三个阻值相同的电阻串联的总电阻为9Ω，若将它们并联起来，则总电阻为
\u4e09\u4e2a\u963b\u503c\u76f8\u540c\u7684\u7535\u963b\u4e32\u8054\u7684\u603b\u7535\u963b\u4e3a9\u03a9\uff0c\u82e5\u5c06\u5b83\u4eec\u5e76\u8054\u8d77\u6765\uff0c\u5219\u603b\u7535\u963b\u4e3a______\u8bbe\u4e09\u4e2a\u963b\u503c\u76f8\u7b49\u7684\u7535\u963b\u963b\u503c\u4e3aR\uff0c\u4e32\u8054\u540e\u7684\u603b\u7535\u963bR\u2032=3R=9\u03a9\uff0c\u6240\u4ee5R=3\u03a9\uff1b\u5e76\u8054\u540e\u7684\u603b\u7535\u963bR\u2033=1nR=13\u00d73\u03a9=1\u03a9\uff0e\u6545\u7b54\u6848\u4e3a\uff1a1\u03a9\uff0e
\u8bbe\u4e09\u4e2a\u963b\u503c\u76f8\u7b49\u7684\u7535\u963b\u963b\u503c\u4e3aR\uff0c\u4e32\u8054\u540e\u7684\u603b\u7535\u963bR\u2032=3R=9\u03a9\uff0c\u6240\u4ee5R=3\u03a9\uff1b\u5e76\u8054\u540e\u7684\u603b\u7535\u963bR\u2033=1nR=13\u00d73\u03a9=1\u03a9\uff0e\u6545\u9009A\uff0e
| 设三个阻值相等的电阻阻值为R， 串联后的总电阻R′=3R=9Ω， 所以R=3Ω； 并联后的总电阻R″=
故答案为：1Ω． |
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绛旓細r鎬 = 0.5r + r = 1.5r
绛旓細涓茶仈鍚鐨勬荤數闃涓18=R+R+R锛屽嵆姣忎釜鐢甸樆涓6璁惧苟鑱斿悗鐨勭數闃r鍒1/r=1/R+1/R+1/R,鎵浠=2
绛旓細鍋囪姣忎釜瀵间綋鐨勯樆鍊间负R锛庝笁涓鐢甸樆涓茶仈鍚庯紝R 鎬 =R+R+R=3R锛涗笁涓數闃诲苟鑱斿悗锛 1 R 鎬 = 1 R + 1 R + 1 R 锛孯 鎬 = R 3 锛庢墍浠涓変釜闃诲肩浉鍚岀殑瀵间綋骞惰仈鍚鐨勬荤數闃涓庝覆鑱斿悗鐨勬荤數闃讳箣姣斾负3R锛 R 3 =9锛1绛旓細9锛1 ...
绛旓細1:18 R1=3R R2=R/3 R1=9R2
绛旓細涓茶仈 鐢甸樆R=R1+R2+R3=20+40+60=120惟 鐢垫祦I=I1=I2=I3锛屾墍浠ョ數娴佹瘮1锛1锛1 鐢靛帇U=U1+U2+U3锛屾墍浠ョ數鍘嬫瘮1锛2锛3 骞惰仈 鐢甸樆1/R=1/R1+1/R2+1/R3 R=20/11惟 鐢垫祦I=I1+I2+I3锛屾墍浠ョ數娴佹瘮3锛2锛1 鐢靛帇U=U1=U2=U3锛屾墍浠ョ數鍘嬫瘮1锛1锛1 ...
绛旓細涓茶仈鏄3鍊 骞惰仈鏄1/3 鍥犱负锛歊1=R2=R3 涓诧細R鎬=R1+R2+R3=3R1 骞讹細1/R鎬=1/rR1+1/R2+1/R3=3/R1 鎵浠ワ細R鎬=R1/3
绛旓細璁涓変釜闃诲肩浉绛夌殑鐢甸樆闃诲涓篟锛屽垯1R骞=1R+1R+1R=3R锛屸埖骞惰仈鍚鐨勬荤數闃R骞=10惟锛屸埓R=30惟锛庡垯鑻ユ妸瀹冧滑涓茶仈璧锋潵锛屽叾绛夋晥鐢甸樆R涓=R+R+R=30惟+30惟+30惟=90惟锛庢晠绛旀涓猴細90锛
绛旓細璁炬瘡涓數闃讳负R锛屽垯骞惰仈鏃鎬荤數闃R1=R/3=10锛屾墍浠=30娆с涓茶仈鏃舵荤數闃籖2=3R=90娆с
绛旓細濡傛灉鐢甸樆闃诲肩浉鍚 涓茶仈鐢佃矾 R=nR1 骞惰仈鐢佃矾 R=R1/n PS锛歊鏄鎬荤數闃锛孯1绛夋槸鍒嗙數闃汇傚嚑涓數璺厓浠舵部鐫鍗曚竴璺緞浜掔浉杩炴帴锛屾瘡涓妭鐐规渶澶氬彧杩炴帴涓や釜鍏冧欢锛屾绉嶈繛鎺ユ柟寮忕О涓轰覆鑱斻備互涓茶仈鏂瑰紡杩炴帴鐨勭數璺О涓轰覆鑱旂數璺備覆鑱旂數璺腑娴佽繃姣忎釜鐢甸樆鐨勭數娴佺浉绛夈傚洜涓虹洿娴佺數璺腑鍚屼竴鏀矾鐨勫悇涓埅闈㈡湁鐩稿悓鐨鐢垫祦寮哄害銆
