求数列:"1,12,123,1234,12345,123456,….1234567……n,…."的 C# 求一组数1,12,123,1234,12345,123...

\u6c42\u6570\u5217\uff1a"1,12,123,1234,12345,123456\uff0c\u2026.1234567\u2026\u2026n\uff0c\u2026."\u7684\u901a\u9879\u516c\u5f0f~~\u3010\u4f1a\u7684\u7ae5\u978b\u8bd5\u8bd5\u770b\u5427~~\u3011

\u7531\u6570\u5217\u5f97\u9012\u63a8\u516c\u5f0f\uff1aa(n+1)=10an+n+1
\u53ef\u5316\u4e3a a(n+1)+n/9+19/81=10(an+(n-1)/9+19/81)
\u56e0\u6b64\uff5ban+(n-1)/9+19/81}\u4e3a\u9996\u9879100/81, \u516c\u6bd4\u4e3a10\u7684\u7b49\u6bd4\u6570\u5217
\u56e0\u6b64\u6709\uff1aan+(n-1)/9+19/81=100/81*10^(n-1)
\u56e0\u6b64\u6709\uff1aan=10^(n+1)/81-n/9-10/8

string func(int n) //n<=9{ if(n<=1) return "1"; return func(n-1)+n.ToString();}

这个是根据等差数列的进行描述的,个人阶段是这样认为的,大家可以多了解一下

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