python中的字典，列表分别怎样倒过来？ 在python中，列表，字典的相互转换？
python\u7684list()\u51fd\u6570\u628a\u5b57\u5178\u8f6c\u6210\u5217\u8868\uff0c\u5982\u4f55\u4fdd\u6301\u5217\u8868\u539f\u6709\u7684\u987a\u5e8f\uff1f\u5355\u7eaf\u4ece\u6570\u636e\u7ed3\u6784\u4e0a\u6765\u8bb2\u7684\u8bdd\uff0c\u5b57\u5178\u7684\u6570\u636e\u7ed3\u6784\u662f\u6563\u5217\uff0c\u4e5f\u5c31\u662f\u54c8\u5e0c\u8868\uff0c\u5b83\u662f\u65e0\u5e8f\u7684\uff0c\u800c\u5217\u8868\u7684\u6570\u636e\u7ed3\u6784\u662f\u94fe\u8868\uff0c\u662f\u6709\u5e8f\u7684\uff0c\u6240\u4ee5\u60f3\u628a\u5b57\u5178\u8f6c\u6362\u6210\u5217\u8868\u5e76\u4e14\u4fdd\u6301\u987a\u5e8f\u4e0d\u53d8\uff0c\u662f\u4e0d\u53ef\u884c\u7684\u3002
\u9898\u4e3b\u53ef\u4ee5\u4f7f\u7528OrderedDict\uff08Python 2.7+\uff09\u6709\u5e8f\u5b57\u5178\uff0cOrderedDict\u662fdict\u7684\u5b50\u7c7b\uff0c\u5b83\u8bb0\u4f4f\u4e86\u5185\u5bb9\u6dfb\u52a0\u7684\u987a\u5e8f\u3002
\u53e6\u5916\u5982\u679c\u60f3\u628a\u5b57\u5178\u7684key\u8f6c\u6362\u6210\u5217\u8868\uff0c\u4f7f\u7528dict.keys()\u5c31\u53ef\u4ee5\u4e86\u3002
\u4e0b\u9762\u4ee3\u7801\u5217\u8868\u4e2d\u7684\u5185\u5bb9\u548c\u4f60\u7ed9\u7684\u622a\u56fe\u5185\u5bb9\u4e0d\u540c\uff0c\u622a\u56fe\u91cc\u5217\u8868\u5185\u5bb9\u592a\u7e41\u7d22\u4e86\uff0c\u6211\u6309\u7167\u7279\u5f81\u81ea\u5df1\u6362\u4e86\u51e0\u4e2a\u7b80\u5355\u7684\u5185\u5bb9\uff1a
list_code = ['123','456']
list_pic = ['x.jpg','y.jpg']
list_name = ['abc', 'def']
pic1_name1 = [x for x in [list_pic[0],list_name[0]]]
pic2_name2 = [x for x in [list_pic[1],list_name[1]]]
dic1_pic1_name1 = {}
dic2_pic2_name2 = {}
dic1_pic1_name1[list_code[0]] = pic1_name1
dic2_pic2_name2[list_code[1]] = pic2_name2
print(dic1_pic1_name1)
print(dic2_pic2_name2)
\u6267\u884c\u7ed3\u679c\u5982\u56fe:
倒序：
lst = [1, 3, 5]
print(list(reversed(lst)))
print(lst[::-1])
2.dict是不保证顺序的，虽然python3.7以上是默认有序，但不应该假设dict有序
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