c语言编程题：从具有10个元素的数组中查找指定值k(k从键盘输入)的下标,并输出。麻烦要源代码 c语言编程 对于一个具有10个元素的数组,先键盘输入数组元素...
C\u8bed\u8a00.\u7531\u952e\u76d8\u8f93\u516510\u4e2a\u6574\u6570\u5b58\u5165\u6570\u7ec4a\u4e2d\uff0c\u518d\u4efb\u610f\u8f93\u5165\u4e00\u4e2a\u6574\u6570k\uff0c\u7136\u540e\u5728\u6570\u7ec4\u4e2d\u67e5\u627ek\u51fa\u73b0\u7684\u6b21\u6570\u8fd9\u6837\uff1a
#include
#define LEN 10
int main(void)
{
int a[LEN], i, k;
int same = 0;
puts("\u8bf7\u8f93\u516510\u4e2a\u6574\u6570\uff1a");
for(i=0; i<LEN; i++)
scanf("%d", &a[i]);
while(getchar() != '\n')
continue;
puts("\u518d\u8f93\u5165\u4e00\u4e2a\u6574\u6570k");
scanf("%d", &k);
for(i=0; i<LEN; i++)
{
if(k == a[i])
same++;
}
printf("k\u4e00\u5171\u51fa\u73b0%d\u6b21\u3002", same);
getchar();
return 0;
}
\u6269\u5c55\u8d44\u6599\uff1a\u6ce8\u610f\u4e8b\u9879
\u5faa\u73af\u8f93\u51fa1-100\u7684\u6240\u6709\u6574\u6570\uff0c\u7528\u6574\u6570%10\uff0c\u7b49\u4e8e9\uff0c\u5373\u6c42\u51fa\u4e86\u6240\u6709\u5404\u4f4d\u662f9\u7684\u4e2a\u6570\uff0c\u7528\u6574\u6570\u966410\uff0c\u5f97\u5230\u4e86\u6240\u6709\u5341\u4f4d\u662f9\u7684\u4e2a\u6570\uff0c\u6709\u4e00\u4e2a\u6570\u5b57\u6bd4\u8f83\u7279\u6b8a\uff0c99\u5e94\u8be5\u7b97\u4e24\u6b21\uff0c\u6240\u4ee5\uff0c\u5e94\u8be5\u7528\u4e24\u4e2a\u5224\u65ad\u8bed\u53e5\u8fdb\u884c\u5224\u65ad\u3002
#include
#include
#include
#include
int main() {
int i = 0;
int count = 0;//\u5b9a\u4e49\u4e00\u4e2a\u8bb0\u5f55\u6b21\u6570\u7684\u53d8\u91cf
for (i = 1; i <= 100; i++) {
if (i % 10 == 9) {
count++;//99\u8fdb\u6765\u4e00\u6b21count++
}
if (i / 10 == 9) {
++count;//99\u8fdb\u6765count++
}
}
printf("1-100\u4e2d\u51fa\u73b09\u7684\u6b21\u6570\u6709%d\u6b21\n", count);
system("pause");
return 0;
}
#include "stdio.h"int main(){ double a[10],sum=0; int i; printf("\u8bf7\u8f93\u5165\u6570\u7ec4\u768410\u4e2a\u5143\u7d20:\n"); for(i=0;i<10;i++) { scanf("%lf",&a[i]); sum+=a[i]; } printf("10\u4e2a\u5143\u7d20\u7684\u548c\u4e3a:%lf\n",sum);}
#include <stdio.h>
int main(void)
{
int a[10]={1,2,3,4,5,6,7,8,9,10};
int i,k;
scanf("%d",&k);
for(i=0;i<10;i++)
{
if(a[i]==k)
{
printf("指定值k的下标是:%d
",i);
break;
}
}
if(i==10)
{
printf("没有一个元素的值等于指定值k!
");
}
return 0;
}
include"stdio.h"
void main( )
{
int a[ ]={0,1,2,3,4,5,6,7,8,9,10};//例如10个元素是0-10；
int k=0;
printf( "请输入要查找的数 K")
scanf("%d"&k);
for(int i=0;i<10;i++)
{
if(k==a[i])
{
printf("输出要查到的树是:%d",a[i])
}
}
}
绛旓細int i, t, s;printf("璇疯緭鍏鍗佷釜鏁!\n");for (i = 0; i < 10; i++){ scanf("%d", &p[i]);} for (i = 0; i < 10; i++){ for(t = i + 1; t < 10; t++){ if (p[i] > p[t]){ s = p[i];p[i] = p[t];p[t] = s;} } } printf("max=%d\...
绛旓細include<stdio.h> int main(){ int a[10],i;printf("input 10 int data\n");for (i=0;i<10;i++) scanf("%d",&a[i]); //杈撳叆10涓 printf("\n");for (i=9;i>=0;i--) printf("%d ",a[i]); //鍊掑簭杈撳嚭 printf("\n");return 0;} 渚嬶細input 10 int data 1...
绛旓細int main(){ int i,p=0,k=0,s1[5],s2[5];int a[10]={1,2,3,4,5,6,7,8,9,0};for(i=0;i<10;i++){ if(a[i]%2==0){ p=p+1;s1[p-1]=a[i];} else { k=k+1;s2[k-1]=a[i];} } for(i=0;i<5;i++){ printf("%d,%d\n",s1[i],s2[i]);} sy...
绛旓細include "stdio.h"void main(){ int a[10],b[10],i,min;printf("璇疯緭鍏10涓鏁存暟锛歕n");for(i=0;i<10;i++)scanf("%d",&a[i]);printf("杈撳叆鐨10涓暣鏁颁负锛歕n");for(i=0;i<10;i++)printf("%d ",a[i]);printf("\n");for(i=0;i<10;i++)b[9-i]=a[i];printf(...
绛旓細include "stdio.h"int main(){ int a[10]={0};int i,tmp;printf("璇疯緭鍏10涓鏁存暟:");for(i=0;i<10;i++)scanf("%d",&a[i]);printf("鏁扮粍a鍊掔疆鍚庤緭鍑:\n");for(i=0;i<5;i++){ tmp=a[i];a[i]=a[9-i];a[9-i]=tmp;} for(i=0;i<10;i++)printf("%d ",a[...
绛旓細include <stdio.h>int main(){char s[10],*p=&s[6];gets(s);while(*p!=0)*(p++)='#';printf("%s",s);return 0;}
绛旓細鍙傝冧唬鐮佸涓嬶細include<stdio.h>void main(){ double data[10],min;printf("Please input 10 numbers:");for(int i=0;i<10;i++){scanf("%lf",&data[i]);}min=data[0];for(int i=0;i<10;i++){if(data[i]<min) min=data[i];}printf("The minute data is :%.2lf",min)...
绛旓細妤间富浣犲ソ锛佹牴鎹綘鐨勮姹備唬鐮佸疄鐜板涓嬶紒include<stdio.h> int main(){ int a[10]={},i,sum=0;printf("璇疯緭鍏10涓暣鏁帮細\n");for(i=0;i<10;i++){ scanf("%d",&a[i]);sum+=a[i];} printf("10涓厓绱鍜屼负锛%d",sum);return 0;} 甯屾湜鎴戠殑鍥炵瓟瀵逛綘鏈甯姪锛
绛旓細include<stdio.h> define N 10 void main() { int a[N],i,max,min,a3,a5,a7; float av;for ( i=0;i<N;i++ ) scanf("%d",&a[i]);max=min=a[0]; for ( i=1;i<N;i++ ) if ( maxa[i] ) min=a[i];a3=a5=a7=0; av=0;for ( i=0;i<N;i++ ) { av+=a...
绛旓細int i=0;i<10;i++){ a[i] =rand()%100+1; printf("%d ",a[i]); } printf("\n杈撳叆涓涓暟锛"); scanf("%d",&x); j= 0; for(int i=0;i<10;i++){ if (a[i] > x) { b[j] = a[i]...
