JqueryAjax如何传递JSON数据到controller,其中包括List数据? SpringMVC中使用List数据绑定,ajax怎么传输包...

\u4eceAPI\u63a5\u53e3\u83b7\u53d6\u7684json\u6570\u636e\u600e\u4e48\u5b58\u5230\u5bf9\u8c61\u7684List\u96c6\u5408\u4e2d

1. \u7b80\u5355\u7684\u624b\u52a8\u653e\u7f6e \u952e\u503c\u5bf9 \u5230JSONObject\uff0c\u7136\u540e\u5728put\u5230JSONArray\u5bf9\u8c61\u91cc
List al = articleMng.find(f);
System.out.println(al.size());
HttpServletResponse hsr = ServletActionContext.getResponse();
if(null == al){
return ;
}
for(Article a : al){
System.out.println(a.getId()+a.getDescription()+a.getTitle());
}
JSONArray json = new JSONArray();
for(Article a : al){
JSONObject jo = new JSONObject();
jo.put("id", a.getId());
jo.put("title", a.getTitle());
jo.put("desc", a.getDescription());
json.put(jo);
}
try {
System.out.println(json.toString());
hsr.setCharacterEncoding("UTF-8");
hsr.getWriter().write(json.toString());
} catch (IOException e) {
e.printStackTrace();
}
\u590d\u5236\u4ee3\u7801
\u4e0a\u8ff0\u4ee3\u7801JSONArray\u662f\u5f15\u5165\u7684org.json.JSONArray\u5305

\u800c\u7528net.sf.json\u5305\u4e0bJSONArray\u7684\u9759\u6001\u65b9\u6cd5\uff1afromObject(list) \u8fd9\u662f\u7f51\u4e0a\u5927\u591a\u662f\u90fd\u662f\u76f4\u63a5\u7528\u6b64\u65b9\u6cd5\u5feb\u6377\u8f6c\u6362JSON\uff0c\u4f46\u662f\u5bf9\u4e8eHibernate\u7ea7\u8054\u64cd\u4f5c\u5173\u8054\u7684\u5bf9\u8c61\uff0c\u8fd9\u4e2a\u65b9\u6cd5\u5c31\u4f1a\u62a5\u9519\uff0c\u5982\u679c\u5c06\u6620\u5c04\u6587\u4ef6\u4e2d\u7684\u7ea7\u8054\u914d\u7f6e\u53bb\u6389\u5c31\u884c\u4e86\u3002

\u53e6\u5916\u5bf9\u4e8elist\u7684\u8981\u6c42\u5c31\u662f\u5176\u4e2d\u7684\u5143\u7d20\u662f\u5b57\u7b26\u4e32\u6216\u5bf9\u8c61\uff0c\u5426\u5219JSON\u4e0d\u77e5\u9053\u4f60\u60f3\u8981\u7684\u662f\u4ec0\u4e48\u6570\u636e\u3002

<many-to-one name="cmsent" column="comment_tid" class="com.fcms.cms.entity.CmsComment"
not-null="false" cascade="delete">
\u4f46\u662f\u7ea7\u8054\u64cd\u4f5c\u6bd5\u7adf\u8fd8\u662f\u5f97\u5b58\u5728\uff0c\u5426\u5219\u4ee5\u540e\u6570\u636e\u5197\u4f59\u3001\u591a\u4f59\u3002

\u89e3\u51b3\u65b9\u6cd5\u5c31\u662f\uff1aJSONArray subMsgs = JSONArray.fromObject(object, config);

JsonConfig config = new JsonConfig();
config.setJsonPropertyFilter(new PropertyFilter() {
public boolean apply(Object arg0, String arg1, Object arg2) {
if (arg1.equals("article") ||arg1.equals("fans")) {
return true;
} else {
return false;
}
}
});

\u7528spring mvc3\u7684\u6ce8\u89e3@ResponseBody
@ResponseBody
public List xxxx() {
...
List res = xxx
return res;
}


\u52a0\u4e24\u4e2a\u4f9d\u8d56

org.codehaus.jackson
jackson-mapper-asl
1.8.4



org.codehaus.jackson
jackson-core-asl
1.8.4



\u5982\u679c\u6ca1\u914d



\u8fd8\u9700\u914d\u7f6e









\u9644\u4e0a\u51fa\u5904\u94fe\u63a5\uff1ahttp://www.thinksaas.cn/ask/question/19691/

无所谓有没有所谓的list数据,在序列化后传递到后端的结构都是根据的请求设置来定的,而json是有两种表示结构,对象和数组,而他们是可以任意混合的。list序列化后变成了json中的数组。后台取值可以在参数上获取,也可以在content上获取。
所以Ajax如何传递JSON数据到controller,其中包括List数据,其实只要序列化这个对象给ajax即可。

在jquery中用ajax传递接送数据的方法是:
以下代码示例:
$.ajax({
url: url,
type: "POST",
data: JSON.stringify(data), //注意这里一定要验证json格式
contentType: "application/json",
complete: callback
});

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