C语言编程:编写程序实现,5个学生,每个学生的数据包括学号、姓名、3门课的成绩 C语言编程:编写程序实现,5个学生,每个学生的数据包括学号、...

\u7528C\u8bed\u8a00\u7f16\u5199\u7a0b\u5e8f\uff0c\u5b8c\u6210\u4ee5\u4e0b\u529f\u80fd\uff1a \uff081\uff09 \u67095\u4e2a\u5b66\u751f\uff0c\u6bcf\u4e2a\u5b66\u751f\u7684\u6570\u636e\u5305\u62ec\u5b66\u53f7\u3001\u59d3\u540d\u30013\u95e8\u8bfe\u7684\u6210\u7ee9

#include

#define STUDENT 2

typedef struct tagSTU
{
char name[11] ;
char stunum[11] ;
float score1,score2,score3 ;
float total,aver ;
} STU;

void input(STU *stu, int num) //stu\u4e3a\u5b66\u751f\u6570\u7ec4\u7684\u9996\u5730\u5740\uff0cnum\u4e3a\u6570\u7ec4\u957f\u5ea6
{
int i ;

printf("\u8bf7\u8f93\u5165%d\u4e2a\u5b66\u751f\u7684\u57fa\u672c\u60c5\u51b5: \n",num) ;
printf("\u59d3\u540d \u5b66\u53f7 \u6210\u7ee9\u4e00 \u6210\u7ee9\u4e8c \u6210\u7ee9\u4e09\n") ;
for(i=0; i<num; i++)
{
scanf("%s%s%f%f%f",&stu[i].name,&stu[i].stunum,&stu[i].score1,
&stu[i].score2,&stu[i].score3) ;
}
}

float average(STU *stu, int num) //stu\u4e3a\u5b66\u751f\u6570\u7ec4\u7684\u9996\u5730\u5740\uff0cnum\u4e3a\u6570\u7ec4\u957f\u5ea6\uff0c\u8fd4\u56de\u603b\u5e73\u5747\u6210\u7ee9
{
int i ;
float avertotal = 0 ;

for(i=0; i<num; i++)
{
stu[i].total = 0 ;
stu[i].total = stu[i].score1+stu[i].score2+stu[i].score3 ;
stu[i].aver = stu[i].total/3 ;
avertotal += stu[i].aver ;
}
return avertotal/num ;
}

void max(STU *stu, int num, STU *stuRev, int *stuRevNum) //stu\u4e3a\u5b66\u751f\u6570\u7ec4\u7684\u9996\u5730\u5740\uff0cnum\u4e3a\u6570\u7ec4\u957f\u5ea6
//stuRev\u8868\u793a\u8981\u63a5\u6536\u7684\u6570\u7ec4\uff0cstuRevNum\u8868\u793a\u6700\u7ec8\u63a5\u6536\u7684\u4e2a\u6570\uff0c\u5373\u6700\u9ad8\u6210\u7ee9\u540c\u5b66\u7684\u4e2a\u6570\uff08\u6709\u53ef\u80fd\u4e0d\u6b62\u4e00\u4e2a\u540c\u5b66\uff09
{
STU temp[5] ;
float maxtotal = 0 ;
int i ,temp_index=0 ;

for(i=0; i<num; i++)
{
if(stu[i].total>maxtotal)
{
maxtotal = stu[i].total ;
temp[0] = stu[i] ;
temp_index = 0 ;
}
else if(stu[i].total==maxtotal)
{
temp[++temp_index] = stu[i] ;
}
}
for(i=0;i<=temp_index;i++)
{
stuRev[i] = temp[i] ;
}
*stuRevNum = temp_index+1 ;
}

void main()
{
STU stu[STUDENT] ;
STU stumax[STUDENT] ;
int stumax_num, i ;
float avertotal ;

input(stu,STUDENT) ;
avertotal = average(stu,STUDENT) ;
max(stu,STUDENT,stumax,&stumax_num) ;

//\u8f93\u51fa\u7ed3\u679c
printf("3\u95e8\u8bfe\u603b\u5e73\u5747\u6210\u7ee9: %4.2f\n",avertotal) ;
printf("\u6700\u9ad8\u5206\u540c\u5b66\u6709%d\u4e2a: \n",stumax_num) ;
printf("\u59d3\u540d \u5b66\u53f7 \u6210\u7ee9\u4e00 \u6210\u7ee9\u4e8c \u6210\u7ee9\u4e09 \n") ;
for(i=0; i<stumax_num; i++)
{
printf("%4s %4s %-4.2f %-4.2f %-4.2f\n",stumax[i].name,stumax[i].stunum,
stumax[i].score1,stumax[i].score2,stumax[i].score3) ;
}
}

#include

class Student
{
private:
char xm;
int zch,sx,yy,jsj;

public:
void sum();
void average();
void print();
void get_reg_num();
void set_stu_inf(int,char,int,int,int);
};

void Student::sum()
{
cout<<"\u603b\u5206:"<<sx+yy+jsj<<endl;
}
void Student::average()
{
cout<<"\u5e73\u5747\u5206:"<<(sx+yy+jsj)/3<<endl;
}
void Student::print()
{
cout<<"\u5b66 \u53f7:"<<zch<<endl;
cout<<"\u59d3 \u540d:"<<xm<<endl;
cout<<"\u6570 \u5b66:"<<sx<<endl;
cout<<"\u82f1 \u8bed:"<<yy<<endl;
cout<<"\u8ba1\u7b97\u673a:"<<jsj<<endl;
cout<<"--------------------"<<endl;
}
void Student::get_reg_num()
{
cout<<"\u5b66 \u53f7:"<<zch<<endl;
}
void Student::set_stu_inf(int zc,char x,int s,int y,int j)
{
zch=zc;
xm=x;
sx=s;
yy=y;
jsj=j;
}






void main()
{
Student stu[5];
int zc,s,y,j,i;
char x;
for (i=0;i<5;i++)
{
cout<<"\u8f93\u5165 \u5b66\u53f7:";
cin>>zc;
cout<<"\u8f93\u5165 \u59d3\u540d:";
cin>>x;
cout<<"\u8f93\u5165 \u6570\u5b66\u6210\u7ee9:";
cin>>s;
cout<<"\u8f93\u5165 \u82f1\u8bed\u6210\u7ee9:";
cin>>y;
cout<<"\u8f93\u5165\u8ba1\u7b97\u673a\u6210\u7ee9:";
cin>>j;
stu[i].set_stu_inf(zc,x,s,y,j);
stu[i].print();
}
}

#include "stdafx.h"
#include <stdio.h>

struct student
{
int num;
char name[20];
float sorce[3];
}stu[5];//10个选手

int main(int argc, char* argv[])
{
for(int i=0;i<5;i++)
{
printf("请输入第%d个人的学号,姓名,三门课分数\n",i+1);
scanf("%d%s%f%f%f",&stu[i].num,&stu[i].name,&stu[i].sorce[0],&stu[i].sorce[1],&stu[i].sorce[2]);
}
printf("5个同学的信息为")
for(i=0;i<5;i++)
{
printf("%d\t%s\t%f\t%f\t%f\n",stu[i].num,stu[i].name,stu[i].sorce[0],stu[i].sorce[1],stu[i].sorce[2]);
}
return 0;
}

#include<stdio.h>
main()
{
char xm[5][10] // 存放5个人的姓名
int a[5][3]={0},i,j; // 数组a存储5个人的所有信息,i,j控制下标
printf("请输入5人3门课的成绩:\n");
for(i=0;i<=4;i++) // 输入5个人的成绩
{
a[i][0]=i+1; // 自动获取学号
printf("姓名:");
gets(xm[i]);
printf("请输入学号为 %d 的四门课成绩:",i+1);
for(j=1;j<=4;j++)
scanf("%d",&a[i][j]);
}
printf("\n\n 学生成绩表\n\n");
printf(" 学号 姓名 语文 数学 英语 \n");
for(i=0;i<=4;i++) // 打印5个人的成绩
{
for(j=0;j<=2;j++)
printf("%6d",xm[i],a[i][j]);
printf("\n");
}
}

问题描述的不清楚,建立一个数据表,设置学号\姓名\课程名\成绩四个字段,在程序中用SQL语句对其进行操作.

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