y^2=x的切线方程公式是什么
\u00b7y^2=x\u7684\u5207\u7ebf\u65b9\u7a0b\u516c\u5f0f\u662f\u4ec0\u4e48kx+b
k=(1/2)x^(1/2)
\u65b9\u7a0b\u4e24\u8fb9\u5bf9x\u6c42\u5bfc\uff1a2yy'=2p, \u5f97y'=p/y
\u8bbe\u66f2\u7ebf\u4e0a\u4e00\u70b9\u4e3a(xo, yo), \u5219\u6709yo²=2pxo
\u5728\u6b64\u70b9\u7684\u5207\u7ebf\u4e3ay=p/yo(x-xo)+yo
\u5373yyo=px-pxo+yo²
\u5373yyo=px-pxo+2pxo
\u5f97\uff1ayyo=p(x+x0)
y=ax+b
y^2=x
ay^2-y+b=0有唯一解时，y=ax+b即为切线。
△=b^2-4ac=1-4ab=0
b=1/4a
所以切线通式为
y=ax+1/4a
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