java字符串的处理
\u5173\u4e8eJAVA\u5904\u7406\u5b57\u7b26\u4e32\u95f2\u6765\u65e0\u4e8b\uff0c\u5199\u4e00\u4e2a\u73a9\u73a9\u3002\u5982\u4e0b\uff1a
package com.test;
public class Str {
public static void main(String[] args) {
String str="sdasdrasdtaadd";
String minChars=""; // \u6700\u5c11\u51fa\u73b0\u6b21\u6570\u7684\u5b57\u7b26\u96c6
int len = 0;
String chars = getChars(str); // \u6c42\u51fa\u5b57\u7b26\u4e32\u6240\u5305\u542b\u7684\u6240\u6709\u5b57\u7b26
for (int i = 0; i < chars.length(); i ++){ // \u6839\u636e\u5b57\u7b26\u96c6\u6c42\u51fa\u6700\u5c11\u51fa\u73b0\u6b21\u6570\u7684\u5b57\u7b26
String[] temp = str.split(chars.charAt(i)+"");
int tempLen = temp.length;
if (i == 0){
minChars = chars.charAt(i)+"";
}
if (len == tempLen){
minChars += chars.charAt(i);
}else if (len > tempLen ){
minChars = chars.charAt(i)+"";
}else{
//result = ""; \u4ec0\u4e48\u90fd\u4e0d\u505a
}
len = tempLen;
}
for (int j = 0; j < minChars.length(); j ++)
str = str.replaceAll(minChars.charAt(j)+"", "");
System.out.println(str);
}
public static String getChars(String str){
String returnChars = "";
while(!str.equals("")){
char temp = str.charAt(0);
returnChars += temp;
str = str.replaceAll(temp+"", "");
}
return returnChars;
}
}
答：可以用简单的replaceAll进行替换。String result = "2009-08-20".replaceAll("-","");
或者使用SimpleDateFormat("yyyy-MM-dd")这种来进行处理。
如何将一个全数字字符串"123456"转换为int型123456
Integer.parseInt("123456")即可！
把字符串"2009-08-20" 转换为字符串"20090820" 怎么弄:
"2009-08-20".replaceAll("-","");
如何将一个全数字字符串"123456"转换为int型123456:
int i = Integer.parseInt("123456");
这些在jdk帮助文档 中 都可以找到的。
"2009-08-20".replaceAll("-","");
int i = Integer.parseInt("123456");
楼主基础不是很牢固哦。还有就是遇到问题多查看jdk帮助文档。
String symbol="2009-08-20";
System.out.println(symbol.replaceAll("-", ""));
"2009-08-20".replaceAll("-","");
int i = Integer.parseInt("123456");
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