∫cosx/sin^2x不定积分 cosx.sin^2x求定积分
Cosx/sin^2(x) \u7684\u4e0d\u5b9a\u79ef\u5206\u600e\u4e48\u6c42\u222bdx/(sin2xcosx)=\u222bdx/(2sinxcos²x)=\u222b(1/(2sinx(1-sin²x))dx=1/2\u222b[1/sinx + sinx/(1-sin²x)]dx=1/2\u222b(cscx+sinx/cos²x)dx=1/2\u222bcscxdx-1/2\u222b1/cos²x d(cosx)=1/2*ln|cscx-cotx|+1/2*secx+C
\u51d1\u5fae\u5206
∫cos(x)/(sin(x)^2)dx=∫1/(sin(x)^2)dsin(x)
=-1/sin(x)+C
原式等于 积分号1/(Sin[x])^2 * dSin[x]
-Csc[x]+C
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