一个有关圆锥曲线椭圆的内接圆、外接圆以及三点共线的问题,题目见图片,谢谢 如图,一道圆锥曲线椭圆的问题,题目及答案见图片,但答案上画波...

\u4e00\u9053\u6709\u5173\u5706\u9525\u66f2\u7ebf\u692d\u5706\u7684\u5185\u63a5\u5706\u3001\u5916\u63a5\u5706\u4ee5\u53ca\u4e09\u70b9\u5171\u7ebf\u7684\u95ee\u9898\uff0c\u9898\u76ee\u89c1\u56fe\u7247\uff0c\u8c22\u8c22

\u8bbe\u692d\u5706C1\u7684\u957f\u8f74a, \u77ed\u8f74b
\u8bbeP0\u7684\u5750\u6807\u4e3a(m,n)
\u5219m,n\u6ee1\u8db3\uff1am^2/a^2 +n^2/b^2 =1
A\u70b9\u5750\u6807\u4e3a(m,yA), B\u70b9\u5750\u6807\u4e3a(xB,n), \u5176\u4e2d\u7684yA, xB\u5f85\u6c42
\u800c\uff0cyA=\u221a(a^2 -m^2) = a\u221a(1 - m^2/a^2) =a\u221a(n^2/b^2) =an/b
xB=\u221a(b^2 -n^2) =b\u221a(1 - n^2/b^2) =b\u221a(m^2/a^2) =bm/a
\u6240\u4ee5\uff0cOA\u7684\u659c\u7387=yA/m =an/(bm)
OB\u7684\u659c\u7387=n/xB =an/(bm)
\u6240\u4ee5\uff0cOA\u7684\u659c\u7387=OB\u7684\u659c\u7387
\u6240\u4ee5\uff0cO, A, B\u4e09\u70b9\u5171\u7ebf


\u5dee\u4e0d\u591a\u4e86\u5427


上图片



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