555电路多谐振荡频率的计算方法 555电路与RL组成多谐振荡器计算频率？？？
555\u591a\u8c10\u632f\u8361\u7535\u8def\u7684\u5468\u671f\u8ba1\u7b97\u516c\u5f0f\u662f\u591a\u5c111\u3001\u5468\u671f\u8ba1\u7b97\u516c\u5f0f\uff1af = 1 / T = 1.44 / (R1 + 2R2)*C\u3002
2\u3001\u542b\u4e49\uff1af\u4e3a\u9891\u7387\u3001T\u4e3a\u5468\u671f\u3001R1,R2\u4e3a\u7535\u963b\u5927\u5c0f\u3001C\u4e3a\u7535\u5bb9\u5bb9\u91cf\u5927\u5c0f\u3002
\u6269\u5c55\u8d44\u6599\uff1a
\u4e00\u3001\u5f15\u811a\uff1a
1\u30011\u811a:\u5916\u63a5\u7535\u6e90\u8d1f\u7aefVSS\u6216\u63a5\u5730\uff0c\u4e00-\u822c\u60c5\u51b5\u4e0b\u63a5\u5730\u3002
2\u30018\u811a:\u5916\u63a5\u7535\u6e90VCC,\u53cc\u6781\u578b\u65f6\u57fa\u7535\u8defVCC\u7684\u8303\u56f4\u662f4.5 ~ 16V\uff0cCMOS\u578b\u65f6\u57fa\u7535\u8defVCC\u7684\u8303\u56f4\u4e3a3~ 18V\u3002\u4e00\u822c\u75285V\u3002
3\u30013\u811a:\u8f93\u51fa\u7aefVo\u3002
4\u30012\u811a:\u4f4e\u89e6\u53d1\u7aef\u3002
5\u30016\u811a: TH\u9ad8\u89e6\u53d1\u7aef\u3002
6\u30014\u811a:\u662f\u76f4\u63a5\u6e05\u96f6\u7aef\u3002\u5f53\u6b64\u7aef\u63a5\u4f4e\u7535\u5e73\uff0c\u5219\u65f6\u57fa\u7535\u8def\u4e0d\u5de5\u4f5c\uff0c\u6b64\u65f6\u4e0d\u8bbaTR\u3001TH\u5904\u4e8e\u4f55\u7535\u5e73\uff0c\u65f6\u57fa\u7535\u8def\u8f93\u51fa\u4e3a\u201c0\u201d,\u8be5\u7aef\u4e0d\u7528\u65f6\u5e94:\u63a5\u9ad8\u7535\u5e73\u3002
7\u30015\u811a: VC\u4e3a\u63a7\u5236\u7535\u538b\u7aef\u3002\u82e5\u6b64\u7aef\u5916\u63a5\u7535\u538b\uff0c\u5219\u53ef\u6539\u53d8\u5185\u90e8\u4e24\u4e2a\u6bd4\u8f83\u5668\u7684\u57fa\u51c6\u7535\u538b\uff0c\u5f53\u8be5\u7aef\u4e0d\u7528\u65f6\uff0c\u5e94\u5c06\u8be5\u7aef\u4e32\u5165\u4e00\u53ea0.01uF\u7535\u5bb9\u3002
\u4e8c\u3001\u82e5\u89e6\u53d1\u8f93\u5165\u7aefTR\u7684\u7535\u538b,\u5c0f\u4e8eVCC /3\uff0c\u5219\u6bd4\u8f83\u5668C2\u7684\u8f93\u51fa\u4e3a0\uff0c\u53ef\u4f7fRS\u89e6\u53d1\u5668\u7f6e1,\u4f7f\u8f93\u51fa\u7aefOUT=1\u3002\u5982\u679c\u9608\u503c\u8f93\u5165\u7aefTH\u7684\u7535\u538b\u5927\u4e8e2VCC/3\uff0c\u540c\u65f6TR\u7aef\u7684\u7535\u538b\u5927\u4e8eVCC/3\uff0c\u5219C1\u7684\u8f93\u51fa\u4e3a0\uff0cC2\u7684\u8f93\u51fa\u4e3a1,\u53ef\u5c06RS\u89e6\u53d1\u5668\u7f6e0\uff0c\u4f7f\u8f93\u51fa\u4e3a0\u7535\u5e73\u3002
\u53c2\u8003\u8d44\u6599\uff1a\u767e\u5ea6\u767e\u79d1-\u591a\u8c10\u632f\u8361\u5668
\u53c2\u8003\u8d44\u6599\uff1a\u767e\u5ea6\u767e\u79d1-\u8c10\u632f\u7535\u8def
1.\u901a\u8fc7\u8ba1\u7b97cL\u53d6\u503c\u6c42\u9891\u7387\uff0c\u8fd9\u662f\u7406\u8bba\u503c\uff0c\u5b58\u5728\u8f83\u5927\u8bef\u5dee\u3002
2.\u6700\u597d\u7528\u9891\u7387\u8ba1\u6d4b\u51fa\u9891\u7387\u591a\u5c11\uff0c\u7136\u540e\u901a\u8fc7\u9009\u62e9\u5143\u4ef6\u5fae\u6539\u9891\u7387\u3002
放电时间：T2=0.7*R2*C；
振荡周期：T=T1+T2；
振荡频率：f=1/T；
因此有： f=1/0.7（R1+2*R2）C。
如果C选0.01uF，R1选1kΩ，那么要获得20kHz频率，R2 大约为3kΩ左右。
绛旓細鎸崱棰戠巼锛歠=1/T锛涘洜姝ゆ湁锛 f=1/0.7锛圧1+2*R2锛塁銆傚鏋淐閫0.01uF锛孯1閫1k惟锛岄偅涔堣鑾峰緱20kHz棰戠巼锛孯2 澶х害涓3k惟宸﹀彸銆
绛旓細555澶氳皭鎸崱鐢佃矾鐨勫懆鏈熻绠楀叕寮忥細f = 1 / T = 1.44 / (R1 + 2R2)*C銆傦紙娉細鍏朵腑f涓洪鐜囥乀涓哄懆鏈熴丷1,R2涓虹數闃诲ぇ灏忋丆涓虹數瀹瑰閲忓ぇ灏忋傦級555瀹氭椂鍣ㄦ槸涓绉嶆ā鎷熷拰鏁板瓧鍔熻兘鐩哥粨鍚堢殑涓妯￠泦鎴愬櫒浠讹紝璇ュ櫒浠舵垚鏈綆锛屾ц兘鍙潬锛屽彧闇瑕佸鎺ュ嚑涓數闃汇佺數瀹癸紝灏卞彲浠ュ疄鐜板绉嶅姛鑳姐傜敱浜庣數璺畝鍗曞彲闈...
绛旓細鎸崱棰戠巼 f=1.43/[(R1+2R2)C1]瀵逛簬鍥句腑鐢甸樆鐢靛鏁版嵁锛屾尟鑽￠鐜囧疄闄呭 f=1.43脳10³脳10³/[(43+2脳51)脳10³脳2]鈮5Hz
绛旓細T=T1+T2=0.7(R1+2R2)C 鐢佃矾鎸崱棰戠巼f锛璁＄畻鍏紡涓猴細杈撳嚭娉㈠舰鍗犵┖姣攓=T1/T锛屽嵆鑴夊啿瀹藉害涓庤剦鍐插懆鏈熶箣姣旓紝绉颁负鍗犵┖姣斻傝绠楀叕寮忎负锛歲= T1/T=0.7(R1+R2)C/(0.7(R1+2R2)C)=( R1+R2)/( R1+2R2)鐢555瀹氭椂鍣ㄦ瀯鎴澶氳皭鎸崱鍣ㄧ殑鍘熺悊鍥惧鍥1鎵绀恒傚浘1鐢佃矾涓虹敱555瀹氭椂鍣ㄦ瀯鎴愮殑澶氳皭鎸崱鍣ㄣ
绛旓細锛1锛555 澶氳皭鎸崱鍣璁＄畻鍏紡濡備笅锛氳緭鍑洪珮鐢靛钩鏃堕棿 Tph=(R1+R2)Cln2 杈撳嚭浣庣數骞虫椂闂 Tpl=R2Cln2 鎸崱鍛ㄦ湡 T=(R1+2R2)Cln2 鍗犵┖姣 D = Tph / T = (R1+R2) / (R1+2R2)甯﹀叆鏁版嵁锛歍 = (510 + 2 * 10000) * 10^(-8) * 0.693 = 0. 142 mS D = (510 + 1000...
绛旓細555鎸崱棰戠巼鐢卞鎺ョ殑RC鏃堕棿甯告暟纭畾锛岀悊璁轰笂f =0.7/RC锛岀矖鐪嬭捣鏉ュ彧瑕丷銆丆瓒冲澶э紝鎸崱棰戠巼灏辫兘澶熻冻澶熶綆銆備絾鏄疄闄呬笂锛孯瓒婂ぇ锛屽厖锛堟斁锛夌數鐢垫祦灏辫秺灏忥紝C瓒婂ぇ锛屽娍蹇呰閲囩敤鐢佃В鐢靛锛屾紡鐢典篃浼氶殢鐫瀹归噺澧炲ぇ锛屽啀鍔犱笂555鐨2銆6鑴氳緭鍏ョ數闃讳笉鏄棤绌峰ぇ锛屼細娑堣椾竴浜涚數娴侊紝浠ヨ嚦浜嶳鎻愪緵鐨勭數娴佸凡缁忚杩欎簺棰濆鐨...
绛旓細澶氳皭鎸崱鍣ㄤ袱涓殏绋虫佺殑缁存寔鏃堕棿鍙栧喅浜嶳C鍏呫佹斁鐢鍥炶矾鐨鍙傛暟銆傛殏绋虫佲厾鐨勭淮鎸佹椂闂达紝鍗宠緭鍑篤o鐨勬鍚戣剦鍐插搴1鈮0.7(R1+R2)C锛涙殏绋虫佲叀鐨勭淮鎸佹椂闂达紝鍗宠緭鍑篤o鐨勮礋鍚戣剦鍐插搴2鈮0.7R2C銆傚洜姝わ紝鎸崱鍛ㄦ湡T=T1+T2=0.7(R1+2R2)C锛鎸崱棰戠巼f=1/T銆傛鍚戣剦鍐插搴1涓庢尟鑽″懆鏈烼涔嬫瘮绉扮煩褰㈡尝鐨勫崰绌烘瘮...
绛旓細鍏呯數杈撳嚭楂樼數骞虫椂闂翠负t1=0.69(R1+R2)C锛屾斁鐢典綆鐢靛钩鏃堕棿涓簍2=0.69R2C锛孎=1/(t1+t2)銆
绛旓細555瀹氭椂鍣ㄧ敤浜庡崰绌烘瘮50%鐨澶氳皭鎸崱鍣紝鍏蜂綋鐢佃矾鍥鍙婂弬鏁璁＄畻鍏紡濡備笅锛
绛旓細Ra锛7鑴氬埌鐢垫簮鐨勭數闃 Rb锛6鑴氬埌7鑴氱殑鐢甸樆 C锛2銆6鑴氬埌鍦扮殑鐢靛 鎸崱鍛ㄦ湡锛歍=0.695路锛圧a+Rb锛壜稢 鍗犵┖姣旓細D=锛圧a+Rb锛壝凤紙Ra+2Rb锛鎸崱棰戠巼鍙湪0.001Hz-500KHz闂翠换鎰忚皟鑺傘傚崰绌烘瘮鍙湪0.01%-99.00%鑼冨洿鍐呰皟鑺傘
