呯敓浜т腑閲囩敤y00掳C鐨勬俯搴︼紝鏄洜涓哄湪鐢▂00掳C鏃讹紝鍌寲鍓傛椿鎬ф渶e锛屽弽搴旈熺巼鏈蹇紝鏁呴噰鐢ㄦ娓╁害锛屾晠绛旀涓猴細鍔犲揩鍙嶅簲閫熺巼...
绛旓細锛1锛塁O 2 (g)+3H 2 (g) =CH 3 OH(g)+H 2 O(g) 螖H锛-49.47kJ/mol锛 CD 锛2锛2CO 2 +4e - +2H 2 O=2CO+4OH - 锛3锛夛紴锛涘洜涓烘棦瀛樺湪HCO 3 - CO 3 2- +H + 涔熷瓨鍦℉CO 3 - +H 2 O H 2 CO 3 +OH - 鑰孒CO 3 - 鐨勬按瑙ｇ▼搴﹀ぇ浜庣數绂荤▼搴︼紙4锛...
绛旓細鎵浠1mol浜屾哀鍖栫⒊鍜岃冻閲忔阿姘斿弽搴旀斁鍑49.47KJ鐑噺锛屾墍浠ュ叾鐑寲瀛﹀弽搴旀柟绋嬪紡涓篊O2锛坓锛+3H2锛坓锛=CH3OH锛坓锛+H2O锛坓锛夆柍H=-49.47KJ/mol锛庢晠绛旀涓猴細CO2锛坓锛+3H2锛坓锛=CH3OH锛坓锛+H2O锛坓锛夆柍H=-49.47KJ/mol锛庯紙3锛夌敳閱囩噧鏂欑⒈鎬х數姹犱腑锛岀敳閱囧湪璐熸瀬涓婂彂鐢熸哀鍖栧弽搴旓紝鐢查唶澶辩數瀛愬拰姘㈡哀鏍圭瀛...
绛旓細鍦ㄦ棩甯哥敓娲讳腑涔熷彲浠ラ氳繃鐕冪儳鎻愪緵鑳介噺锛屾墍浠ヤ箼閱囧叿鏈夊彲鐕冩э紝閫氳繃绫绘瘮鎬濇兂鍙煡锛岀敳閱囦篃鍏锋湁鍙噧鎬э紱锛5锛夊ぇ姘斾腑鐨勪簩姘у寲纰冲惈閲忓鍔狅紝浼氫娇鍦扮悆琛ㄩ潰鐨勬俯搴﹀崌楂橈紝鍔犲墽娓╁鏁堝簲锛庢晠绛旀涓猴細锛1锛変簩姘у寲纰筹紱锛2锛塁O2+3H2 閾攲鍌寲鍓 . CH3OH+H2O锛涳紙3锛夎川閲忥紱锛4锛夊彲鐕冩э紱锛5锛夋俯瀹わ紟
